A beaker contains 100 mL of NaOH solution at pH = 13. A technician carefully pours into the beaker 10 mL of HCl at pH = 1. Which of the following statements correctly describes the results of this mixing?a. The concentration of Na⁺ ion rises.
b. The concentration of Cl⁻ ion will be 0.1M.
c. The concentration of undissociated H₂O molecules remains unchanged.
d. The pH of the beaker's contents will be neutral.
e. The pH of the beaker's contents falls.

Answers

Answer 1
Answer:

Answer: Option (e) is the correct answer.

Explanation:

Since, the beaker contains NaOH solution whose pH is 13. As pH of NaOH is greater than 7 so, it means that this solution is basic in nature.

Whereas pH of HCl solution is equal to 1. As its pH is less that 7 so, it is acidic in nature.

Hence, when we add 10 ml of HCl into 100 mL of NaOH then there will be a slight decrease in pH of the solution because an acid is being added into the NaOH solution.

Thus, we can conclude that the statement pH of the beaker's contents falls, correctly describes the results of this mixing.


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One faraday of electricity will liberate one gram-atom of the metal form a solution .

Which step would help a student find the molecular formula of a compound from the empirical formula?Multiply the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.

Subtract the ratio of the actual mass of the compound to the empirical formula mass from the subscripts of the empirical formula.

Divide the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.

Add the ratio of the actual mass of the compound to the empirical formula mass to the subscripts of the empirical formula.

Answers

Answer : Option A) Multiply the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.

Explanation : To find molecular formula for a compound one needs to follow the below steps using the emphirical formula of that compound.

Step 1) Calculate the empirical formula mass of that compound

Step 2) Take the ratio of gram molecular mass by the empirical formula mass that was obtained in step 1.

Step 3) Multiply each of the subscripts within the empirical formula by the number that is calculated in step 2.

By following these easy steps one can find the molecular formula.

The step that would help a student finds the molecular formula of a compound from the empirical formula is by ‘Multiply the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.’

If a straight-chain hydrocarbon is a gas at room temperature, how many carbon atoms will it have?A. 6 carbon atoms

B. 12 carbon atoms

C. 24 carbon atoms

D. 3 carbon atoms

Answers

The fewer the carbon atoms, the closer it is  to being a gas. The only one you have to check out is A which is hexane. You know that gasoline at the pumps has 8 carbons and its a liquid. So B and C are both not gases  because they are above 8.

C6 (hexane) is a liquid at room temperature not a gas.

The answer is D. If there is a gas present, it must be C3

What are the products of the complete combustion of a hydrocarbon in excess oxygen

Answers

The products for the complete combustion of a hydrocarbon in excess air is carbon dioxide and water. Any hydrocarbon when reacted with oxygen will always yield the said products. Incomplete combustion, on the other hand, yields carbon monoxide and water.

A solution of KCIO3 is prepared using 75 grams of the solute in enough water to make 0.250 liters of solution. The gram-formula mass of KCIO3 is 122 grams per mole.-- Determine the percent by mass of solute in the solution.

Answers

The mass percent of the solute present is 99.7%.

What is mass percent?

The term mass percent refers to the ratio of the mass of solute to the mass of the solution multiplied by 100.

We have the following information;

volume of the water = 0.250 liters

Mass of the water = 0.250 g

Mass of the solute = 75 grams

Mas of solute and  solvent = 0.250 g + 75 grams = 75.250 g

Mass percent of the solute = 75 grams /75.250 g * 100 = 99.7%

Learn more about mass percent: brainly.com/question/1190311

Using the mass/volume percentage method for percentages of the solution, you simply divide the grams of solute by the volume of the solution and multiply by 100 to get your percentage.
(75.0g/250mL)•100 = 30.0% solute

Who Organized elements into four groups based on properties:

Answers

the answer is lavoiser

Final answer:

Antoine-Laurent de Lavoisier, a French chemist, organized elements into four groups based on their properties: gases, nonmetals, metals, and earths. This was a monumental contribution to the field of Chemistry.

Explanation:

The person you're referring to who organized elements into four groups based on their properties is the French chemist Antoine-Laurent de Lavoisier. Lavoisier is commonly known as the 'Father of Modern Chemistry' and his work contributed significantly to the development of this field. In the late 18th century, he sorted 33 elements into four categories: gases, nonmetals, metals, and earths, by recognizing their similar properties. This was a significant step at the time, further paving the way for the modern periodic table.

Learn more about Organization of Elements here:

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Which pair of compounds are isomers?(1) NO2 and N2O4
(2) P2O5 and P4O10
(3) HCOOH and CH3COOH
(4) CH3OCH3 and C2H5OH

Answers

Answer: CH_3OCH_3 and C_2H_5OH

Explanation: The compounds having similar molecular formula but different arrangement of atoms or groups in space are called isomers and the phenomenon is called as isomerism.

CH_3OCH_3 and C_2H_5OH are functional isomers which have same molecular formula but different functional groups attached.

(1) NO_2 and N_2O_4 are different compounds.

(2)  P_2O_5 and P_4O_(10) are different compounds.

(3) HCOOH and CH_3COOH are different compounds.

CH3OCH3 and C2H5OH are isomers. They have same molecular formula. But with another formation.