Answer:
Yield strength, tensile strength decreases with increasing temperature and modulus of elasticity decreases with increasing in temperature.
Explanation:
The modulus of elasticity of a material is theoretically a function of the shape of curve plotted between the potential energy stored in the material as it is loaded versus the inter atomic distance in the material. The temperature distrots the molecular structure of the metal and hence it has an effect on the modulus of elasticity of a material.
Mathematically we can write,
where,
E(t) is the modulus of elasticity at any temperature 'T'
is the modulus of elasticity at absolute zero.
is the mean melting point of the material
Hence we can see that with increasing temperature modulus of elasticity decreases.
In the case of yield strength and the tensile strength as we know that heating causes softening of a material thus we can physically conclude that in general the strength of the material decreases at elevated temperatures.
Web application 3’s “Where’s the Beef” exploit can be seen in the screenshot provided. In order to mitigate this vulnerability, developers should take measures to ensure that input validation is performed on all data.
Additionally, developers should enforce strict rules on which characters are allowed in user inputs and reject all requests that don’t follow these rules. Finally, developers should implement best practices such as password hashing to ensure that user data is secure.
Developers should use secure coding techniques, such as sanitizing user input and properly escaping HTML output, to protect against injection-based attacks. Also, developers should implement authentication and authorization techniques to ensure that only authorized users have access to sensitive data. Furthermore, developers should use an up-to-date web application firewall to protect against known exploits, and use secure protocols such as HTTPS to protect data in transit. Finally, developers should ensure that software is kept up-to-date and patched to prevent exploitation of known vulnerabilities.
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Answer: Fossil remains of the same land-dwelling animal.
Explanation: Fossil remains which were found to belong to same land dwelling animals, in South America and Africa was used as evidence to help support the theory of Tectonics plates, what this theory simply means is that the whole continents of earth were once fused together until a tectonic plate caused it’s division. Since same remains were found in Africa and South America this shows that both continents were once fused together.
Answer:
Fossil remains of the same land-dwelling animal
Explanation:
Fossil remains tell us where the animals once lived and how by the movement of plate spearated their remaind that was burried thousands of years ago.
☐ E-W
☐ NW-SE
☐ NE-SW
Answer:
☐ NE-SW
Explanation:
Based on the description, the rock direction is North East - South West (NE-SW). Rocks generally can expand or compress depending on the type and magnitude of stress applied on the rocks. However, if the applied stress is sufficiently high, cracks and fractures will be created on the rock and it can ultimately lead to the formation of particles.
O B. Power is a measure of how quickly work is done.
O C. Power and work have the same unit of measurement
O D. Power is the amount of work needed to overcome friction.
Pls answer quick
B
a jsdnjwevhfgruewbkuwygru
again = "false";
result = 0;
a. choice
b. again
c. result
d. none of these are Boolean variables
Answer:
C
Explanation:
Boolean Algebra deals with either a one or a zero and how to manipulate them in computers or elsewhere. The "choice" option may not work, since for text it must be enclosed in quotation marks, usually. For "again," it's text and not a 1 or 0. So, the answer is C, since this is a 0.
Answer:
True
Explanation:
For steels, we can assume the endurance limit measured by rotating beam tests is the 50% of the ultimate tensile strength (UTS) as long as the UTS is equal to or less than 200 kpsi (1400 MPa).
Also, It is a simplistic rule of thumb that, for steels having a UTS less than 160 kpsi, the endurance limit for the material will be approximately 45 to 50% of the UTS.