ENGINEERING COLLEGE

The resultant force is directed along the positive x axis and has a magnitude of 1330 N. Determine the magnitude of F_A. Express your answer to three significant figures and include the appropriate units. Determine the direction theta of F_A. Express your answer using three significant figures.

Answers

Answer 1
Answer:

Answer:

the magnitude of F_A is 752 N

the direction theta of F_A is 57.9°

Explanations:

Given that,

Resultant force = 1330 N in x direction

∑Fx = R

from the diagram of the question which i uploaded along with this answer

FB = 800 N

FAsin∅ + FBcos30 = 1330 N

FAsin∅ = 1330 - (800 × cos30)

FA = 637.18 / sin∅

Now ∑Fx = 0

FAcos∅ - FBsin30 = 0

we substitute for FA

(637.18 / sin∅)cos∅ = 800 × sin30

637.18 / 800 × sin30 = sin∅/cos∅

and we know that { sin∅/cos∅ = tan∅)

so tan∅ = 1.59295

∅ = 57.88° ≈ 57.9°

THEREFORE FROM THE EQUATION

FA = 637.18 / sin∅

we substitute ∅

so FA = 637.18 / sin57.88

FA = 752 N

Related Questions

Yield and tensile strengths and modulus of elasticity . with increasing temperature. (increase/decrease/independent)
An interest buydown program offers to reduce interest rates by 4% from the base rate. Suppose the base rate for a loan of $8000 is 8% for 10 years. What is the monthly payment before and after the buydown? In this case, use monthly compounding, that is, the term is 120 payment periods, and the interest per month is 0.667% before and 0.333% after the buydown.
An automobile engine consumes fuel at a rate of 27.4 L/h and delivers 55 kW of power to the wheels. If the fuel has a heating value of 44,000 kJ/kg and a density of 0.73 g/cm3, deter- mine the efficiency of this engine in percentage(
A ___________ is defined as a change in shape of the part between the damaged and undamaged area hat is smooth and continuous. When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation
In contrasting the read-evaluation loop and the notification-based paradigm for inter- active programs, construction of a pre-emptive dialog was discussed. How would a programmer describe a pre-emptive dialog by purely graphical means? (Hint: Refer to the discussion in Sec- tion 8.5 concerning the shift from external and independent dialog management to presentation control of the dialog)

Calculate the amount of power (in Watts) required to move an object weighing 762 N from point A to point B within 29 seconds. Distance between point A and point B is 5.0 meters and they are at the same level. (Ignore the frictional losses)

Answers

Answer:

0.556 Watts

Explanation:

w = Weight of object = 762 N

s = Distance = 5 m

t = Time taken = 29 seconds

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

s=ut+(1)/(2)at^2\n\Rightarrow a=(2* (s-ut))/(t^2)\n\Rightarrow a=(2* (5-0))/(29^2)=(10)/(481)

Mass of the body

m=(w)/(g)=(762)/(9.81)

Force required to move the body

F=ma\n\Righarrow F=(762)/(9.81)* (10)/(481)

Velocity of object

v=u+at\n\Rightarrow v=0+(10)/(481)* 29\n\Rightarrow v=(10)/(29)

Power

P=Fv\n\Rightarrow P=(762)/(9.81)* (10)/(481)* (10)/(29)=0.556\ W

∴ Amount of power required to move the object is 0.556 Watts

The specific volume of mercury is .00007 m^3/Kg. What is its density in lbm/ft^3?

Answers

Answer:

891.027 lbm/ft³

Explanation:

See it in the pic

After the load impedance has been transformed through the ideal transformer, its impedance is: + . Enter the real part in the first blank and the imaginary part in the second blank. If a value is negative, include the negative sign. Provide up to four digits of precision. If the exact value can be provided with fewer digits, merely provide the exact value. These instructions pertain to the following blanks as well. What is the total impedance seen by the source? + . What is the current phasor Ig (expressed in rectangular form)?

Answers

Answer:

Ig =7.2 +j9.599

Explanation: Check the attachment

List the RTL (Register Transfer Language) sequence of micro-operations needed to execute the instruction STORE X

from the MARIE instruction set architecture. Then write the corresponding signal sequence to perform these micro-operations and to reset the clock cycle counter.

You may refer to the provided "MARIE Architecture and Instruction Set" file in the Front Matter folder.

Answers

Answer:

So these are the RTL representation:

MAR<----X

MBR<-----AC

M[MAR]<------MBR

Control signal sequence are:

P3T0:MAR<----X

P2P3 P4T1:MBR<-----AC

P0P1 P3T2:M[MAR]<------MBR

Explanation:

STORE X instruction is used for storing the value of AC to the memory address pointed by X. This operation can be done by using the Register Transfers at System Level and this can be represented by using a notation called Register Transfer Language RTL. Let us see what are the register transfer operations happening at the system level.

1. First of all the address X has to be tranfered on to the Memory Address Register MAR.  

MAR<----X

2. Next we have to tranfer the contents of AC into the Memory Buffer Register MBR

MBR<-----AC

3. Store the MBR into memory where MAR points to.

M[MAR]<------MBR

So these are the RTL representation:

MAR<----X

MBR<-----AC

M[MAR]<------MBR

Control signal sequence are:

P3T0:MAR<----X

P2P3 P4T1:MBR<-----AC

P0P1 P3T2:M[MAR]<------MBR

Which of the following results from the fact that skip signals refracted from the ionosphere are elliptically polarized?A. Digital modes are unusable

B. Either vertically or horizontally polarized antennas may be used for transmission or reception

C. FM voice is unusable

D. Both the transmitting and receiving antennas must be of the same polarization

Answers

Answer:

B

Explanation:

The fact that skip signals refracted from the ionosphere are elliptically polarized is a result of either vertically or horizontally polarized antennas may be used for transmission or reception.

A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.15 m2 and whose thickness is 5 mm. Treat the wall as a slab of the insulating material Styrofoam whose area and thickness are 10 m2 and 0.15 m, respectively. Heat is lost via conduction through the wall and the window. The temperature difference between the inside and outside is the same for the wall and the window. Of the total heat lost by the wall and the window, what is the percentage lost by the window

Answers

Answer:

The percentage loss of the window is  E = 97.3%

Explanation:

From the question we are told that

      The area of pane of glass is  A = 0.15 m^2

      The thickness is d = 5mm = (5)/(1000) = 0.005m

       The thickness of the wall is  D = 0.15m

       The area of the wall is  a = 10m^2

Generally the heat lost as a result of conduction of the window is  

              Q_(window) = (j_(glass) * A * (\Delta T) )/(d)

Where j_(glass) is the thermal conductivity of glass which has a constant value of

          j_(glass) = 0.80 J/(s \cdot m \cdot C^o)

 Substituting values

                 Q_(window) = ( 0.80 * 0.15 * (\Delta T) )/(0.005)

                 Q_(window) = 24 \Delta T

Generally the heat lost as a result of conduction of the wall is  

              Q_(wall) = (j_(styrofoam) * A * (\Delta T) )/(d)

j_(styrofoam) s the thermal conductivity of Styrofoam which has a constant value of  j_(styrofoam) = 0.010J / (s \cdot m \cdot C^o)

       Substituting values

                 Q_(wall) = ( 0.010 * 10 * (\Delta T) )/(0.15)

                 Q_(wall) = 0.667 \ \Delta T

Now the net loss of heat is

         Q_(net) = Q_(window) + Q_(wall)

  Substituting values

         Q_(net) = 24 + 0.667

         Q_(net) = 24.667

Now the percentage loss by the window is  

            E = (Q_(window) )/(Q_(net)) * 100

  Substituting value  

           E = (24)/(24 .667) * 100

           E = 97.3%
Other Questions
A technician has been dispatched to assist a sales person who cannot get his laptop to display through a projector. The technician verified the video is displaying properly on the laptop's built-in screen. Which of the following is the next step the technician should take?
IN JAVA,Knapsack ProblemThe file KnapsackData1.txt and KnapsackData2.txt are sample input filesfor the following Knapsack Problem that you will solve.KnapsackData1.txt contains a list of four prospective projects for the upcoming year for a particularcompany:Project0 6 30Project1 3 14Project2 4 16Project3 2 9Each line in the file provides three pieces of information:1) String: The name of the project;2) Integer: The amount of employee labor that will be demanded by the project, measured in work weeks;3) Integer: The net profit that the company can expect from engaging in the project, measured in thousandsof dollars.Your task is to write a program that:1) Prompts the user for the number of work weeks available (integer);2) Prompts the user for the name of the input file (string);3) Prompts the user for the name of the output file (string);4) Reads the available projects from the input file;5) Dolves the corresponding knapsack problem, without repetition of items; and6) Writes to the output file a summary of the results, including the expected profit and a list of the bestprojects for the company to undertake.Here is a sample session with the program:Enter the number of available employee work weeks: 10Enter the name of input file: KnapsackData1.txtEnter the name of output file: Output1.txtNumber of projects = 4DoneFor the above example, here is the output that should be written to Output1.txt:Number of projects available: 4Available employee work weeks: 10Number of projects chosen: 2Number of projectsTotal profit: 46Project0 6 30Project2 4 16The file KnapsackData2.txt, contains one thousand prospective projects. Your program should also be able to handle this larger problem as well. The corresponding output file,WardOutput2.txt, is below.With a thousand prospective projects to consider, it will be impossible for your program to finish in areasonable amount of time if it uses a "brute-force search" that explicitly considers every possiblecombination of projects. You are required to use a dynamic programming approach to this problem.WardOutput2.txt:Number of projects available: 1000Available employee work weeks: 100Number of projects chosen: 66Total profit: 16096Project15 2 236Project73 3 397Project90 2 302Project114 1 139Project117 1 158Project153 3 354Project161 2 344Project181 1 140Project211 1 191Project213 2 268Project214 2 386Project254 1 170Project257 4 427Project274 1 148Project275 1 212Project281 2 414Project290 1 215Project306 2 455Project334 3 339Project346 2 215Project356 3 337Project363 1 159Project377 1 105Project389 1 142Project397 1 321Project399 1 351Project407 3 340Project414 1 266Project431 1 114Project435 3 382Project446 1 139Project452 1 127Project456 1 229Project461 1 319Project478 1 158Project482 2 273Project492 1 142Project525 1 144Project531 1 382Project574 1 170Project594 1 125Project636 2 345Project644 1 169Project668 1 191Project676 1 117Project684 1 143Project689 1 108Project690 1 216Project713 1 367Project724 1 127Project729 2 239Project738 1 252Project779 1 115Project791 1 110Project818 2 434Project820 1 222Project830 1 179Project888 3 381Project934 3 461Project939 3 358Project951 1 165Project959 2 351Project962 1 316Project967 1 191Project984 1 117Project997 1 187
In response to the market revolution:the legal system worked with local governments to find better ways to regulate entrepreneurs.Chief Justice John Marshall ruled that legislatures could not alter or rescind charters and contracts that previous legislatures had created.local judges protected businessmen from paying property damages associated with factory construction and from workers seeking to unionize.Massachusetts Chief Justice Lemuel Shaw held in Commonwealth v. Hunt that workers had no right to organize.corporations proved less able to raise capital than chartered companies did.
Which of the following expressions causes an implicit conversion between types? Assume variable x is an integer, t is a float, and name is a string.Group of answer choices7.5 + (x / 2)x + 2 * x"Hello, " + str(name)print(str(t))