CHEMISTRY HIGH SCHOOL

Tendons attach muscles to bones.
True
False

Answers

Answer 1
Answer: Absolutely true

Just in case you do get it, a ligament will attach a bone to a bone, just as a fun fact
Answer 2
Answer:

Answer:

This is true.

Explanation:

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An unknown compound contains only carbon, hydrogen, and oxygen (cxhyoz). combustion of 3.50 g of this compound produced 5.13 g of carbon dioxide and 2.10 g of water.how many moles of hydrogen, h, were in the original sample?

The amount of silica in the magma and temperature are factors that determine the viscosity of magma.

Answers

The viscosity of magma increases as the silica content increases from basalt to rhyolite.

Identify the elements and the number of atoms of each element in BO2

Answers

The B stands for Boron which is 5 on the periodic table.
The O stands for Oxygen which is 8 on the periodic table.

There is 1 Boron,        It's only 1 because there is only on B which doesn't have coefficent 
There is 2 Oxygen,     The 2 is from the 2 next to the O

A fundamental object that is difficult to divide into smaller bits is known as an element. An element is a substance that cannot be broken down by non-nuclear reactions in chemistry and physics. The elements are boron and oxygen, and their numbers are 1 and 2.

A pure material known as an element is made up of just one type of atom and cannot be divided into two or more different substances. A compound is a pure substance that is created when two or more substances are mixed in a specific mass ratio.

Chemistry's fundamental building block is an atom. It is the smallest fraction of matter into which electrically charged particles cannot be released. It is also the smallest piece of substance with chemical element-like characteristics.

To know more about elements, visit;

brainly.com/question/29545466

#SPJ6

Repulsion is a force or interaction among the atoms in a molecule in which the atoms attract one another. a. True
b. False

Answers

Repulsion is a force or interaction among the atoms in a molecule in which the atoms REPEL one another. By the word itself repulsion, meaning to repel, it automatically bans the idea of ATTRACTION. Therefore, the statement above is FALSE. The answer to this question is "B. False". 

Write the ionic equation for the reaction of aqueous propanoic acid with aqueouspotassium hydroxide.

Answers

The ionic equation for the reaction of aqueous propanoic acid (CH3CH2COOH) with aqueous potassium hydroxide (KOH) can be written as follows:

CH3CH2COOH + OH- → CH3CH2COO- + H2O

In this equation, propanoic acid (CH3CH2COOH) reacts with hydroxide ions (OH-) from potassium hydroxide (KOH) to form the propanoate ion (CH3CH2COO-) and water (H2O).

What coefficients must be added to balance the following reaction __Sn+___H3PO4___=H2+___Sn3(PO4)4

Answers

answer 3Sn+ 4H3pO4= 6H2+Sn(PO)4

1 Sn                                  3 Sn
3 H                                    2 H
1 P                                    4 P
4 O                                    16 O
 then you have to make the numbers the same for each side

so you get by putting the 3 infront of Sn 4 infront of the H3PO4  and 6 infront of the H2
3 Sn                                   3 Sn
12 H                                    12 H
4 P                                      4 P
16 O                                     16 O

Pentane, C5H12, will react as shown below:____C5H12(l) + ____O2 --- ______CO2 +_______ H2O

H20(g)

1. Balance the equation above by putting coefficients into each blank space.

1C5H12+ 8O2----- 5CO2+ 6 H2O (this is what I got)

2. How many atoms of oxygen are in 144 grams of pentane?

step 1: 144g of C5H12*(1mole/72.17)= 1.995moles of C5H12
step 2: 1.995moles of C5H12*(8moles of O2/1mole of C5H12)= 15.962 moles of O2
step 3: 15.962 moles of O2*(6.02*10^23 atoms of O2/1mole of O2)= 9.609*10^24 atoms of O2 (I don't know if I did this right)


3. How many atoms of oxygen are in 192 grams of carbon dioxide gas?

step 1: 192 grams of CO2 *(1mole of CO2/44.01grams of CO2)= 4.363 moles of CO2
step two: 4.36moles of CO2* ( 1 mole of O2/1mole of CO2)=
step 3: 4.363* (6.02*10^23) = 2.627*10^24 atoms of O2 (I don't know if this is correct.


4. A) CIRCLE ONE: True or False:

reactant you begin with fewer grams of is your limiting reactant.

B) If 32 g of oxygen gas and 32 g of pentane are combined, how much water will be produced, in moles? (Use your reaction from the top of the first page)


NEED HELP ASAP THANK YOU!!!

Answers

1) That looks right

2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol
    Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of       oxygen is moles of pentane times 8. 2*8=16mol of oxygen
    Step 3: 16= 9.6*10^24

3) The ratio of oxygen to carbon in CO2 is 1:2
    so it's 192/3 = 64
    64*2=128g
Moles = Mass/Mr = 128/32 = 4mol = 2.41*10^24 atoms of oxygen
Basically you needed to work out the mass of oxygen using ratios before using a moles equation instead of just working with moles

4) True

5) 1C5H12+ 8O2----- 5CO2+ 6 H2O
      32g        32g

Moles of oxygen = Mass/Mr = 32/32= 1mol so you'd need 0.125mol of pentane to react fully
Moles of pentane= Mass/Mr = 32/72=0.4mol so you'd need 3.2mol of oxygen to react fully

This makes oxygen the limiting factor, because you need more of it to react fully with the pentane, so we use oxygen 

Stoichiometry means for every 8mol of oxygen there's 5mol of CO2
So, 1/8*5=0.635mol of CO2
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