A ball of mass 0.7 kg flies through the air at low speed, so that air resistance is negligible. (a) What is the net force acting on the ball while it is in motionWhich components of the ball's momentum will be changed by this force? What happens to the x component of the ball's momentum during its flight? What happens to the y component of the ball's momentum during its flight? It decreases. What happens to the z component of the ball's momentum during its flight?

Answers

Answer 1
Answer:

A) Net Force is -6.86N

B) The y component of momentum.

C) The x component of momentum should remain the same.

D)The y component of momentum decreases.

E)The z component of momentum should remain constant.

The following information should be considered:

(A)

The net force should be

= -9.8 (0.7)

= -6.86N

(B)

Due to the net force is on the y-axis, so only the vertical component of the momentum should be changed because to the force.

(C)

Because there is no resistance of air, the ball should be in projectilemotion problems, this represents hat the x component of the velocity remains constant, also does the mass.

D)

The y component of momentum reduced, this is due to gravity reduced the y component of the velocity.

E)Because there is no z component of the force there is no change in the z component of the momentum.

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Answer 2
Answer:

Final answer:

With negligible air resistance and low speed, the only significant net force on a 0.7 kg ball is gravity, affecting the ball's y component of momentum. The x component remains constant, and z component changes are not discussed without additional forces.

Explanation:

When a ball of mass 0.7 kg flies through the air at low speed with air resistance negligible, the net force acting on the ball while it is in motion is primarily due to gravity, which will be impacting the y component of the ball's momentum. The x component of the ball's momentum remains unchanged because no horizontal force is applied, while the y component changes due to gravity, and the z component would only change if there were forces acting in a direction out of the horizontal plane, which are not mentioned in the scenario. As for the Earth-ball system, momentum is conserved in the vertical direction because the system experiences no net external vertical force.


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What type of fossils were found near Macon Georgia?

Answers

Answer:

I believe whale fossils were found.

Whale fossils were found at macon georgia

Q18: A cube of aluminum has an edge length of 20 cm. Aluminum has adensity of 2.7 g/cm and a specific heat of 0.217 cal/ g.°С. When
the internal energy of the cube increases by 47000 cal its temperature
increases by:
A
B
C
D
E
5 °C
10 °C
20 °C
100 °C
200 °C

Answers

The change in temperature of this cube of aluminum is equal to: B. 10°C

Given the following data:

  • Edge length, L = 20 cm.
  • Density of Aluminum = 2.7 g/cm
  • Specific heat capacity (C) of aluminum = 0.217 Cal/g°С
  • Internal energy = 47000 calories.

To find the change in temperature of this cube of aluminum:

First of all, we would determine the volume of this cube of aluminum.

Volume \;of \;a \;cube = L^3\n\nVolume \;of \;a \;cube = 20^3\n\nVolume \;of \;a \;cube = 8000\; cm^3

Next, we calculate the mass of this cube of aluminum:

Mass = Density * Volume\n\nMass = 2.7 * 8000

Mass = 21,600 grams.

Now, we can find the change in temperature of this cube of aluminum:

Mathematically, the quantity of heat energy is given by the formula;

Q = mc\theta

Where:

  • Q represents the quantity of heat energy.
  • m represents the mass of an object.
  • c is the specific heat capacity.
  • ∅ is the change in temperature.

Substituting the parameters into the formula, we have;

47000 = 21600 * 0.217 * \theta\n\n47000 = 4687.2 \theta\n\n \theta =(47000)/(4687.2) \n\n \theta = 10.03

Change in temperature = 10°C

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Answer:

10 °C

Explanation:

From the question given above, the following data were obtained:

Egde length (L) of aluminum = 20 cm

Density of Aluminum = 2.7 g/cm³

Specific heat capacity (C) of aluminum = 0.217 cal/ g°С

Heat (Q) energy = 47000 cal

Change in Temperature (ΔT) =?

Next, we shall determine the volume of the aluminum. This can be obtained as follow:

Egde length (L) of aluminum = 20 cm

Volume (V) of aluminum =?

V = L³

V = 20³

V = 8000 cm³

Thus, the volume of the aluminum is 8000 cm³

Next, we shall determine the mass of the aluminum. This can be obtained as follow:

Density of Aluminum = 2.7 g/cm³

Volume of Aluminum = 8000 cm³

Mass of aluminum =.?

Density = mass/volume

2.7 = mass /8000

Cross multiply

Mass of aluminum = 2.7 × 8000

Mass of Aluminum = 21600 g

Finally, we shall determine the change in temperature of the aluminum as follow:

Specific heat capacity (C) of aluminum = 0.217 Cal/g°С

Heat (Q) energy = 47000 Cal

Mass (M) of Aluminum = 21600 g

Change in Temperature (ΔT) =?

Q = MCΔT

47000 = 21600 × 0.217 × ΔT

47000 = 4687.2 × ΔT

Divide both side by 4687.2

ΔT = 47000 / 4687.2

ΔT = 10 °C

Therefore, the increase in the temperature of the aluminum is 10 °C.

A jogger runs 4 km in 0.4 hr, then 8 km in 0.8 hr. What is the average speed of the jogger?

Answers

The jogger would have ran about 10 km/h.

If I am given a total capacitence of two capacitors, their capacitence togather is 22 F. What capacitence would the individual capacitors have if they are connected in parallel or connected in series.

Answers

Answer:

In parallel combination, the capacity of each capacitor is 11 F.

In series combination, the capacity of each capacitor is 44 F.

Explanation:

Let there are two capacitors each of capacitance C.

When they are connected in parallel:

In parallel combination, the effective capacitance is Cp.

Cp = C1 + C2 = C + C

22 = 2 C

C = 11 F

When they are connected in series:

In parallel combination, the effective capacitance is Cs.

1 / Cs = 1 / C1 + 1 / C2 = 1 / C + 1 / C = 2 / C

1 / 22 = 2 / C

C = 44 F

Two microwave frequencies are authorized for use in microwave ovens: 895 and 2560 mhz. calculate the wavelength of each.

Answers

Wavelength = (speed) / (frequency)

The speeds of the two possible signals are equal, just like
all other forms of electromagnetic radiation.

Wavelength of 895 MHz = (3 x 10⁸ m/s) / (8.95 x 10⁸/s) = 0.335 m

Wavelength of 2560 MHz = (3 x 10⁸ m/s) / (2.56 x 10⁹/s) =  0.117 m 

Light of wavelength 608.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 88.5 cm from the slit. The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm. What is the width of the slit?

Answers

Answer:

The width of the slit is 0.167 mm

Explanation:

Wavelength of light, \lambda=608\ nm=608* 10^(-9)\ m

Distance from screen to slit, D = 88.5 cm = 0.885 m

The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m

We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :

y=(mD\lambda)/(a)

where

a = width of the slit

a=(mD\lambda)/(y)

a=(5* 0.885\ m* 608* 10^(-9)\ m)/(0.0161\ m)

a = 0.000167 m

a=1.67* 10^(-4)\ m

a = 0.167 mm

So, the width of the slit is 0.167 mm. Hence, this is the required solution.