An industrial load with an operating voltage of 480/0° V is connected to the power system. The load absorbs 120 kW with a lagging power factor of 0.77. Determine the size of the capacitor in vars that is necessary to raise the power factor to 0.9 lagging.

Answers

Answer 1
Answer:

Answer:

Q=41.33 KVAR\ \nat\n\ 480 Vrms

Explanation:

From the question we are told that:

Voltage V=480/0 \textdegree V

Power P=120kW

Initial Power factor p.f_1=0.77 lagging

Final Power factor p.f_2=0.9 lagging

Generally the equation for Reactive Power is mathematically given by

Q=P(tan \theta_2-tan \theta_1)

Since

p.f_1=0.77

cos \theta_1 =0.77

\theta_1=cos^(-1)0.77

\theta_1=39.65 \textdegree

And

p.f_2=0.9

cos \theta_2 =0.9

\theta_2=cos^(-1)0.9

\theta_2=25.84 \textdegree

Therefore

Q=P(tan 25.84 \textdegree-tan 39.65 \textdegree)

Q=120*10^3(tan 25.84 \textdegree-tan 39.65 \textdegree)

Q=-41.33VAR

Therefore

The size of the capacitor in vars that is necessary to raise the power factor to 0.9 lagging is

Q=41.33 KVAR\ \nat\n\ 480 Vrms


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Answers

Answer:

answer is 0 ok answer is 0

Explanation:

A ___________ is defined as a change in shape of the part between the damaged and undamaged area hat is smooth and continuous. When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation

Answers

A plastic deformation is defined as a change in shape of the part between the damaged and undamaged area that is smooth and continuous. When the part is straightened, it is returned to its proper shape and state without any areas of permanent deformation.

Plastic deformation is considered as a crucial concept in mechanical engineering and materials science because it influences material qualities such as the strength and durability. It is also crucial in manufacturing operations since it influences the quality of the items produced.

Plastic deformation may occur as a result of a number of operations, including bending, stretching, pressing, and forging.

For more such questions on deformation, click on:

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Write a program to accept a one-line string (maximum of 100 characters) from the keyboard. Edit the string entered in Part 1a (with code that you write) to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. Print out the resulting compressed string to the screen.

Answers

Answer:

// This program is written in C++ programming language

// Comments are used for explanatory purpose

/* The aim of this program is to to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. */

// Program starts here

#include <stdio.h>

#include<iostream>

using namespace std;

int main()

{

// Declare Variable of 100 characters

char word[100];

// Prompt user for input

cout<<"Your input goes here (max, 100 characters)";

cin>>word;

// Iterate through string to check for non alphabetic characters

for (int i = 0; word[i] != '\0'; ++i) {

// Check for uppercase and lowercase letters

while (!((word[i] >= 'a' && word[i] <= 'z') || (word[i] >= 'A' && word[i] <= 'Z') || word[i] == '\0')) {

for (int j = i; word[j] != '\0'; ++j) {

word[j] = word[j + 1];

}

word[j] = '\0';

}

}

cout<<"The resulting compressed string: "<<word;

return 0;

}

Answer:

w = str(input("input your values: "))

values = ' '.join(filter(str.isalpha, w))

while len(w) < 100:

       print(values)

       break

Explanation:

The code is written in python

w = str(input("input your values: "))

This code ask the user to input any string values with characters, numbers, line spaces , letters etc.

values = ' '.join(filter(str.isalpha, w))

This code filters the inputted value to bring only letters. All the letter are then joined together

while len(w) < 100:

The code check if the inputted value is less than 100 characters. While it is less than 100 characters. If it is less than 100 character the next code will function.

print(values)

This code prints the joined letters after checking with  a while loop to confirm the length of character is less than 100

break

The break function breaks the code whether it print the values or not.

Generally, the letters will only be printed if the character inputted is less than 100 and later break the while loop or will not print any letter if the character is greater than 100 and later break.

Indicate whether the following statements are true or false for an isothermal process: (A) Q=T(∆S). (B) ∆U=0.(C) The entropy change of the system is always zero. (D) The total entropy change of the system and the surroundings is always zero. (E) The entropy change of the surroundings is negative. (F) Q=W.

Answers

Answer:

A=False

B=False

C=False

D=False

E=False

F=False

Explanation:

A. In an isothermal process, only the reversibly heat transfer is 0, Q_(rev)=T (\Delta S)

B. Consider the phase change of boiling water. Here, the temperature remains constant but the internal energy of the system increases.

C. This is not true even in reversible process, as can be inferred from the equation in part A.

D. This is only true in reversible processes, but not in all isothermal processes.

E. Consider the phase change of freezing water. Here, the surroundings are increasing their entropy, as they are taking in heat from the system.

F. This is not true if (\Delta U)\neq 0, like in answer B. One case where this is true is in the reversible isothermal expansion (or compression) of an ideal gas.

A 26-tooth pinion rotating at a uniform 1800 rpm meshes with a 55-tooth gear in a spur gear reducer. Both pinion and gear are manufactured to a quality level of 10. The transmitted tangential load is 22 kN. Conditions are such that Km = 1.7. The teeth are standard 20-degree, full-depth. The module is 5 and the face width 62 mm. Determine the bending stress when the mesh is at the highest point of single tooth contact.

Answers

Answer:

The bending stress of the face tooth is  \sigma _(bg) = 502.82 MPa

Explanation:

From the question we are told that

        The number of tooth of the pinion is  N_t = 26 \ tooth

         The velocity of rotation is given as \omega_p = 1800 rpm

         The number of tooth is of the gear is  N_g = 55 \ tooth

        The quality level is Q_r = 10

          The transmitted tangential load is F_T = 22\ kN = 22 KN * (1000N)/(1KN) = 22*10^3 N

                                                                    k_m = 1.7

        The angle of the teeth is  \theta_t = 20^o

         The module is  M= 5

         The face width is W_f = 62mm

The diameter of the pinion is mathematically represented as

                d_p = M * N_t

Substituting the values

                d_p = 5 *26

                    = 130 mm = (130)/(1000) = 0.130m

The pitch line velocity is mathematically represented as

                     V_t = (d_p )/(2) (2 \pi \omega_p)/(60)

Substituting values

                          = (0.130)/(2) * (2 * 3.142 * 1800 )/(60)

                          = 12.25\  m/s

Generally the dynamic factor is mathematically represented as

                      K_v = [(A)/(A +√(200V_t) ) ]^B

Now B is a constant that is mathematically represented as

                B = ((12 -Q_r )^(2/3))/(4)

substituting values

                  = ((12- 10 )^(2/3))/(4)

                  =0.3968

A is also a constant that is mathematically represented as

              A = 50 + 56(1 -B)

Substituting values

             = 50 +56 (1- 0.3968)

             = 83.779

Substituting these value into the equation for dynamic factor we have

           K_v = [(83.779)/(83.779 + √(200 * 12.25) ) ]^(0.3968)

                = 0.831

The geometric bending factor for a 20° profile from table

"AGMA Bending Geometry Factor J for 20°, Full -Depth Teeth with HPSTC Loading , Table 2-9"                

That corresponds to 55 tooth gear meshing with 26 pinion is

                   J_g = 0.41

the diameter pitch can be mathematically represented as

              p_d = (1)/(M)

Substituting values

            p_d  = (1)/(5)

                =0.2mm^(-1)

The mathematically representation for gear tooth bending stress in the teeth face is as follows

          \sigma_(bg) = (F_T \cdot p_d )/(W_f * J_g)(K_a K_(dt) )/(K_v) K_s K_B K_t ----(1)

Where W_t is the tangential load

            W_f is the face width

            K_a is the application factor  this is obtained from table "Application Factors, Table 12-17 " and the value  is  K_a  = 1

            K_(dt) is the load distributed factor

            K_s is the size factor

             K_B is the rim thickness factor which is obtained for M which has a value  1

           K_t is the idler

Substituting values into equation 1

     \sigma_(bg) = (22*10^3 *0.2)/(62 * 0.41) * (1 * 1.7 )/(0.831)  * 1 *1 *1.42

            = 502.82  N/mm^2

            = 502.82 * 1000 * (N)/(m^2)

           = 502.82 MPa

           

           

       

 

               

                 

In response to the market revolution:the legal system worked with local governments to find better ways to regulate entrepreneurs.Chief Justice John Marshall ruled that legislatures could not alter or rescind charters and contracts that previous legislatures had created.local judges protected businessmen from paying property damages associated with factory construction and from workers seeking to unionize.Massachusetts Chief Justice Lemuel Shaw held in Commonwealth v. Hunt that workers had no right to organize.corporations proved less able to raise capital than chartered companies did.

Answers

Answer:

Local judges protected businessmen from paying property damages associated with factory construction and from workers seeking to unionize.

Explanation:

The Market Revolution is the name given to change in the economy that occurred in the 19th century. This drastic change led to various important changes in the United States and across the world. During this period, capitalism became more entrenched and society became, for the first time, predominantly capitalist. This gave businessmen great power, as they played an increasingly important role when it came to economic growth. The power that they had influenced society deeply, including legislation. Judges often protected businessmen from paying property damages that were associated with their business enterprises. Moreover, workers had few rights and protections, and judges prevented them from unionizing.

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