What happens in a chain reaction

Answers

Answer 1

Answer:

Answer: Neutrons released act as reactants in next reaction.

Explanation:

Nuclear chain reactions occur in fission reactions only. Nuclear fission reactions are defined as the reactions in which larger nuclide splits into two or more smaller daughter nuclides.

In nuclear chain reaction, the neutrons that are released in the previous fission reaction act as the starting material in the next reaction. Thus, this process continues to many reactions and hence, is known as nuclear chain reaction.

For Example: Uranium-235 on bombardment of 1 neutron undergoes fission reaction producing 3 neutrons and a huge amount of energy. The reaction follows:

$_(92)^(235)\textrm{U}+_0^1n\rightarrow 3_0^1n+_(36)^(92)\textrm{Kr}+_(56)^(141)\textrm{Ba}+\text{energy}$

Hence, neutrons released act as reactants in next reaction.

Answer 2

Answer: Hi there! A nuclear fission is a chain reaction. What happens in a food chain is that a uranium-235, which is a atom absorbs a neutron, and then it fissions into two new atoms. Which then releases three new neutrons and a lot of binding energy.

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Which element has the greatest density at STP?(1) scandium (3) silicon
(2) selenium (4) sodium

Answers

Answer:

Selenium has the greatest density at STP.

Explanation:

According to Ideal gas equation,

P V = n R T

where;

n = m/M

Therefore,

P V = m R T / M

Rearranging,

P M = (m/V) R T

Also,

m/V = density = d

So,

P M = d R T

Solving for density,

d = P M / R T

According to this equation density is directly proportional to Molar mass of a substance. Hence, the Atomic masses of given compounds are listed below,

Scandium = 44.96 g.mol⁻¹

Selenium = 78.97 g.mol⁻¹

Silicon = 28.09 g.mol⁻¹

Sodium = 22.99 g.mol⁻¹

Therefore, selenium having the greatest Atomic Mass will have the greatest density. The densities of given elements are as follow;

Scandium = 2.98 g.cm⁻³

Selenium = 4.81 g.cm⁻³

Silicon = 2.33 g.cm⁻³

Sodium = 0.96 g.cm⁻³

$\boxed{\left( 2 \right){\text{ Selenium}}}$ has the greatest density at STP.

Further Explanation:

Ideal gas law is the equation of state for any hypothetical gas. The expression for the ideal gas equation is as follows:

${\text{PV}} = {\text{nRT}}$ …… (1)

Here,

P is the pressure.

V is the volume.

T is the absolute temperature.

n is the number of moles.

R is the universal gas constant.

The formula to calculate the number of moles is as follows:

${\text{n}}=\frac{{\text{m}}}{{\text{M}}}$ ...... (2)

Here,

n is the number of moles.

m is the mass.

M is the molar mass.

Substitute the value of n from equation (2) in equation (1).

${\text{PV}} = \frac{{{\text{mRT}}}}{{\text{M}}}$ …… (3)

Rearrange equation (3) as follows:

${\text{PM}} = \frac{{{\text{mRT}}}}{{\text{V}}}$ …… (4)

The formula to calculate density is as follows:

${\rho }} = \frac{{\text{m}}}{{\text{V}}}$ ...... (5)

Here,

${\rho }}$ is the density.

m is the mass.

V is the volume.

Substitute equation (5) in equation (4).

${\text{PM}} = \rho{\text{RT}}$ …… (6)

Rearrange equation (6) to calculate the density.

${\rho }} = \frac{{{\text{PM}}}}{{{\text{RT}}}}$ ...... (7)

At STP, T and P remain constant, R is already a constant. So according to equation (7), density of substance is directly proportional to the molar mass of the substance.

The molar mass of scandium is 44.96 g/mol.

The molar mass of selenium is 78.97 g/mol.

The molar mass of silicon is 28.09 g/mol.

The molar mass of sodium is 22.99 g/mol.

The molar mass of selenium is the highest among the given elements so its density will be the greatest.

Learn more:

1. Which statement is true for Boyle’s law: brainly.com/question/1158880

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: P, V, n, R, T, ideal gas, pressure, volume, selenium, sodium, scandium, silicon, 22.99 g/mol, 78.97 g/mol, 28.09 g/mol, 44.96 g/mol, density, molar mass.

What form of energy provides power for a gas stove?A.nuclear energy
B.electrical energy
C.chemical energy
D.sound energy

Can you explain the answer for me ?

Answers

C . chemical energy will be the answer. In a gas stove, LPG is stored and it is brought out and it reacts with oxygen to give out heat energy. all the other options are not convincing and hence chemical energy is the best answer.

The compound before the arrow are called blank and the compound after the arrow are called blank

Answers

First one is reactants and then second one is products

Contrast the lithosphere and the asthenosphere

Answers

The lithosphere is the hard, externel section of Earth, it includes the crust of Earth. The asthenosphere is underneath the lithosphere, & it is weak, unlike the lithosphere which is solid.

Consider the following reaction: 2HCl + Ca(OH)2 CaCl2 + 2H2O A scientist wants to neutralize 25 mL of 0.001 M Ca(OH)2 with a volume of 0.005 M HCl. What is the minimum volume of HCl required?

Answers

The balanced chemical equation for the above reaction is as follows ;
Ca(OH)2 + 2HCl —> CaCl2 + 2H2O
Stoichiometry of Ca(OH)2 to HCl is 1:2
Number of Ca(OH)2 moles present - 0.001 mol/L / 1000 mL/L x 25 mL
Number of Ca(OH)2 moles = 2.5 x 10^(-5) mol
Number of HCl moles needed for neutralisation = 2.5 x 10^(-5) mol x2 = 5 x 10 ^(-5) mol
The molarity of HCl solution is 0.005 M
The solution contains 0.005 mol in 1000 mL
Therefore volume of 5x10^(-5) mol in = 1000/0.005 x 5 x 10^(-5) mol = 10 mL
10 mL of HCl is needed for neutralisation

How many moles are in 68.5 liters of oxygen gas at STP?

Answers

We can solve this problem when we use the conditions of a gas at standard temperature and pressure. It has been established that at STP where the temperature is 0 degrees Celsius and the pressure is 101.325 kPa, the volume of 1 mole of gas is 22.4 L. We will use this data for the calculations.

68.5 L ( 1 mol O2 / 22.4 L O2 ) = 3.06 mol O2

Explanation:

It is known that at STP, there are 22.4 L present in one mole of a substance.

Therefore, in 68.5 liters there will be 1 mol divided by 22.4 L times 68.5 L.

Mathematically, $68.5 L * (1 mol O_(2))/(22.4 L)$

= 3.05 mol

Hence, we can conclude that there are 3.05 moles present in 68.5 liters of oxygen gas at STP.

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