A ___________ is defined as a change in shape of the part between the damaged and undamaged area hat is smooth and continuous. When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation
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A plastic deformation is defined as a change in shape of the part between the damaged and undamaged area that is smooth and continuous. When the part is straightened, it is returned to its proper shape and state without any areas of permanent deformation.
Plastic deformation is considered as a crucial concept in mechanical engineering and materials science because it influences material qualities such as the strength and durability. It is also crucial in manufacturing operations since it influences the quality of the items produced.
Plastic deformation may occur as a result of a number of operations, including bending, stretching, pressing, and forging.
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A hydraulic jump is induced in an 80 ft wide channel. The water depths on either side of the jump are 1 ft and 10 ft. Please calculate: a) The velocity of the faster moving flow. b) The flow rate (discharge). c) The Froude number of the sub-critical flow. d) The flow energy dissipated in the hydraulic jump (expressed as percentage of the energy prior to the jump). e) The critical depth.
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The temperature drop of air if air is assumed to be an ideal gas for which C_p = ⁷/₂R is; Δt = 1546 K
We are given;
Final velocity; v₂ = 300 m/s
C_p = ⁷/₂R
At constant pressure, the change in enthalpy is;
Δh = C_p × Δt
Now, from first law of thermodynamics;
h₂ + (v₂²/2) = h₁ + (v₁²/2)
We are told initial velocity is negligible and as such v₁ = 0 m/s
Thus;
h₂ + (v₂²/2) = h₁ + 0
(h₁ - h₂) = (v₂²/2)
Thus; Δh = v₂²/2
Finally;
C_p × Δt = v₂²/2
Δt = v₂²/2/(C_p)
Δt = (300²/2)/(⁷/₂R)
where R is ideal gas constant = 8.314 Kj/kg.mol
Thus;
Δt = (300²/2)/(⁷/₂ × 8.314)
Δt = 1546 K
Read more at; brainly.com/question/24188841
Answer:
ΔH+U²/2=0
and
ΔH=×ΔT
∴to get the temperature drop of air, you make ΔT subject of the formula
ΔT=-U²/2Cp
=-300²/2××8.314
∴ΔT=-1546K
Explanation:
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Answer. In the present study, it was found that 61% students had multimodal learning style preferences and that only 39% students had unimodal preferences. Amongst the multimodal learning styles, the most preferred mode was bimodal, followed by trimodal and quadrimodal respectively
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See attachment for the detailed step by step solution of the given problem.
(A) contouring
(B) roughing out
(C) forming
(D) tapping out
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tapping out I think sorry if I'm wrong