Convert 53 grams to kilograms.

530 kg
53,000 kg
0.053 kg
5.3 kg

Answers

Answer 1
Answer: 0.053 kg would be your answer cause 1 gram is 0.001
Answer 2
Answer: There are 1000 grams in a kilo gram so you do 53/1000. That is 0.053 so the answer is c.

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PLEASE HELP! How do I solve this problem?

Answers


The toughest part of this problem could be deciding what names to give the quantities of one-Euro and two-Euro coins.

-- I called the number of one-Euro coins ' N '.
Each of them is worth 1 Euro, so all ' N ' of them are worth ' N ' Euros.

-- I called the number of two-Euro coins ' T '.
Each of them is worth 2 Euros, so all ' T ' of them are worth ' 2T ' Euros.

-- The total number of coins in Penny's pocket is (N + T), and it says there are 11.

-- Their total value is (N + 2T), and it says the total value is 18.

So now you have two equations, with two unknowns.

               N + 2T  =  18
               N +  T  =  11

Subtract the bottom equation from the top one, and you get:

          (N - N) + (2T - T)  =  (18 - 11)

                             T        =      7         (there are 7 two-Euro coins in her pocket)

That right there is the answer to the question, so you don't need to go
any farther.  But if you wanted to, you could also figure out how many
one-Euro coins there are in her pocket.


Choose the correct product of (2x + 10)2.4x2 − 100
4x2 + 40x + 100
4x2 + 100
4x2 − 40x + 100

Answers

Answer: 4x² + 40x +100

(2x+10)(2x+10)
4x2 + 20x + 20x +100
4x2 + 40x + 100

Answer:

(2x+10)^2=4x^2+40x+100

Step-by-step explanation:

Given the expression

(2x+10)^2

we have to simplify the above expression.

By identity

(a+b)^2=a^2+2ab+b^2

Put a=2x and b=10

(2x+10)^2=(2x)^2+2(2x)(10)+10^2

(2x+10)^2=4x^2+40x+100

Option B is correct.

will bought 3 college textbooks. one cost $32, one cost $45, and one cost $39. what is the average price of his books? choose the statement that correctly calculates the average. a. ($32 $45 $39) ÷ 3 b. $32 ÷ 3 $45 ÷ 3 $39 c. $32 $45 $39 ÷ 3 d. 3 × $32 $45 $39

Answers

The correct answer is a. ($32 + $45 + $39) ÷ 3

What is -0.66666666666 as a fraction

Answers

-2/3, if -1/3 is 0.333333333333333333333, double that, -0.666666666666, would have to be -2/3

Answer:

-2/3

Uhh I need 20 characters so here

Which polynomial is prime? A. 7x^2 – 35x + 2x – 10
B. 9x^3 + 11x^2 + 3x – 33
C. 10x^3 – 15x^2 + 8x – 12
D. 12x^4 + 42x^2 + 4x^2 + 14

Answers

Answer:

C.9x^(3)+11 x^(2) +3x-33

Step-by-step explanation:

A polynomial is prime if it can't be factored in polynomials of lower degree. Let's factorize:

A. 7x^(2) -35x+2x-10

In this case we have 4 terms, so we can use Grouping:

Part a:

7x^(2) -35x

We're going to use Greatest common factor:

=7x^(2) -7.5x\n=7x(x-5)

Part b:

2x-10

In this part we also use greatest common factor:

2x-10=2x-2.5\n=2(x-5)

Then,

7x^(2) -35x+2x-10=\n 7x(x-5)+2(x-5)=\n =(7x+2)(x-5)

This polynomial is not prime.

B.9x^3 + 11x^2 + 3x-33

This polynomial cannot be factorized then it's prime.

C.10x^3-15x^2 + 8x-12

In this polynomial we can use grouping too:

Part a:

10x^3 -15x^2=2.5x^3-3.5x^2\n=5x^2(2x-3)

Part b:

8x-12=4.2x-4.3\n=4(2x-3)

Then,

10x^3-15x^2 + 8x-12=\n=5x^2(2x-3)+4(2x-3)\n=(5x^2+4)(2x-3)

This polynomial isn't prime.

D. 12x^4 + 42x^2 + 4x^2 + 14

First we're going to use Greatest common factor:

12x^4 + 42x^2 + 4x^2 + 14=\n2.6x^4+2.21x^2+2.2x^2+2.7=2(6x^4+21x^2+2x^2+7)

Now we're going to apply grouping on the terms inside of the parenthesis:

6x^4+21x^2+2x^2+7

Part a:

6x^4+2x^2=2.3x^4+2x^2=2x^2(3x^2+1)

Part b:

21x^2+7=7.3x^2+7=7(3x^2+1)

Then,

6x^4+21x^2+2x^2+7=2x^2(3x^2+1)+7(3x^2+1)\n=(2x^2+7)(3x^2+1)

Remember that at the beginning we use Greatest common factor:

12x^4 + 42x^2 + 4x^2 + 14=\n=2.(6x^4+21x^2+2x^2+7)\n=2(2x^2+7)(3x^2+1)

This polynomial isn't prime.

Answer:

B not C  9x^3 + 11x^2 + 3x - 33

Step-by-step explanation:

Help help help help help

Answers

area=108 in. squared

12/2 gives you the radius (6)

6 squared is 36

36 times 3 is 108