nononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononno
Solution :
i. Slip plane (1 1 0)
Slip direction -- [1 1 1]
Applied stress direction = ( 1 0 0 ]
τ = 50 MPa ( Here slip direction must be perpendicular to slip plane)
τ = σ cos Φ cos λ
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
ii. Slip plane --- (1 1 0)
Slip direction -- [1 1 1]
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
iii. Slip plane --- (1 0 1)
Slip direction --- [1 1 1]
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
iv. Slip plane -- (1 0 1)
Slip direction ---- [1 1 1]
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
∴ (1, 0, -1). (1, -1, 1) = 1 + 0 - 1 = 0
Find the given attachments for complete explanation
(b) 75 kHz
(c) 80 kHz
(d) 160 kHz
(e) None of the above.
Answer:
Option D
160 kHz
Explanation:
Since we must use at least one synchronization bit, total message signal is 15+1=16
The minimum sampling frequency, fs=2fm=2(5)=10 kHz
Bandwith, BW required is given by
BW=Nfs=16(10)=160 kHz
Answer:
hello your question has a missing part below is the missing part
Consider the string length equal to
answer : 2cos(2t) sin(2x) - 10cos(10t)sin(10x)
Explanation:
Given string length =
distorted function f(x) = 2sin(2x) - 10sin(10x)
Determine the wave formed in the string
attached below is a detailed solution of the problem
Answer:
Explanation:
From the question we are told that:
Voltage
Power
Initial Power factor
Final Power factor
Generally the equation for Reactive Power is mathematically given by
Q=P(tan \theta_2-tan \theta_1)
Since
And
Therefore
Therefore
The size of the capacitor in vars that is necessary to raise the power factor to 0.9 lagging is
Answer:
ask someone u fool hhhhhhhh