Joseph, a supervisor at H2O Chemicals Inc., needs to assess the behavior of 25 people, who constitute a large group of his subordinates. Which of the following methods combines ease of use with objectivity and a basis for providing feedback?
Answers
Answer:
behavioral observation scale
Explanation:
According to my research on different methods for providing feedback, I can say that based on the information provided within the question Joseph should use a behavioral observation scale. This feedback method measures the level of performance and frequency of certain behaviors. In this situation this feedback method would be the easiest and most accurate method of providing feedback.
**Even though no answer choices were provided this method is the most used in these types of situations.**
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Answers
Answers
Its molecular formula : C₆H₁₂O₆
Further explanation
The empirical formula(EF) is the smallest comparison of atoms of compound forming elements.
A molecular formula(MF) is a formula that shows the number of atomic elements that make up a compound.
(EF) n = MF
its empirical formula is CH₂O
CH₂O : 12+2+16=30
Answer:
C. C6H12O6
Explanation:
For edge(:
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1 mol ----- 18.0 g
3.5 moles --- ?
Mass ( H₂O) = 3.5 x 18.0 / 1
=> 63.0 g
hope this helps!
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Answer: Not determine their exact position.
Explanation: In the electron cloud model, electrons are said to be moving so fast that a person cannot determine their exact position.
This phenomenon goes well off with the Heisnberg Uncertainity Principle (HUP)which states that the momentum (Δm) and position (Δx) of an obejct cannot be determined simultaneously at the same time.
The mathematical relation of HUP is -
Δx Δm ≥ h/ 4π
where h = Planck's Constant
Answers
Cl₂ = 71.0 g/mol Na = 23.0 g/mol
2 Na + Cl₂ = 2 NaCl
2 x 23 g Na -------> 71.0 g Cl₂
96.6 g Na ----------> ?
Mass Cl₂ = ( 96.6 x 71.0 ) / ( 2 x 23 )
Mass Cl₂ = 6858.6 / 46
= 149.1 g of Cl₂
hope this helps!
Answers
Answer:
The answer to your question is 2.84 M
Explanation:
Data
mass of MgO = 57.3 g
volume of the solution = 500 ml
Process
1.- Calculate the molar mass of MgO
MgO = 24.3 + 16 = 40.3 g
2.- Calculate the moles of MgO
40.3 g MgO ----------------- 1 mol
57.3 g MgO ----------------- x
x = (57.3 x 1) / 40.3
x = 1.42 moles
3.- Calculate the Molarity
Molarity = moles / volume (l)
Volume = 0.5 liters
-Substitution
Molarity = 1.42 / 0.5
-Result
Molarity = 2.84
Final answer:
The molarity of the solution is 2.84 M.
Explanation:
To find the molarity of the solution, we need to first calculate the number of moles of MgO and the volume of the solution.
First, we convert the mass of MgO to moles using its molar mass. The molar mass of MgO is 40.31 g/mol, so:
moles of MgO = mass of MgO / molar mass of MgO
moles of MgO = 57.3 g / 40.31 g/mol = 1.42 mol
Next, we convert the volume of the solution to liters:
volume of solution = 500.0 mL / 1000 mL/L = 0.500 L
Finally, we divide the number of moles of MgO by the volume of the solution to find the molarity:
molarity = moles of solute / volume of solution
molarity = 1.42 mol / 0.500 L = 2.84 M
Learn more about Molarity here:
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