1. (5 pts) An adiabatic steam turbine operating reversibly in a powerplant receives 5 kg/s steam at 3000 kPa, 500 °C. Twenty percent of the flow is extracted at 1000 kPa to a feedwater heater and the remainder flows out at 200 kPa. Find the two exit temperatures and the turbine power output.
Answers
Answer:
temperature of first extraction 330.8°C
temperature of second extraction 140.8°C
power output=3168Kw
Explanation:
Hello!
To solve this problem we must use the following steps.
1. We will call 1 the water vapor inlet, 2 the first extraction at 100kPa and 3 the second extraction at 200kPa
2. We use the continuity equation that states that the mass flow that enters must equal the two mass flows that leave
m1=m2+m3
As the problem says, 20% of the flow represents the first extraction for which 5 * 20% = 1kg / s
solving
5=1+m3
m3=4kg/s
3.
we find the enthalpies and temeperatures in each of the states, using thermodynamic tables
Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties
4.we find the enthalpy and entropy of state 1 using pressure and temperature
h1=Enthalpy(Water;T=T1;P=P1)
h1=3457KJ/kg
s1=Entropy(Water;T=T1;P=P1)
s1=7.234KJ/kg
4.
remembering that it is a reversible process we find the enthalpy and the temperature in the first extraction with the pressure 1000 kPa and the entropy of state 1
h2=Enthalpy(Water;s=s1;P=P2)
h2=3116KJ/kg
T2=Temperature(Water;P=P2;s=s1)
T2=330.8°C
5.we find the enthalpy and the temperature in the second extraction with the pressure 200 kPav y the entropy of state 1
h3=Enthalpy(Water;s=s1;P=P3)
h3=2750KJ/kg
T3=Temperature(Water;P=P3;s=s1)
T3=140.8°C
6.
Finally, to find the power of the turbine, we must use the first law of thermodynamics that states that the energy that enters is the same that must come out.
For this case, the turbine uses a mass flow of 5kg / s until the first extraction, and then uses a mass flow of 4kg / s for the second extraction, taking into account the above we infer the following equation
W=m1(h1-h2)+m3(h2-h3)
W=5(3457-3116)+4(3116-2750)=3168Kw
Related Questions
Consider the string length equal to 7. This string is distorted by a function f (x) = 2 sin(2x) - 10sin(10x). What is the wave formed in this string? a. In=12cos (nit ) sin(max) b. 2cos(2t)sin (2x) - 10cos(10t ) sin(10x) c. n 2 sin 2x e' – 10sin 10x e
1.19. A gas is confined in a 0.47 m diameter cylinder by a piston, on which rests a weight. The mass of the piston and weight together is 150 kg. The local acceleration of gravity is 9.813 m·s−2, and atmospheric pressure is 101.57 kPa. (a) What is the force in newtons exerted on the gas by the atmosphere, the piston, and the weight, assuming no friction between the piston and cylinder? (b) What is the pressure of the gas in kPa? (c) If the gas in the cylinder is heated, it expands, pushing the piston and weight upward. If the piston and weight are raised 0.83 m, what is the work done by the gas in kJ? What is the change in potential energy of the piston and weight?\
If the total energy change of an system during a process is 15.5 kJ, its change in kinetic energy is -3.5 kJ, and its potential energy is unchanged, calculate its change in specificinternal energy if its mass is 5.4 kg. Report your answer in kJ/kg to one decimal place.
In response to the market revolution:the legal system worked with local governments to find better ways to regulate entrepreneurs.Chief Justice John Marshall ruled that legislatures could not alter or rescind charters and contracts that previous legislatures had created.local judges protected businessmen from paying property damages associated with factory construction and from workers seeking to unionize.Massachusetts Chief Justice Lemuel Shaw held in Commonwealth v. Hunt that workers had no right to organize.corporations proved less able to raise capital than chartered companies did.
Answers
Answer: Provided in the explanation section
Explanation:
Transactional Leadership - This leadership style is mainly focused on the transactions between the leader and employees. If the employees work hard, achieve the objectives and deliver the results, they are rewarded through bonuses, hikes, promotions etc. If the employees fail to achieve the desired results, they are punished by awarding lower ratings in the performance appraisal, denying opportunities etc.
In this style, leader lays emphasis on the relation with the followers.
It is a reactive style where the growth of the employee in the organization completely depends on the performance with respect to the activities and deliverables.
It is best suited for regular operations and for a settled environment by developing the existing organizational culture which is not too challenging.
It is a bureaucratic style of leadership where the leader concentrates on planning and execution rather than innovation and creation.
A transactional leader is short-term focused and result oriented. He/she doesn't consider long-term strategic objectives regarding the organization's future.
cheers i hope this helped !!
b) sketch vc and ic.
Answers
Answer:
hello your question is incomplete attached is the complete question
A) Vc = 15 ( 1 - ) , ic =
B) attached is the relevant sketch
Explanation:
applying Thevenin's theorem to find the mathematical expression for the transient behavior of Vc and ic after closing the switch
= 8 k ohms || 24 k ohms = 6 k ohms
=
= 15 v
t = RC = (10 k ohms( 15 uF) = 0.15 s
Also; Vc =
hence Vc = 15 ( 1 - )
ic = =
=
attached
Answers
The program analyses a set of male and female names and displays, the combined set of names, specific names and neutral names. The program written in python 3 goes thus :
male_names = {'John', 'Bailey', 'Charlie', 'Chuck', 'Michael', 'Samuel', 'Jayden', 'Aiden', 'Henry', 'Lucas'}
#setofmalenames
female_names = {'Elizabeth', 'Meghan', 'Kim', 'khloe','Bailey', 'Jayden' , 'Aiden', 'Britney', 'Veronica', 'Maria'}
#setoffemalenames
neutral_names = male_names.intersection(female_names)
#names common to both males and females
all_names = male_names.union(female_names)
#set of all baby names ; both male and female
specific_names = male_names.symmetric_difference(female_names)
#name in one set and not in the other
print(all_names)
print(' ')
#leavesaspaceinbetweenthelines
print(specific_names)
print(' ')
print(neutral_names)
Asamplerunoftheprogramisattached.
Learn more :brainly.com/question/9908895
Answer:
Please see attachment
Explanation:
Please see attachment
100
101
102
103
104
105
Value
1
2.
3
8
15
16
hi
Answer:80
Answers
Answer:
364 566 inches of class-6th from a
Answers
Answer: The average distance the electron can travel in microns is 1.387um/s
Explanation: The average distance the electron can travel is the distance an exited electron can travel before it joins together. It is also called the diffusion length of that electron.
It is gotten, using the formula below
Ld = √DLt
Ld = diffusion length
D = Diffusion coefficient
Lt = life time
Where
D = 25cm2/s
Lt = 7.7
CONVERT cm2/s to um2/s
1cm2/s = 100000000um2/s
Therefore D is
25cm2/s = 2500000000um2/s = 2.5e9um2/s
Ld = √(2.5e9 × 7.7) = 138744.37um/s
Ld = 1.387e5um/s
This is the average distance the excited electron can travel before it recombine
Answers
Answer:
The correct answer is C) Trimetric
Explanation:
The most suitable answer is a trimetric projection because, in this type of projection, we see that the projection of the three angles between the axes are not equal. Therefore, to generate a trimetric projection of an object, it is necessary to have three separate scales.