Which statement correctly describes the gravitational potential energy of the pendulum based on this diagram? A.
It is greatest at 25% of the period length.
B.
It is greatest at the point where the arm meets the pivot point.
C.
It is greatest when the bob is at its maximum amplitude.
D.
It is greatest when the bob is in the rest position.

Answers

Answer 1

Answer: I think it's 'C' but I won't know for sure until you let me see the diagram.

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A ray of light is travelling from north towards south and it has travelled 49 km until it hit a mirror which reflected the light towards east. The ray of light reflected towards east has travelled 47 km until it hit another mirror which reflected it diagonally towards the initial point which is north. How long is the line reflected towards north diagonally? Round the result to two decimals.

Answers

The path is a right triangle. One side of this triangleis 49 km long, the other side is 47 km long.

The hypotenuse is the the diagonal line searched.

So use Pythagora's theorem to find the diagonal line:

Diagonal = √[(47km)^2 + (49km)^2] = 67.90km

A person drops a brick from the top of a building. The height of the building is 400 m and the mass of the brick is 2.00 kg. What will be the speed of the brick right before it touches the ground? Use g=10.0 m/s^2.

Answers

This question involves the conservation of energy. There are two energy in this case, potential energy and kinetic energy. Let's divid the energy into three status.
1. Before dropping, all potential energy
2.dropping, potential energy transformed to kinetic energy
3. before hitting the ground, all Kinetic energy.

Recall the formula for both energy, which are U=mgh, and K=1/2mv^2

Since the energy is conserved in this case ( b/c otherwise it will say in the problem), the amount of energy at the beginning should equal to the energy at the end. Therefore we have, mgh=1/2mv^2

plug the number in and solve for velocity.

2x400x10=1/2 x 2 x v^2
v^2=8000
v= $√(8000)$
v=40 $√(5)$

Jawless fish and ocean reefs were devastated by which extinction? Late Devonian

Ordovician-Silurian

Permian-Triassic

End Triassic

Cretaceous-Tertiary

Answers

Late Devonian (I believe)

The Late Devonian.

If you go back and reach the text, you may find the passage, "Which species did we lose during this extinction (Late Devonian)? About 20% of all animal families and 70-80% of all animal species were lost. Major victims included the following:

....

- Jawless fish"

A crane has an arm length of 20m inclined at 30deg with the vertical. It carries a container of mass of 1 ton suspended from the top end of the arm. Find the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane. Given: 1 ton = 1000 kg; neglect the weight of the arm. Hint: take the force and perpendicular distance from the point where the arm is fixed to the crane. Note: Express your answer in whole number. No unit is required for the final answer. Set your calculator in radians.

Answers

To find the torque produced by the gravitational force on the container, we need to calculate the force and perpendicular distance from the point where the arm is fixed to the crane.

First, let's calculate the force exerted by the gravitational force on the container. The weight of the container can be calculated using its mass and the acceleration due to gravity. Given that the mass of the container is 1000 kg (1 ton) and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the force as follows:

Force = mass * acceleration due to gravity
Force = 1000 kg * 9.8 m/s^2
Force = 9800 N

Next, we need to find the perpendicular distance from the point where the arm is fixed to the crane to the line of action of the gravitational force. This distance can be determined using trigonometry.

The perpendicular distance can be calculated using the formula:

Perpendicular distance = arm length * sin(angle)

Given that the arm length is 20 m and the angle with the vertical is 30 degrees, we can calculate the perpendicular distance as follows:

Perpendicular distance = 20 m * sin(30 degrees)
Perpendicular distance = 20 m * 0.5
Perpendicular distance = 10 m

Now, we can calculate the torque using the formula:

Torque = force * perpendicular distance

Substituting the values we calculated earlier:

Torque = 9800 N * 10 m
Torque = 98000 Nm

Therefore, the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane is 98000 Nm.

Discuss the force that exists between the Earth and the moon by referring to the mass of each.

Answers

The word gravity is used to describe the gravitational pull (force) an object experiences on or near the surface of a planet or moon. The gravitational force is a force that attracts objects with mass towards each other. Any object with mass exerts a gravitational force on any other object with mass.

Hope it answers your question!

Brainliest would be nice but of course you don’t gotta :)

A uniform Capillary tube closed at one end Contain dry air trapped by a thread of mercury 8.5x10 m long when the tube was held horizontally, the length of the air Column 5.0X10^2 Wher it held verti cally with the closed end downward the length was 4.5x10^2m Determine the value of atmospheric pressure take g=10m/s, density of mercury (1.36×10^4kg/m)

Answers

Answer:

To determine the value of atmospheric pressure, we can use the concept of hydrostatic pressure. By comparing the lengths of the air column in the capillary tube when held horizontally and vertically, we can equate the pressure difference to the difference in height of the mercury column. Using the given values and the density of mercury, we can calculate the atmospheric pressure.

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Sa ma ajute cineva va rog mult Ce cantitate de apă poate fi încălzită de la temperatura t 1 = 10 0 C la temperatura finală T 2 = 293, 15 K, dacă i se furnizează căldura de 41850 J ? Se dă căldura specifică a apei : c apă = 4185