CHEMISTRY HIGH SCHOOL

In the following combustion reaction of acetylene (C2H2), how many liters of CO2 will be produced if 60 liters of O2 is used, given that both gases are at STP?2C2H2+5O2 2H2O+4CO2

The volume of one mole of gas at STP is 22.4 liters.

Answers

Answer 1
Answer: The stoichiometry of the reaction is 5 mols of O2 produces 4 mols of CO2.

1 mol at STP is equivalent to 22.4 liters.

So, 5*22.4 liters of O2 produces 4*22.44 liters of CO2

Then 60 liters of O2 produces 60*4/5 = 48 liters of CO2
Answer 2
Answer:

Final answer:

In the combustion reaction of acetylene (C2H2), 60 liters of CO2 will be produced if 60 liters of O2 is used.

Explanation:

To determine the volume of CO2 produced in the combustion reaction of acetylene (C2H2), we need to use stoichiometry. From the balanced equation, we can see that 2 moles of C2H2 produce 4 moles of CO2. The ratio is 2:4 or 1:2. Given that 60 liters of O2 is used, we can assume the same volume of CO2 will be produced since both gases are at STP.

Therefore, the volume of CO2 produced would be 60 liters as well.

Keywords: combustion, volume, acetylene, O2, CO2, STP

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Answers

Answer:

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Explanation:

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A triglyceride  is an ester derived from glycerol and three fatty acids. So not a saccharide. The other 3 options all are saccharides. Triglycerides are the main constituents of body fat.

Final answer:

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Explanation:

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Answers

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Answers

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Explanation:

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Give me brainliest plz

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Explanation:

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