Write a program that allows you to enter grocery item names into an array of strings and the cost of each item in an array of doubles. At the beginning of the program prompt the user to enter the total number of items they will be entering. Max value of 100. After entering the item names and cost, the application should display the names and cost and total cost of all items.
Answers
Answer:
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
//declare arrays
string ItemName[100];
double ItemCost[100]={0.0};
//declare variable
string name="";
double Total=0.0;
int NumItems=0;
cout<<"Enter number of grocery item you will be entering";
cin>>NumItems
cout<<"\n";
if (NumItems>100)
{
cout<<"Enter grocery items less than 100"
cin>>NumItems
cout<<"\n";
}
for (int i=1;i>=NumItems;i++)
{
cout<<"Please enter the item name in one word only, Example: icecream\n";
cin>>ItemName[i]
cout<<"Please enter the cost as a decimal number, Example: 2.05\n\n";
cin>>ItemCost[i];
}
cout<<"Items"<<" "<<""$""<<"Cost"<<endl
for (int i=1;i>=NumItems;i++)
{
cout<<ItemName[i]<<" "<<"$"<<ItemCost[i]<<endl
}
for (int i=1;i>=NumItems;i++)
{
Total=Total+ItemCost[i];
}
cout<<"Total:$"<<Total<<endl;
system("PAUSE");
return 0;
}
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An industrial load with an operating voltage of 480/0° V is connected to the power system. The load absorbs 120 kW with a lagging power factor of 0.77. Determine the size of the capacitor in vars that is necessary to raise the power factor to 0.9 lagging.
Answers
Answer:
option B
Explanation:
given,
heating tap water from 16° C to 50° C
at the average rate of 0.2 kg/min
the COP of this heat pump is 2.8
power output = ?
the required power input is 0.169 kW or 0.17 kW
hence, the correct answer is option B
Answers
Answer. In the present study, it was found that 61% students had multimodal learning style preferences and that only 39% students had unimodal preferences. Amongst the multimodal learning styles, the most preferred mode was bimodal, followed by trimodal and quadrimodal respectively
Explanation:
Answers
Answer: hello your question is incomplete below is the missing part
question :Determine the temperature of the cooled water exiting the cooling tower
answer : T = 43.477° C
Explanation:
Temp of water at exit = 45°C
mass flow rate of cooling tower = 15,000 kg/s
Temp of makeup water = 20°C
Assuming an atmospheric pressure of = 101.3 kPa
Determine temperature of the cooled water exiting the cooling tower
Water entering cooling tower at 45°C
Given that Latent heat of water at 45°C = 43.13 KJ/mol
Cp(wet air) = 1.005+ 1.884(y1)
where: y1 - Inlet mole ratio = (0.01257) / (1 - 0.01257) = 0.01273
Hence : Cp(wet air) = 29.145 + (0.01273) (33.94) = 29.577 KJ/kmol°C
First step : calculate the value of Q
Q = m*Cp*(ΔT) + W(latent heat)
Q = 321.6968 (29.577) (40-30) + 43.13 (18.26089)
Q = 95935.8547 KJ/s
Given that mass rate of water = 15000 kg/s
Hence the temperature of the cooled water can be calculated using the equation below
Q = m*Cp*∆T
Cp(water) = 4.2 KJ/Kg°C
95935.8547 = (15000)*(4.2)*(45 - T)
( 45 - T ) = 95935.8547/ 63000. ∴ T = 43.477° C
Answers
Answer:
11.125°
Explanation:
Given:
Radius of bend, R = 100 m
Speed around the bend = 50 Km/hr = = 13.89 m/s
Now,
We have the relation
where,
θ = angle of banking
g is the acceleration due to gravity
on substituting the respective values, we get
or
or
θ = 11.125°
Answers
b. A rigid bar does not bend regardless of the loads acting upon it.
c. A rigid bar deforms when experiencing applied loads.
d. A rigid bar is unable to translate or rotate about a support.
e. A rigid bar represents an object that does not experience deformation of any kind.
Answers
Answer:
option b and E are true
Explanation:
A lever is an example of a rigid bar that can rotate around a given point. In a rigid material, the existing distance does not change whenever any load is placed on it. In such a material, there can be no deformation whatsoever. Wit this explanation in mind:
option a is incorrect, given that we already learnt that no deformation of any kind happens in a rigid bar.
option b is true. A rigid bar remains unchanged regardless of the load that it carries.
option c is incorrect, a rigid bar does not deform with loads on it
option d is incorrect. A lever is a type of rigid bar, a rigid bar can rotate around a support.
option e is true. A rigid bar would not experience any deformation whatsoever.