Currently, system administrators create Ken 7 users in each computer where users need access. In the Active Directory, where will system administrators create Ken 7 users? 2. How will the procedures for making changes to the user accounts, such as password changes, be different in the Active Directory? 3. What action should administrators take for the existing workgroup user accounts after converting to the Active Directory? 4. How will the administrators resolve the differences between the user accounts defined on the different computers? In other words, if user accounts have different settings on different computers, how will the Active Directory address that issue? 5. How will the procedure for defining access controls change after converting to the Active Directory?

Answers

Answer 1

Answer:

1. First, you would need to open Active Directory Users and Computers. You click on the folder in which you want to add an account, and point to new, and then user. You would fill in the new user's information, such as name and initials.

2. In Active Directory, you input the user logon name, click on the UPN suffix in the drop-down list. It will prompt you to input password and confirm it.

3. Administrators would need to create new user accounts for all users, then join these to the AD domain manually.

4. Administrators will have to manually change the permissions and privileges of the users in order to meet the new established requirements.

5. After converting to the Active Directory, access control will be administered at the object level by setting different levels of access.

Related Questions

What is the deflection equation for a simply supported beam with a uniformly distributed load?
In response to the market revolution:the legal system worked with local governments to find better ways to regulate entrepreneurs.Chief Justice John Marshall ruled that legislatures could not alter or rescind charters and contracts that previous legislatures had created.local judges protected businessmen from paying property damages associated with factory construction and from workers seeking to unionize.Massachusetts Chief Justice Lemuel Shaw held in Commonwealth v. Hunt that workers had no right to organize.corporations proved less able to raise capital than chartered companies did.
Which of these factors would help the environment?a. Betty drinks only bottled water instead of soda.b. Greg changes all of the light bulbs in the office to energy efficient bulbs.c. John keeps his off topic conversations down to 10 minutes a day.d. Doug turns the air conditioning down to cool the office during the hot summer months.Please select the best alswer from the choices providedABD
2) The switch in the circuit below has been closed a long time. At t=0, it is opened.Find the inductor current for il(t) for t> 0.
An environmental engineer is considering three methods for disposing of a nonhazardous chemical sludge: land application, fluidized-bed incineration, and private disposal contract. The estimates for each method are below. (a) Determine which has the least cost on the basis of an annual worth comparison at 10% per year. (b) Determine the equivalent present worth value of each alternative using its AW value

A furnace is shaped like a long equilateral triangular duct where the width of each side is 2 m. Heat is supplied from the base surface, whose emissivity is ε1 = 0.8, at a rate of 800 W/m2 while the side surfaces, whose emissivities are 0.5, are maintained at 500 K. Neglecting the end effects, determine the temperature of the base surface. Can you treat this geometry as a two-surface enclosure?

Answers

Answer:

The geometry is treated as a two surface enclosure because the two surfaces have the same properties.

Let's take the base surface to be surface 1, while the side surfaces are surface 2.

Let's take the heat transfer expression:

$Q_1_2 = (\sigma[(T_1)^4 - (T_2)^4])/((1 - E_1)/(A_1 E_1) + (1)/(A_1 F_1_2) + (1-E_2)/(A_2 E_2))$

Where,

$\sigma = Boltmanz constant = 5.68*10^-^8$

$T_1$ = base temperature

$T_2$ = surface 2 temperature = 500K

$E_1$ = emissivity of surface 1 = 0.8

$E_2$ = emissivity of surface 2 = 0.5

$A$ = Area

$F_1_2$ = shape factor

Substituting figures in the equation, we have:

$800= (5.67*10^-^8[(T_1)^4 - (500)^4])/((1 - 0.8)/(2*0.8) + (1)/(2*1) + (1-0.5)/(4*0.5))$

$[(T_1)^4 - (500)^4] = (700)/(5.67*10^-^8)$

$(T_1)^4 = 1.234*10^1^0 + 6.25*10^1^0$

$T_1 = (7.484*10^1^0)^0^.^2^5$

$T_1 = 523.038 K$

The base temperature is 523.038 k

The cost of hiring new employees outpaces the raises for established employees is A.
Salary compression

B.
Occupational based pay

C.
Merit pay

D.
Need for Achievement

Answers

Answer:

do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or

5. Switch a in the circuit has been open for a long time and switch b has been closed for a long time. Switch a is closed at t = 0. After remaining closed for 1s, switches a and b are opened simultaneously and remain open indefinitely. Determine the expression for the inductor current i that is valid when (a) 0 ≤ t ≤ 1s and (b) t ≥ 1s

Answers

Answer:

(a) 1/L∫Vdt; integral t [0,1]

(b) 1/L∫Vdt; integral t [ 1, infinity]

Explanation:

An Inductor current I, flowing through an inductor depends on the voltage, V, across the inductor and the inductance, L, of the inductor. The switch 1, 2 timing varies the voltage V with time t

The expression for inductor current is given as:

I= 1/L∫Vdt,

where I is equal to the current flowing through the inductor, L is equal to the inductance of the inductor, and V is equal to the voltage across the inductor.

The formula can also be written as:

I= I0 + 1/L∫Vdt, where I is inductor current at time t, and io is inductor current at t = 0. Time can be varied by controlling the switch

write an interface downloadable that has a method "geturl" that returns the url of a downloadable object

Answers

Answer:

I want to believe the program is to be written in java and i hope your question is complete. The code is in the explanation section below

Explanation:

import java.util.Date;

public interface Downloadable {

//abstract methods

public String getUrl();

public Date getLastDownloadDate();

}

Determine the voltage across a 2-μF capacitor if the current through it is i(t) = 3e−6000t mA. Assume that the initial capacitor voltage is zero g

Answers

Answer:

$v = 250[1 - {e^(-6000t)}]$ mV

Explanation:

The voltage across a capacitor at a time t, is given by:

$v(t) = (1)/(C) \int\limits^(t)_(t_0) {i(t)} \, dt + v(t_0)$ ----------------(i)

Where;

v(t) = voltage at time t

$t_(0)$ = initial time

C = capacitance of the capacitor

i(t) = current through the capacitor at time t

v(t₀) = voltage at initial time.

From the question:

C = 2μF = 2 x 10⁻⁶F

i(t) = 3 $e^(-6000t)$ mA

t₀ = 0

v(t₀ = 0) = 0

Substitute these values into equation (i) as follows;

$v = (1)/(2*10^(-6)) \int\limits^(t)_(0) {3e^(-6000t)} \, dt + v(0)$

$v = (1)/(2*10^(-6)) \int\limits^(t)_(0) {3e^(-6000t)} \, dt + 0$

$v = (1)/(2*10^(-6)) \int\limits^(t)_(0) {3e^(-6000t)} \, dt$

$v = (3)/(2*10^(-6)) \int\limits^(t)_(0) {e^(-6000t)} \, dt$ [Solve the integral]

$v = (3)/(2*10^(-6)*(-6000)) {e^(-6000t)}|_0^t$

$v = (-3000)/(12) {e^(-6000t)}|_0^t$

$v = -250 {e^(-6000t)}|_0^t$

$v = -250 {e^(-6000t)} - [-250 {e^(-6000(0))]$

$v = -250 {e^(-6000t)} - [-250]$

$v = -250 {e^(-6000t)} + 250$

$v = 250 -250 {e^(-6000t)}$

$v = 250[1 - {e^(-6000t)}]$

Therefore, the voltage across the capacitor is $v = 250[1 - {e^(-6000t)}]$ mV

A hydraulic jump is induced in an 80 ft wide channel. The water depths on either side of the jump are 1 ft and 10 ft. Please calculate: a) The velocity of the faster moving flow. b) The flow rate (discharge). c) The Froude number of the sub-critical flow. d) The flow energy dissipated in the hydraulic jump (expressed as percentage of the energy prior to the jump). e) The critical depth.