Which is evidence that scientists use to support the big bang theory? A.
There is constant cosmic background radiation.

B.
Galaxies are moving toward each other.

C.
A loud explosion can be heard in the radio frequencies everywhere in the universe.

D.
Hydrogen and helium are the most abundant elements in the universe.

Answers

Answer 1

Answer: The right answer for the question that is being asked and shown above is that: "C. A loud explosion can be heard in the radio frequencies everywhere in the universe." The evidence that scientists use to support the big bang theory is that A loud explosion can be heard in the radio frequencies everywhere in the universe.

Related Questions

The ratio of oxygen to carbon by mass in carbon monoxide is 1.33:1.00. part a find the formula of an oxide of carbon in which the ratio by mass of oxygen to carbon is 2.00:1.00.
Moving ________ create a magnetic field.a. protons b. electrons c. poles d. neutrons
A solution with a ph of 2.0 has a hydrogen ion concentration ten times greater than a solution with a pha. 1.0 b. 3.0 c. 0.20 d. 20
Changes in color , energy, and odor are indications that a
PLEASE HELP!! Perform the followingmathematical operation, andreport the answer to theappropriate number ofsignificant figures.5.1 – 2.3685 = [?]

What tendency is the standard reduction potential of an element based on?

Answers

The tendency of the standard reduction potential of an element is to be reduced and is based on the measurement of volts at standard conditions. The more positive the standard potential of an element, the more it is reduced

Which compound has the highest percent composition by mass of strontium?(1) SrC12 (2) SrI2 (3) SrO (4) SrS

Answers

The answer is (3). The number of Sr is the same so if the compound has the smallest gram formula mass, it has the highest percent composition by mass of strontium. So the answer is (3).

Answer: option (3) SrO, with 84.56%

Explanation:

You have to calculate the mass of strontium and the mass of the compound, for each of the four compounds, and compute the percent:

percent of strontium = (mass of strontium / mass of the chemical formula) × 100 %.

These are the atomic masses of the elements that you have to use:

Atomic mass of Sr: 87.62 g/mol

Atomic mass of Cl: 35.453 g/mol

Atomic mass of I: 126.904 g/mol

Atomic mass of O: 15.999 g/mol

Atomic mass of S: 32.065 g/mol

(1) SrCl₂:

i) mass of Sr: 87.62 g/mol

ii) mass of Cl₂: 2×35.453 g/mol = 70.906 g/mol

iii) mass of SrCl₂: 87.62 g/mol + 70.906 g/mol = 158.526 g/mol

iv) Sr % = [87.62 / 158.526 ] × 100 = 55.27%

(2) SrI₂

Following the same procedure:

i) Sr % = [87.62 / (87.62 + 2× 126.904) ] × 100 = 25.66%

(3) SrO

i) Sr % = [87.62 / (87.62 + 15.999) ] × 100 = 84.56%

(4) SrS

i) Sr % = [87.62 / (87.62 + 32.065) ] × 100 = 73.21%

Which metal is more active than H2?
(1) Ag (3) Cu
(2) Au (4) Pb

Answers

Answer is (4) - Pb.

According to the reactivity series of elements

- the elements which are above the hydrogen are more reactive than hydrogen.

- the elements which are below the hydrogen are less reactive than hydrogen.

Among the given choices, only Pb is placed above the hydrogen in the reactivity series and rest are below the hydrogen.

Hence, Pb is more active than hydrogen.

A sample originally contained 1.28 g of a radioisotope. It now contains 1.12 g of its daughter isotope. How many half-lives have passed since the sample originally formed?

3
4
8
16

Answers

The answer is 3.

The relation between number of half-lives (n) and decimal amount remaining (x) can be expressed as:

$(1/2) ^(n) =x$

We need to calculate n, but we need x to do that. To calculate what percentage of a radioactive species would be found as daughter material, we must calculate what amount remained:
1.28 - 1.12 = 0.16

If 1.28 is 100%, how much percent is 0.16:
1.28 : 100% = 0.16 : x
x = 12.5%
Presented as decimal amount:
x = 0.125

Now, let's implement this in the equation:

$(1/2) ^(n) =0.125$

Because of the exponent, we will log both sides of the equation:
$n * log(1/2) = log(0.125)$
$n = (log(0.125))/(log(1/2))$
$n = (log(0.125))/(log(0.5))$
$n= (-0.903)/(-0.301)$
$n = 3$

Therefore, 3 half-lives have passed since the sample originally formed.

Answer:

Explanation:

What is meant by a pure substance? Name two pure substances.

Answers

Answer:

Explanation:

A pure substance is a substance that consists of only one type of particle, either atoms, molecules, or ions, and has a consistent and uniform composition throughout. Pure substances cannot be separated into other substances by physical means. They have well-defined chemical properties and distinct physical properties, such as melting point and boiling point.

Two examples of pure substances are:

Elemental Hydrogen (H2): Elemental hydrogen consists of diatomic molecules, each containing two hydrogen atoms bonded together. It is a pure substance because it consists only of hydrogen molecules and cannot be separated into other substances without chemical reactions.

Water (H2O): Water is a pure substance composed of water molecules, each consisting of two hydrogen atoms and one oxygen atom bonded together. It is also a pure substance because it has a consistent and uniform composition throughout and cannot be separated into other substances without breaking its molecular bonds.

These examples illustrate the concept of pure substances, where the composition is homogeneous and consistent throughout the entire sample.

A protein denatures when you cook it at 60°C. What is that temperature on the Kelvin scale?

Answers

Kelvin = Celsius + 273
60°C +273 = 333 K

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Which of the following sets of characteristics describe what we know about the inner planets?Select one: a. They are closest to the sun, have many moons, and include ring systems. b. They are closest to the sun, have many moons, and include ring systems. c. They have rocky surfaces, no rings, and few or no moons. d. They have rocky surfaces, ring systems, and are larger in size.

The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a) empirical formula mass / molecular mass = n B) molecular mass = element mass / empirical formula mass ´ 100 c) subscript of H in empirical formula = 2 subscript of H in molecular formula D) subscript of C in molecular formula = n subscript of C in empirical formula

Which process requires an external power source?(1) neutralization (3) fermentation(2) synthesis (4) electrolysis

Which statement correctly describes diamond and graphite, which are different forms of solid carbon?(1) They differ in their molecular structure, only.(2) They differ in their properties, only.(3) They differ in their molecular structure and properties.(4) They do not differ in their molecular structure or properties.