Logical variables: Running late? Complete the tunction RunningLate such that the logical variable on Time is true if no Traffic is true and gasEmpty is false. Ex >> n°Traffic = true ; >> gasEmpty-false; >onTime - Runninglate(noTraffic,gasEmpty) logical Your Function B Save C Reset EE MATLAB Documentation 1 function onTime - RunningLate (noTraffic,gasEmpty) 2 % complete the logical expression to the right of . using the variables n°Traffic and gasEmpty 4 onTime - 6 end Code to call your function C Reset 1 noTraffic true; gasEmpty true; 2 onTime-Runninglate(noTraffic, gasEmpty)

Answers

Answer 1

Answer:

The program was written in MATLAB. The program source file has an incomplete function, that needs to be completed.

Complete the function with the following code segment

function onTime = RunningLate (noTraffic, gasEmpty)

onTime = ((noTraffic) & not(gasEmpty))

end

The following, should be noted about the above code segment

The first line declares/defines the function; The function name is RunningLate, and it receives noTraffic and gasEmpty as its parameters
On the second line; If noTraffic is true and gasEmpty is false, the function will return true
If otherwise, it will return false.

I've added the image of the complete question (in a more presentable format), as an attachment.

As stated above;

After running the complete program; onTime will be true if noTraffic and gasEmpty are true and false, respectively.

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Considering only (110), (1 1 0), (101), and (10 1 ) as the possible slip planes, calculate the stress at which a BCC single crystal will yield if the critical resolved shear stress is 50 MPa and the load is applied in the [100] direction.

What is the primary function of NCEES?

Answers

Answer:

A primary function of NCEES is to prepare standardized, confidential examinations that are used by the state and territorial boards to help determine the competency of individuals seeking to become licensed to practice as professional engineers and land surveyors.

Explanation:

i looked it up

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Calculate how large a mass would be necessary to obtain a mechanical noise limit of [Equation] = 1 nG, 1 µG, and 1 mG if the mechanical resonance frequency is [Equation] = 100 Hz. If the mass is to be made of cube of `silicon, what would its physical dimensions be?

Answers

Answer:

Mechanical resonance frequency is the frequency of a system to react sharply when the frequency of oscillation is equal to its resonant frequency (natural frequency).

The physical dimension of the silicon is 10kg

Explanation:

Using the formular, Force, F = 1/2π√k/m

At resonance, spring constant, k = mw² ( where w = 2πf), when spring constant, k = centripetal force ( F = mw²r).

Hence, F = 1/2π√mw²/m = f ( f = frequency)

∴ f = F = mg, taking g = 9.8 m/s²

100 Hz = 9.8 m/s² X m

m = 100/9.8 = 10.2kg

The specific volume of mercury is .00007 m^3/Kg. What is its density in lbm/ft^3?

Answers

Answer:

891.027 lbm/ft³

Explanation:

See it in the pic

Which of these factors would help the environment?a. Betty drinks only bottled water instead of soda.
b. Greg changes all of the light bulbs in the office to energy efficient bulbs.
c. John keeps his off topic conversations down to 10 minutes a day.
d. Doug turns the air conditioning down to cool the office during the hot summer months.
Please select the best alswer from the choices provided
A
B
D

Answers

Answer:

B. Greg changes all of the light bulbs in the office to energy efficient bulbs.

Explanation:

Energy efficient bulbs help you to reduce the carbon footprint of your office / house and last up to 12 times as long as traditional bulbs, using less electricity to emit the same amount of light as a traditional bulb.

Answer:

Explanation:

The sports car has a weight of 4500-lb and a center of gravity at G. If it starts from rest it causes the rear wheels to slip as it accelerates. Determine how long it takes for it to reach a speed of 10 ft/s. Also, what are the normal reactions at each of the four wheels on the road? The coefficients of static and kinetic friction at the road are us=0.5 and uk=0.3, respectively. Neglect the mass of the wheels.

Answers

Answer:

Time=2.72 seconds

Front wheel reactions= 1393 lb

Rear wheel reactions= 857 lb

Explanation:

The free body diagram is assumed to be the one attached here

The mass, m of the car is

$M=\frac {W}{g}$ where W is weight and g is acceleration due to gravity

Taking g as $32.2 ft/s^(2)$ then

$M=\frac {4500}{32.2}=139.75 lbm$

Considering equilibrium in x-axis

$Ma_G-f=0$

$Ma_G-(\mu_g* 2N_B)=0$

$139.75* a_G-(0.3* 2* N_B)=0$

$0.6N_B=139.75a_g$

$N_B=232.92a_g$

At point A using the law of equilibrium, the sum of moments is 0 hence

$-2N_B(6)+4500(2)=-Ma_G(2.5)$

$-12N_B+9000=-139.75a_G* 2.5$

$-12(232.92a_G)+900=-349.375a_G$

$a_g\approx 3.68 ft/s^(2)$

The normal reaction at B is therefore

$N_B=232.92a_G=232.92* 3.68\approx 857 lb$

Consider equilibrium in y-axis

$4500-2N_A-2N_B=0$

$N_A+N_B=2250$

$N_A+857=2250$

$N_A=1393 lb$

To find time that the car takes to a speed of 10 ft/s

Using kinematic equation

V=u+at

10=0+3.68t

$t=\frac {10}{3.68}\approx 2.72 s$

(d) Arches NP is known for its spectacular arches that develop in the jointed areas of the park. Placemark Problem 2d flies you to Landscape Arch, the arch with the largest span in Arches NP. If the stresses that stretched the rock to form the joints were oriented perpendicular to the joint surfaces and the rock fins that contain the arches, what was the direction that the rocks were stretched? ☐ N-S
☐ E-W
☐ NW-SE
☐ NE-SW

Answers

Answer:

☐ NE-SW

Explanation:

Based on the description, the rock direction is North East - South West (NE-SW). Rocks generally can expand or compress depending on the type and magnitude of stress applied on the rocks. However, if the applied stress is sufficiently high, cracks and fractures will be created on the rock and it can ultimately lead to the formation of particles.

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