CHEMISTRY HIGH SCHOOL

Which will cause a decrease in gas pressure in a closed containerA) Reducing the volume
B) Adding more gas
C) Lowering the temperature

Answers

Answer 1

Answer: By lowering the temps, there is a decrease in the pressure inside. so C.

Answer 2

Answer:

Answer: C, Lowering the temperature

Explanation: Gradpoint

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Which of the following compounds will experience dipole-dipole forces of attraction? Cl2
NaCl
H2S
C2H4

Answers

NaCl and H2S will experience dipole-dipole interaction because they are permanently polarized.

NaCl and H2s are the answers

List the different types of fuel that are made from crude oil

Answers

well there are quite a few so ima going to give you like four Finished motor gasoline,Distillate fuel,Kerosene-type jet fuel3, and coke

9Ammonia is manufactured from nitrogen and hydrogen by the Haber process.
N2(g) + 3H2(g)2NH3(g)
What is the percentage yield when 60 kg of ammonia is produced from 60 kg of hydrogen?
A
5.9%
B
17.6%
с
35.3%
D
50.0%

Answers

Answer:

17.6%

Explanation:

1. Percentage yield = (Actual yield/theoretical yield) x 100

2. You know actual yield of ammonia (60kg) so you need to work out theoretical yield.

3. mols of hydrogen = m/mr = 60,000/2 = 30,000 mols.

4. 3:2 ratio so (30,000/3) x 2 = 20,000 mols of Ammonia.

5. Therefore mass of ammonia = mr x mols = 20,000 x 17 = 340,000 grams

6. So percentage yield is (60,000/340,000) x 100 = 17.6

An enzyme is a catalyst used by living things to promote and regulate chemical reactions. What is the most likely enzyme for the chemical reaction depicted below? A. Catalyst A
B. Catalyst B
C. Catalyst C
D. Catalyst D

Answers

Answer:

B. Catalyst B

Explanation:

Explanation: Enzymes are complex proteins that have a very specific shape. Just as a key fits a lock and allows it to open, the active site of the enzyme fits the reactants, allowing them to meet at the right orientation to form new chemical bonds. The shape of catalyst B is the best fit to the given reactants and product. The presence of catalysts allows reactions to proceed at much lower energy levels than without, as high-energy collisions between molecules are no longer necessary.

The following three solutions are mixed: 100.0mL of 0.100M Na₂SO₄, 50.0mL of 0.300M ZnCl₂, and 100.0mL of 0.200M Ba(CN)₂. Cyanide (CN-) solubilities are not in most tables, but Ba(CN)₂ is soluble, Zn(CN)₂ is not. a. What ionic compounds will precipitate out of solution? b. What is the molarity of each ion remaining in the solution, assuming complete precipitation of all insoluble compounds, and assuming that volumes are additive?

Answers

a. To determine the ionic compounds that will precipitate out of solution, we need to consider the solubility rules. According to the solubility rules:

1. All sodium (Na+) salts are soluble, so Na₂SO₄ will remain in solution.
2. Zinc (Zn2+) salts are generally soluble, except for zinc sulfide (ZnS) and zinc hydroxide (Zn(OH)₂). However, in this case, we are adding ZnCl₂ to the solution, which contains chloride (Cl-) ions. Chloride ions form soluble salts with most cations, including Zn2+. Therefore, ZnCl₂ will remain in solution.
3. Barium (Ba2+) salts are generally soluble, except for barium sulfate (BaSO₄) and barium carbonate (BaCO₃). However, in this case, we are adding Ba(CN)₂ to the solution, which contains cyanide (CN-) ions. Cyanide ions form insoluble salts with most cations, including Ba2+. Therefore, Ba(CN)₂ will precipitate out of solution as Ba(CN)₂ is not soluble.

b. Assuming complete precipitation of all insoluble compounds and that volumes are additive, we can calculate the molarity of each ion remaining in the solution.

For Na₂SO₄:
- Sodium (Na+) ion concentration: 2 * 0.100 M = 0.200 M
- Sulfate (SO₄2-) ion concentration: 0.100 M

For ZnCl₂:
- Zinc (Zn2+) ion concentration: 0.300 M
- Chloride (Cl-) ion concentration: 2 * 0.300 M = 0.600 M

For Ba(CN)₂:
- Barium (Ba2+) ion concentration: 0.200 M
- Cyanide (CN-) ion concentration: 2 * 0.200 M = 0.400 M

Therefore, the molarity of each ion remaining in the solution, assuming complete precipitation of all insoluble compounds and that volumes are additive, are as follows:
- Sodium (Na+) ion: 0.200 M
- Sulfate (SO₄2-) ion: 0.100 M
- Zinc (Zn2+) ion: 0.300 M
- Chloride (Cl-) ion: 0.600 M
- Barium (Ba2+) ion: 0.200 M
- Cyanide (CN-) ion: 0.400 M

List the four components of natural gas in order of increasing strength of intermolecular forces.