Technician A says that the unitized structure of a hybrid vehicle is considerably different when compared to the same conventional model.Technician B says that hybrid vehicles have 12-volt and high voltage batteries.

Who is right?

Answers

Answer 1

Answer:

Technician A says that the unitized structure of a hybrid vehicle is considerably different when compared to the same conventional model is right.

What are hybrid vehicle?

Hybrid vehicle are defined as a powered by a combustion engine and/or a number of electric motors that draw power from batteries. A gas-powered car simply has a traditional gas engine, but a hybrid car also features an electric motor.

One important advantage of hybrid cars is their capacity to reduce the size of the main engine, which improves fuel efficiency. Many hybrid vehicles employ electric motors to accelerate slowly at first until they reach higher speeds. They then use gasoline-powered engines to increase fuel efficiency.

Thus, technician A says that the unitized structure of a hybrid vehicle is considerably different when compared to the same conventional model is right.

To learn more about hybrid vehicle, refer to the link below:

brainly.com/question/14610495

#SPJ5

Answer 2

Answer: A train was right get it

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An automobile engine consumes fuel at a rate of 27.4 L/h and delivers 55 kW of power to the wheels. If the fuel has a heating value of 44,000 kJ/kg and a density of 0.73 g/cm3, deter- mine the efficiency of this engine in percentage(

Answers

Answer:

The efficiency of the engine is 22.5%.

Explanation:

Efficiency = power output ÷ power input

power output = 55 kW

power input = specific energy×volumetric flow rate×density

specific energy = 44,000 kJ/kg

volumetric flow rate = 27.4 L/h = 27.4 L/h × 1000 cm^3/1 L × 1 h/3600 s = 7.61 cm^3/s

density = 0.73 g/cm^3 = 0.73 g/cm^3 × 1 kg/1000g = 7.3×10^-4 kg/cm^3

power input = 44,000 kJ/kg × 7.61 cm^3/s × 7.3×10^-4 kg/cm^3 = 244.4332 kJ/s = 244.4332 kW

Efficiency = 55 ÷ 244.4332 = 0.225 × 100 = 22.5%

At full load, a commercially available 100hp, three phase induction motor operates at an efficiency of 97% and a power factor of 0.88 lag. The motor is supplied from a three-phase outlet with a line voltage rating of 208V.a. What is the magnitude of the line current drawn from the 208 V outlet? (1 hp = 746 W.) b. Calculate the reactive power supplied to the motor.

Answers

Answer:

I = Line Current = 242.58 A

Q = Reactive Power = 41.5 kVAr

Explanation:

Firstly, converting 100 hp to kW.

Since, 1 hp = 0.746 kW,

100 hp = 0.746 kW x 100

100 hp = 74.6 kW

The power of a three phase induction motor can be given as:

$P_(in) = √(3) VI Cos\alpha\n$

where,

P in = Input Power required by the motor

V = Line Voltage

I = Line Current

Cosα = Power Factor

Now, calculating Pin:

$efficiency = \frac{{P_(out)} }{P_(in) }\n0.97 = (74.6)/(P_(in) ) \nP_(in) = (74.6)/(0.97)\n P_(in) = 76.9 kW$

a) Calculating the line current:

$P_(in) = √(3)VICos\alpha \n76.9 * 1000= √(3)*208*I*0.88\nI = (76.9*1000)/(√(3)*208*0.88 )\nI = 242.58 A$

b) Calculating Reactive Power:

The reactive power can be calculated as:

Q = P tanα

where,

Q = Reactive power

P = Active Power

α = power factor angle

Since,

$Cos\alpha =0.88\n\alpha =Cos^(-1)(0.88)\n\alpha=28.36$

Therefore,

$Q = 76.9 * tan (28.36)\nQ = 76.9 * (0.5397)\nQ = 41. 5 kVAr$

A rocket is launched vertically from rest with a constant thrust until the rocket reaches an altitude of 25 m and the thrust ends. The rocket has mass 2 kg and thrust force 35 N. Neglecting air resistance, determine (a) the speed of the rocket when the thrust ends, (b) the maximum height reached by the rocket, and (c) the speed of the rocket when it returns to the ground.

Answers

Answer:

a) $v=19.6 m/s$

b) $H=19.58 m$

c) $v_(f)=29.57 m/s$

Explanation:

a) Let's calculate the work done by the rocket until the thrust ends.

$W=F_(tot)h=(F_(thrust)-mg)h=(35-(2*9.81))*25=384.5 J$

But we know the work is equal to change of kinetic energy, so:

$W=\Delta K=(1)/(2)mv^(2)$

$v=\sqrt{(2W)/(m)}=19.6 m/s$

b) Here we have a free fall motion, because there is not external forces acting, that is way we can use the free-fall equations.

$v_(f)^(2)=v_(i)^(2)-2gh$

At the maximum height the velocity is 0, so v(f) = 0.

$0=v_(i)^(2)-2gH$

$H=(19.6^(2))/(2*9.81)=19.58 m$

c) Here we can evaluate the motion equation between the rocket at 25 m from the ground and the instant before the rocket touch the ground.

Using the same equation of part b)

$v_(f)^(2)=v_(i)^(2)-2gh$

$v_(f)=\sqrt{19.6^(2)-(2*9.81*(-25))}=29.57 m/s$

The minus sign of 25 means the zero of the reference system is at the pint when the thrust ends.

I hope it helps you!

An electric current of 237.0 mA flows for 8.0 minutes. Calculate the amount of electric charge transported. Be sure your answer has the correct unit symbol and the correct number of significant digits x10

Answers

Answer:

amount of electric charge transported = 1.13 × $10^(-2)$ C

Explanation:

given data

electric current = 237.0 mA = 0.237 A

time = 8 min = 8 × 60 sec = 480 sec

solution

we get here amount of electric charge transported that is express as

amount of electric charge transported = electric current × time ...........1

put here value and we get

amount of electric charge transported = 0.237 × 480

amount of electric charge transported = 113.76 C

amount of electric charge transported = 1.13 × $10^(-2)$ C

A hot brass plate is having its upper surface cooled by impinging jet of air at temperature of 15°C and convection heat transfer coefficient of 220 W/m^2•K. The 10-cm thick brass plate (rho = 8530 kg/m^3, cp = 380 J/kg•K, k = 110 W/m•K, and α = 33.9×10^–6 m^2/s) has a uniform initial temperature of 900°C, and the bottom surface of the plate is insulated. Required:
Determine the temperature at the center plane of the brass plate after 3 minutes of cooling.

Answers

Answer:

809.98°C

Explanation:

STEP ONE: The first step to take in order to solve this particular Question or problem is to find or determine the Biot value.

Biot value = (heat transfer coefficient × length) ÷ thermal conductivity.

Biot value = (220 × 0.1)÷ 110 = 0.2.

Biot value = 0.2.

STEP TWO: Determine the Fourier number. Since the Biot value is greater than 0.1. Tis can be done by making use of the formula below;

Fourier number = thermal diffusivity × time ÷ (length)^2.

Fourier number = (3 × 60 × 33.9 × 10^-6)/( 0.1)^2 = 0.6102.

STEP THREE: This is the last step for the question, here we will be calculating the temperature of the center plane of the brass plate after 3 minutes.

Thus, the temperature of the center plane of the brass plane after 3 minutes = (1.00705) (0.89199) (900- 15) + 15.

= > the temperature of the center plane of the brass plane after 3 minutes = 809.98°C.

One kind of SS-3xX steel alloy has a melting point of 1450°c. Its specific heat = 0.46 J/g°C, and its heat of fusion 270 J/g. For a 200 kg block of this steel, determine how much heat is required to (a) raise its temperature from 25°C to its melting point and (b) transform it from solid to liquid phase.

Answers

Answer:

a)Q=131.1 MJ

b)Q=54 MJ

Explanation:

Given that

Mass ,m=200 kg

Specific heat Cp=0.46 J/g°C

Cp=0.46 KJ/kg°C

Heat of fusion = 270 J/g

Heat of fusion = 270 KJ/kg

Melting point temperature = 1450°C

Initial temperature = 25°C

Final temperature=1450°C

Heat required to rise temperature from 25°C to 1450°C.

Q= m CpΔT

Q=200 x 0.46 x (1450-25) KJ

Q=131,100 KJ

Q=131.1 MJ

Heat required to transform from solid phase to liquid phase

Q= Mass x heat of fusion

Q=200 x 27 KJ

Q=54,000 KJ

Q=54 MJ

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Technician A says that the unitized structure of a hybrid vehicle is considerably different when compared to the same conventional model.Technician B says that hybrid vehicles have 12-volt and high voltage batteries.Who is right?

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What are hybrid vehicle?

Related Questions

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Technician A says that the unitized structure of a hybrid vehicle is considerably different when compared to the same conventional model.Technician B says that hybrid vehicles have 12-volt and high voltage batteries.

Who is right?