8. Removing damage by tapping it out with a hammerand dolly is often referred to as
(A) contouring
(B) roughing out
(C) forming
(D) tapping out

Answers

Answer 1

Answer:

Answer:

tapping out I think sorry if I'm wrong

Related Questions

A chemical process converts molten iron (III) oxide into molten iron and carbon dioxide by using a reducing agent of carbon monoxide. The process allows 10.08 kg of iron to be produced from every 16.00 kg of iron (III) oxide in an excess of carbon monoxide. Calculate the percentage yield of iron produced in this process.
How to find magnitude of net electric charge when current flows through a capacitor with initial charge?
In a refrigerator, heat is transferred from a lower-temperature medium (the refrigerated space) to a higher-temperature one (the kitchen air). Is this a violation of the second law of thermodynamics
Given that the debouncing circuit is somewhat expensive in terms of hardware (2 NAND gates, 2 resistors, and a double-pole, single throw switch), describe applications where you would require switch-debouncing circuits as well as applications where you would not need to include the additional hardware for switch debouncing (in other words, applications where you can tolerate switch bouncing). Note, you cannot use the clock and clear inputs of our lab as example applications; instead you need to think of other examples.
Write two scnr.nextInt statements to get input values into birthMonth and birthYear. Then write a statement to output the month, a slash, and the year. End with newline. The program will be tested with inputs 1 2000 and then with inputs 5 1950. Ex: If the input is 1 2000, the output is: 1/2000

A cube with 1 m on a side is located in the positive x-y-z octant in a Cartesian coordinate system, with one of its points located at the origin. Find the total charge contained in the cube if the charge is given by p_v = x^2 ye^-z mC/m^3

Answers

Answer:

4.61 mC

Explanation:

The cube has 1 m side in the positive x-y-z octant in a Cartesian coordinate system, with one of its points located at the origin. The charge density is given as:

$\rho_v=x^2ye^(-z) \ mC/m^3$

Charge density is the charge per unit length or area or volume. It is the amount of charge in a particular region.

The charge Q is given as:

$Q=\int\limits_v {\rho_v} \, dv \nQ=\int\limits_v {\rho_v} \, dv=\int\limits^2_(x=0)\int\limits^2_(y=0)\int\limits^2_(z=0) {x^2ye^(-z)} \, dxdydz\n$

$Q=\int\limits^2_(x=0) {x^2} \, dx \int\limits^2_(y=0) {y} \, dy \int\limits^2_(z=0) {e^(-z)} \, dz \n\nQ=((1)/(3) [x^3]^2_0)((1)/(2) [y^2]^2_0)(-1 [e^(-z)]^2_0)\n\nQ=(-1)/(6) ([x^3]^2_0)( [y^2]^2_0)( [e^(-z)]^2_0)\n\nQ=(-1)/(6)[2^3-0^3][2^2-0^2][e^(-2)-e^0]\n\nQ=(-1)/(6)(8)(4)(0.1353-1)=(-1)/(6)(8)(4)(-0.8647)\n\nQ=4.61\ mC$

Whats are the best choice of cooling towers for electeic generating power plant and why?

Answers

Answer:

Cooling tower using the "Induced draft tower" mode of operation.

Explanation:

Electric generating power plant generates a lot of steam and heat. On the efficiency aspect of the cooling tower with respect to the operation of the power plant, a cooling tower with its fan at the end of the airstream leaving the tower is best applied considering the pressure of steam coming out of the turbine. On the maintenance angle, it is easier to maintain.

Consider the string length equal to 7. This string is distorted by a function f (x) = 2 sin(2x) - 10sin(10x). What is the wave formed in this string? a. In=12cos (nit ) sin(max) b. 2cos(2t)sin (2x) - 10cos(10t ) sin(10x) c. n 2 sin 2x e' – 10sin 10x e

Answers

Answer:

hello your question has a missing part below is the missing part

Consider the string length equal to $\pi$

answer : 2cos(2t) sin(2x) - 10cos(10t)sin(10x)

Explanation:

Given string length = $\pi$

distorted function f(x) = 2sin(2x) - 10sin(10x)

Determine the wave formed in the string

attached below is a detailed solution of the problem

Karen just checked her bank balance and the balance was 1111.11. She is kind of freaking out and saved the receipt, thinking that it must mean something. Karen is probably just suffering from

Answers

Answer:

chronic stoner syndrome

Explanation:

"the universe just sends us messages sometimes mannnn, you just have to be ready to listen to them" lol

The sports car has a weight of 4500-lb and a center of gravity at G. If it starts from rest it causes the rear wheels to slip as it accelerates. Determine how long it takes for it to reach a speed of 10 ft/s. Also, what are the normal reactions at each of the four wheels on the road? The coefficients of static and kinetic friction at the road are us=0.5 and uk=0.3, respectively. Neglect the mass of the wheels.

Answers

Answer:

Time=2.72 seconds

Front wheel reactions= 1393 lb

Rear wheel reactions= 857 lb

Explanation:

The free body diagram is assumed to be the one attached here

The mass, m of the car is

$M=\frac {W}{g}$ where W is weight and g is acceleration due to gravity

Taking g as $32.2 ft/s^(2)$ then

$M=\frac {4500}{32.2}=139.75 lbm$

Considering equilibrium in x-axis

$Ma_G-f=0$

$Ma_G-(\mu_g* 2N_B)=0$

$139.75* a_G-(0.3* 2* N_B)=0$

$0.6N_B=139.75a_g$

$N_B=232.92a_g$

At point A using the law of equilibrium, the sum of moments is 0 hence

$-2N_B(6)+4500(2)=-Ma_G(2.5)$

$-12N_B+9000=-139.75a_G* 2.5$

$-12(232.92a_G)+900=-349.375a_G$

$a_g\approx 3.68 ft/s^(2)$

The normal reaction at B is therefore

$N_B=232.92a_G=232.92* 3.68\approx 857 lb$

Consider equilibrium in y-axis

$4500-2N_A-2N_B=0$

$N_A+N_B=2250$

$N_A+857=2250$

$N_A=1393 lb$

To find time that the car takes to a speed of 10 ft/s

Using kinematic equation

V=u+at

10=0+3.68t

$t=\frac {10}{3.68}\approx 2.72 s$

An escalator with 35° incline is designed to have two passengers per step. Find number of persons moved per hour for the design if velocity is 50cm/mins and the step tread is 600mm.