PHYSICS COLLEGE

Select True or False for the following statements about Heisenberg's Uncertainty Principle. True False It is not possible to measure simultaneously the x and y positions of a particle exactly.True False It is not possible to measure simultaneously the x and y momentum components of a particle exactly.
True False It is not possible to measure simultaneously the z position and the z momentum component of a particle exactly.

Answers

Answer 1

Answer:

Answer:

Statement 1) False

Statement 2) False

Statement 3) True

Explanation:

The uncertainty principle states that " in a physical system certain quantities cannot be measured with random precision no matter whatever the least count of the instrument is" or we can say while measuring simultaneously the position and momentum of a particle the error involved is

$P\cdot\delta x\geq (h)/(4\pi )$

Thus if we measure x component of momentum of a particle with 100% precision we cannot measure it's position 100% accurately as the error will be always there.

Statement 1 is false since measurement of x and y positions has no relation to uncertainty.

Statement 2 is false as both the momentum components can be measured with 100% precision.

Statement 3 is true as as demanded by uncertainty principle since they are along same co-ordinates.

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A toy car that is 0.12 m long is used to model the actions of an actual car thatis 6 m long. Which ratio shows the relationship between the sizes of themodel and the actual car?A: 5:1B: 1:50C: 50:1D: 1:5
A ball of mass 0.7 kg flies through the air at low speed, so that air resistance is negligible. (a) What is the net force acting on the ball while it is in motionWhich components of the ball's momentum will be changed by this force? What happens to the x component of the ball's momentum during its flight? What happens to the y component of the ball's momentum during its flight? It decreases. What happens to the z component of the ball's momentum during its flight?

The acceleration of a particle moving along a straight line is given by a = −kt2 m/s2 where k is a constant and time t is in seconds. The initial velocity of the particle at t = 0 is v0 = 12 m/s and the particle reverses it direction of motion at t = 6 s. Determine the constant k and the displacement of the particle over the same 6-second interval of motion. Ans: k = 1/6 m/s4, Δs = 54 m

Answers

Answer:

$X - Xo = 54m$

k = 1/18

Explanation:

Data:

a = -k $t^(2)$ $(m)/(s^(2) )$

to = 0s Vo = 12m/s

t = 6s the particle chage it's moviment, so v = 0 m/s

We know that acceleration is the derivative of velocity related to time:

$a = (dV)/(dT)$

rearranging...

$a*dT = dV$

Then, we must integrate both sides:

$\int\limits^f_i {dV} \, dV =-k \int\limits^f_i {t^(2) } \, dT$

$V - Vo = -k(t^(3) )/(3)$

V = 0 because the exercise says that the car change it's direction:

$0 - 12 = -k(6^(3) )/(3)$

k = 1/6

In order to find X - Xo we must integer v*dT = dX

$V - Vo = -k(t^(3) )/(3)$

so...

$(Vo -k(t^(3) )/(3))dT = dX$

$\int\limits^f_i {dX} \, dX = \int\limits^f_i {Vo -k(t^(3) )/(3) } \, dT$

integrating...

$X - Xo = Vot -k(t^(4) )/(12)$

$X - Xo = 12*6 -(1)/(6)* (6^(4) )/(12)$

X - Xo = 54m

A typical laboratory centrifuge rotates at 3700 rpm . Test tubes have to be placed into a centrifuge very carefully because of the very large accelerations. Part A What is the acceleration at the end of a test tube that is 10 cm from the axis of rotation

Answers

Answer:

Explanation:

acceleration of test tube

= ω² R

= (2πn)² R

= 4π²n²R

n = no of rotation per second

= 3700 / 60

= 61.67

R = .10 m

acceleration

= 4π²n²R

= 4 x 3.14² x 61.67² x .10

= 14999 N Approx

What does a planet need in order to retain an atmosphere? How does an atmosphere affect the surface of a planet and the ability of life to exist?

Answers

Answer:

Explained

Explanation:

In order to retain atmosphere a planet needs to have gravity. A gravity sufficient enough to create a dense atmosphere around it, so that it can retain heat coming from sun. Mars has shallow atmosphere as its gravity is only 40% of the Earth's gravity. Venus is somewhat similar to Earth but due to green house effect its temperature is very high. Atmosphere has a huge impact on the planets ability to sustain life. Presence of certain kind gases make the atmosphere poisnous for life. The atmosphere should be such that it allows water to remain in liquid form and maintain an optimum temperature suitable for life.

A container has a large cylindrical lower part with a long thin cylindrical neck open at the top. The lower part of the container holds 22.8 m^3 of water and the surface area of the bottom of the container is 9.10 m^2. The height of the lower part of the container is 2.50 m, and the neck contains a column of water 8.50 m high. The total volume of the column of water in the neck is 0.200 m^3.(a) What is the magnitude of the force exerted by the water on the bottom of the container? (b) Explain why it is not equal to the weight of the water.

Answers

Answer:

(a) 1045.5 KN

(b) 225.63 KN

Explanation:

Since Pressure, $P=\frac {F}{A}$ where F is force exerted and A is area of the bottom of container

Making F the subject then

F=PA

Height of container=8.5m+2.5m=11.0 m

Density of water $\rho_(water)=1000 Kg/m^(3)$

Surface area of the bottom of the container is $9.10 m^(2)$

Pressure at the bottom of container

$P=P_(atm)+h\rho_(water) g$ where $P_(atm)$ is atmospheric pressure taken as $101.3*10^(3) Kg/m.s^(2)$ , h is height which is 11 m, $\rho_(water)$ is density of water and g is acceleration due to gravity which is taken as $9.81 m/s^(2)$

$P=101.3*10^(3) Kg/m.s^(2) +11m*1000 Kg/m^(3) *9.81 m/s^(2)=209.1*10^(3) Kg/m.s^(2)$

Force exerted is then found by

$F=PA=209.1*10^(3) Kg/m.s^(2)*5 m^(2)=104.55*10^(4) N$

Therefore, force at the bottom is 1045.5 KN

(b)

Volume of container at lower part is given as 22.8 cubic meters hence mass of water =volume*density of water

Mass=22.8*1000=22800 Kg

Volume of water confined in the column is 0.2 cubic meters hence the mass of water confined in the column is 0.2*1000=200 Kg

Total mass=200+22800=23000 Kg

Weight of water, W=mg=23000*9.81=225630 N=225.63 KN

Therefore, the weight of water is less than force applied at the bottom of container since pressure exerted by atmosphere on the surface of water is considered during calculation of force exerted at the bottom of the container

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. Calculate the magnitude and direction of the net horizontal force on the rope.

Answers

In a game of tug of war the magnitude and direction of the net horizontal force on the rope is 74 N.

What is force?

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. The magnitude and direction of the net horizontal force on the rope is,

F = 182 - 108

F = 74 N

The magnitude and direction of the net horizontal force on the rope is 74 N.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ2

Answer:

74 N to the right

Explanation:

the forces are going in opposite horizontal directions, meaning that they are directly opposing each other. this means that you can subtract the force applied in the direction that is greater from the direction that is less to get the net force for the greater direction

this means 182 N - 108 N = 74 N to the right

A person is making homemade ice cream. She exerts a force of magnitude 26 N on the free end of the crank handle on the ice-cream maker, and this end moves on a circular path of radius 0.26 m. The force is always applied parallel to the motion of the handle. If the handle is turned once every 2.0 s, what is the average power being expended?