A bicycle moves with a speed of 6 km/h for 2 hour and the speed of 4 km/h for the next 3 hours .find the average speed and the distance traveled?
Answers
Answer:
4.8 km/h
24 km
Explanation:
The distance traveled is:
d = (6 km/h) (2 h) + (4 km/h) (3 h)
d = 24 km
The average speed is distance divided by time:
s = (24 km) / (5 h)
s = 4.8 km/h
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b. the distance a spring stretches has nothing to do with how much force is applied to it.
c. as the force on a spring increases, the distance it stretches increases.
d. as the force on a spring increases, the distance it stretches decreases.
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Answer: option c. as the force on a spring increases, the distance it stretches increases.
Explanation:
Hooke's Law relates the force (F) applied on the spring and extension (x) of the spring:
F = - k x
Where, k is the spring constant.
as the force on a spring increases, the distance it stretches increases but it is limited by its elastic limit. The negative sign means that spring force is a restoring force which means that the stretch of the spring is in opposite direction to force.
c. as the force on a spring increases, the distance it stretches increases
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Answers
At a height of 3.2 meters, the final speed of the model rocket is 26.05 m/s.
Given the following data:
- Initial speed = 0 m/s (since the model rocket accelerated from rest).
- Acceleration = 106
- Distance (height) = 3.2 meters.
To find the final speed of the model rocket, we would use the third equation of motion;
Where:
- V is the final speed.
- U is the initial speed.
- a is the acceleration.
- S is the displacement or distance covered.
Substituting the given parameters into the formula, we have;
Final velocity, V = 26.05 m/s
Read more: brainly.com/question/8898885
We can solve the problem by using the following equation:
where
vf is the final speed of the rocket
vi=0 is the initial speed of the rocket (it starts from rest)
is the rocket's acceleration
S=3.2 m is the distance covered by the rocket
Re-arranging the equation, we find the velocity of the rocket after 3.2 m: