A system with a mass of 8 kg, initially moving horizontally with a velocity of 40 m/s, experiences a constant horizontal force of 25 N opposing the direction of motion. As a result, the system comes to rest.
​Determine the amount of energy transfer by work, in kJ, for this process and the total distance, in m, that the system travels.

Answers

Answer 1
Answer:

Answer:

The kinetic energy is 6.4 kJ and the distance traveled by the system is 256 m.

Explanation:

Given the mass of the system (m) is 8 kg.

And initially, it moves with a velocity (v) 40 m/s.

Also, it experiences 25 N force (f) which opposes its motion.

We need to find the kinetic energy and the distance traveled by the system (d) before going to rest.

It will be the kinetic energy of 8 kg mass with 40 m/s velocity that is transferred to work.

K.E=(1)/(2)mv^2\nK.E=(1)/(2)* 8* 40^2\nK.E= 6400\ J\nK.E=6.4\ kJ

Since this system is opposed by 25 N force, work done by the force will be.

W=f(d)

And the kinetic energy transferred to work. We can equate them.

f(d)=6400\n25(d)=6400\nd=(6400)/(25)=256\ m

So, the system will travel 256 m.


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Answers

Answer:

(b) False

Explanation:

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Required:
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Answers

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The structure of a house is such that it loses heat at a rate of 5400 kJ/h per degree Cdifference between the indoors and outdoors. A heat pump that requires a power input of 6 kW isused to maintain this house at 21 C. Determine the lowest outdoor temperature for which the heatpump can meet the heating requirements of this house

Answers

Answer: Tl = - 13.3°C

the lowest outdoor temperature is - 13.3°C

Explanation:

Given that;

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Answers

Answer:

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Answers

Answer:

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Explanation:

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G  is the shear  modulus.

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Answers

Answer:

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Explanation:

See it in the pic

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