Which is a unique feature of Mercury? A.
It is the only planet with permanent liquid water on its surface.

B.
It is the smallest planet and has the shortest period of revolution around the sun.

C.
The thick atmosphere—made mostly of carbon dioxide—absorbs solar radiation, heating up and helping make the atmosphere very hot.

D.
The planet’s surface is covered with red, iron-oxide dust

Answers

Answer 1
Answer: The correct answer is B. It is the smallest planet and has the shortest period of revolution around the sun. Among the 8 planets in the universe, mercury is the smallest and the closest to the sun. Because of this, mercury has a unique revolution of only 116 days, the fastest revolution among all the planets.

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You are using a calorimeter to calculate the specific heat capacity of a metallic ore. The calorimeter contains 0.50 kilograms of water at room temperature (22 °C). We heat the ore in boiling water and then drop the metal into the calorimeter and wait for the water and metal to reach the same temperature. The mass of the ore is 3.5 kilograms. We find that the water has increased in temperature to 24.3 °C. Recall that the specific heat of water is 4.18 J/g–°C. Calculate the specific heat capacity of the ore.

Ammonia and sulfuric acid react to form ammonium sulfate. Determine the starting mass of each reactant if 20.3 g of ammonium sulfate is produced and 5.89g of sulfuric acid remains unreacted.

Answers

Answer: The mass of ammonia is 5.236 g and that of sulfuric acid is 15.064 g

Explanation:

  • Calculating the mass of ammonia:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of ammonium sulfate = 20.3 g

Molar mass of ammonium sulfate = 132.14 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonium sulfate}=(20.3g)/(132.14g/mol)=0.154mol

The chemical equation for the reaction of ammonia and sulfuric acid follows:

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

As, sulfuric acid remains unreacted, which means it is an excess reagent and its starting mass cannot be determined from ammonium sulfate.

By Stoichiometry of the reaction:

1 mole of ammonium sulfate is produced by 2 moles of ammonia.

So, 0.154 moles of ammonium sulfate is produced by = (2)/(1)* 0.154=0.308mol of ammonia.

Now, calculating the mass of ammonia from equation 1, we get:

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 0.308 moles

Putting values in equation 1, we get:

0.308mol=\frac{\text{Mass of ammonia}}{17g/mol}\n\n\text{Mass of ammonia}=5.236g

  • Calculating the mass of sulfuric acid

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.  

This also means that total mass on the reactant side must be equal to the total mass on the product side.

Let the mass of sulfuric acid be 'x' grams

We are given:

Mass of ammonium sulfate = 20.3 grams

Mass of ammonia = 5.236 grams

Total mass on reactant side = 5.236 + x

Total mass on product side = 20.3 g

So, by applying law of conservation of mass, we get:

5.236+x=20.3\n\nx=15.064g

Hence, the mass of ammonia is 5.236 g and that of sulfuric acid is 15.064 g

2NH₃    +    H₂SO₄     ⇒     (NH₄)₂SO₄
34.06g  :     98.08g      :      132.14g
     x               y                 20.03g

x = [20.03g*34.06g]/132.14g = 5.16g

5.16g + y = 20.03g  ⇔  from stoichiometric ratio
20.03g - 5.16g = y
y = 14,87g + 5.89g = 20.76g  
⇔ 5.89g of sulfuric(VI) acid remains unreacted

Starting mass:

mNH₃ = 5.16g
mH₂SO₄ = 20.76g

Why do ionic compounds have high melitng points??

Answers

An ionic compound is arranged in a organised lattice structre that allows for the greatest electrostatic attraction between the opposite charged atoms and the lesser electrostatic repulsion between the same atoms, where the atoms are as closely packed as possible. So the amount of energy (in form of heat) needed to break the electrostatic attraction between the atoms, so this means that ionic compounds have very high melting points.
because of its bondsIonic bonds are very strong - a lot of energy is needed to break them. So ionic compounds have high melting and boiling points.

How many molecules are in 10 moles of Hydrogen?

Answers

Answer:3.2

Mass:32

Molecular weight: 10

Moles: 3.2

Which statement is true about BF3, a nonpolar molecule? It has nonpolar bonds and a symmetrical structure. It has nonpolar bonds and an asymmetrical structure. It has polar bonds and a symmetrical structure. It has polar bonds and an asymmetrical structure. It has ionic bonds and symmetrical structure.

Answers

I think the correct answer is the first option. It has nonpolar bonds and a symmetrical structure. The structure of a BF3 molecule shows a symmetrical trigonal geometry. The net dipole moment of the molecule is zero therefore it is polar.

Answer: It has polar bonds and a symmetrical structure.

Explanation:

Formula used  for calculating hybridization

:{\text{Number of electrons}} =(1)/(2)[V+N-C+A]

where, V = number of valence electrons present in central atom i.e. boron= 3

N = number of monovalent atoms bonded to central atom=3

C = charge of cation = 0

A = charge of anion = 0

BF_3

{\text{Number of electrons}} =(1)/(2)[3+3-0+0]=3

The number of electrons is 3 that means the hybridization will be sp^2 and the electronic geometry of the molecule will be trigonal planar.

Thus as there are no lone pair of electrons, there is no distortion and the molecule is symmetrical. The B-F bonds are polar due to electronegativity difference but the polarities cancel due to symmetrical structure.

What did Bohr’s model of the atom include that Rutherford’s model did not have?

Answers

What did Bohr’s model of the atom include that Rutherford’s model did not have?

The answer is energy levels

I think it's orbitals.
I'm pretty sure...

What determines the strength of a dipole dipole force?

Answers

Answer:

The more polar the molecules, the stronger the force. The more hydrogen in the molecule, the stronger the force.

Explanation:

I hope this helps and please ask if you need further help!