what is the concentration, in percent (v/v), of a solution containing 50 mL of diethyl ether (C4H10O) in 2.5 L of solution?
Answers
Answer: The v/v in percent of diethyl ether in a solution is 2%.
Explanation:
To calculate the percentage volume by volume of a solute in a solution, we use the formula:
We are given:
Volume of solute = 50 mL
Volume of solution = 2.5 L = 2500 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
Hence, the v/v in percent of diethyl ether in a solution is 2%.
Volume of solution = 2.5 L x 1000 = 2500 mL
( V / V ) = ( 50 / 2500 ) x 100
( V/ V) =0.02 x 100 = 2.0 %
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Answer:
Every homogeneous mixture is uniform in nature.
Explanation:
One of the most interesting facts about homogeneous mixtures is that, in a sense, there's no real distinction. The mixture is uniform in nature.
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Hope this helps :D
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Final answer:
Blue light is emitted when an electron in a He+ ion falls from the energy level n=4 to n=1. This is because the energy difference between these levels is similar to that in a hydrogen atom when blue light is emitted (from n=5 to n=2).
Explanation:
The energy of the emitted photon when an electron transitions between energy levels in an atom is determined by the difference between the energy levels it transitions between. This is described by the formula: E = hν, where E stands for energy, h stands for Planck's constant, and ν stands for frequency. The color of the emitted light, or the wavelength, is determined by the energy of the photon.
For blue light to be emitted when an excited electron falls from n=4 in a He+ ion, it must fall into n=1. This is because the energy gap between the n=4 and n=1 levels in a He+ ion is similar to that between the n=5 and n=2 levels in a hydrogen atom, which results in the emission of blue light.
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Final answer:
In a helium ion (He+), an electron would need to fall from n=4 to n=1 to emit a photon of blue light, similar to the photon emitted when an electron in a hydrogen atom falls from n=5 to n=2.
Explanation:
According to the Bohr model of atoms, when an electron falls from a higher to a lower energy level, a photon is emitted. The energy (and therefore color) of the photon corresponds to the energy difference between the two energy levels. In the case of your question, an excited electron in a hydrogen atom falls from n=5 to n=2 and emits a photon of blue light.
If an electron in an excited helium ion (He+) falls from the n=4 level, to emit a photon of similar energy (and thus color), it must fall to a level that yields a similar energy difference. Based on the energy levels of helium and hydrogen, the electron in the He+ ion would need to fall to n=1 to emit a photon of similar energy to the blue light from the hydrogen atom, given that the energy difference in He+ ion is larger than in hydrogen atom for the same quantum numbers due to its greater nuclear charge.
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