1.19. A gas is confined in a 0.47 m diameter cylinder by a piston, on which rests a weight. The mass of the piston and weight together is 150 kg. The local acceleration of gravity is 9.813 m·s−2, and atmospheric pressure is 101.57 kPa. (a) What is the force in newtons exerted on the gas by the atmosphere, the piston, and the weight, assuming no friction between the piston and cylinder? (b) What is the pressure of the gas in kPa? (c) If the gas in the cylinder is heated, it expands, pushing the piston and weight upward. If the piston and weight are raised 0.83 m, what is the work done by the gas in kJ? What is the change in potential energy of the piston and weight?\

Answers

Answer 1
Answer:

In this exercise we have to use the knowledge of force to calculate the required energies, so we have to:

a) 19094 N

b) 110.055 kPa

c) 1222 J

What is the concept of force?

In the field of physics, force is a physical action that causes deformation or that changes the state of rest or movement of a given object.

a) Knowing that the force formula is defined by:

F = P + p * A\nF = m * g + p *\pi /4 * d^2\nF = 150 * 9.813 + 101570 * \pi /4 * 0.47^2 = 19094 N

b) Knowing that the force exerted by an area is equal to the pressure in that area, we have:

p_1 = F / A\np_1 = F / (\pi /4 * d^2)\np_1 = 19094 / (\pi /4 * 0.47^2) = 110055 Pa = 110.055 kPa

c)So calculating the potential energy we have:

\Delta E_p = m * g * \Delta h\n\Delta E_p = 150 * 9.813 * 0.83 = 1222 J

See more about force at brainly.com/question/26115859

Answer 2
Answer:

Answer:

a) 19094 N

b) 110.055 kPa

c) 1222 J

Explanation:

The force on the gas is the weight plus the atmospheric pressure multiplied by the piston area

F = P + p * A

F = m * g + p * π/4 * d^2

F = 150 * 9.813 + 101570 * π/4 * 0.47^2 = 19094 N

The pressure is the force divided by the area of the piston

p1 = F / A

p1 = F / (π/4 * d^2)

p1 = 19094 / (π/4 * 0.47^2) = 110055 Pa = 110.055 kPa

variation of gravitational potential energy is defined as

ΔEp = m * g * Δh

ΔEp = 150 * 9.813 * 0.83 = 1222 J


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Answer:

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#include <stdio.h>

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Answers

Answer:

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Explanation:

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Answers

Three activities that I can do on a daily basis that involve both metric units (SI units) and customary units are: measuring the length of a door with a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that calls for one teaspoon (customary unit) of baking soda, which can also be converted to four grams (SI unit); and weighing myself on a weighing scale, which can be measured in pound and kilogram (metric unit).

Answer: Three examples of activities that I can perform on a daily basis that involves both metric units (SI units) and customary units include: measuring the length of a door using a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that requires one teaspoon (customary unit) of baking soda, which could also be converted into four grams (SI unit); weighing myself on a weighing scale, which can be measured by pounds (customary unit) or kilograms (metric unit).

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Answers

Answer:

an attachment is below

Explanation:

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2) the responses of critically damped system and under damped system are shown with comments on their time response.

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Answers

Answer: The monthly payment before the buydown is $71.3

The monthly payment after the buydown is $68.9

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Where;

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P = principal

r= interest rate per payment

n= number of payment per period

t= number of period.

NOTE: from our questions, the period is yearly and the payment is monthly. Therefore;

number of payment per period (n) is 12

number of payment period (t) is 10

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FIND MONTHLY PAYMENT BEFORE BUYDOWN:

Step 1: find the Compounded amount to pay.

A= $8000[1+(0.00667÷12)^(12×10)]=

$8551.64 this is the total amount he has to pay for a period of 10years

Step 2: How much does he has to pay monthly for a period of 10year;

Therefore his payment will be for 120 months

$8551.64÷120= $71.3 monthly

FIND MONTHLY PAYMENT AFTER BUYDOWN:

Step 1: find the compounded amount to pay.

A= 8000[1+(0.00333÷12)^(12×10)=

$8270.85 this is the total amount he has to pay for a period of 10years

Step2: How much does he has to pay monthly for a period of 10year;

Therefore his payment will be for 120 months;

$8270.85÷120= $68.9 monthly