What mass of K2SO4 would you need to prepare 1500g of 5.0% K2SO4 (m/m) solution?

Answers

Answer 1

Answer:

To solve this we must be knowing each and every concept related to mass. Therefore, mass of K $_2$ SO $_4$ would you need to prepare 1500g of 5.0% K $_2$ SO $_4$ (m/m) solution is 75 g.

What is mass?

Mass defines the quantity of a substance. It is measured in gram or kilogram. Average mass is the mass of atoms of an element that are isotopes. It can be calculated by multiplying mass of a isotope to natural abundance of that isotope.

Mass of solution = 1500 g

5.0 % = 5.0 / 100 = 0.05

mass percentage = mass of solute / mass of solution

substituting all the given values in the above equation, we get

0.05 = mass of solute / 1500

mass of solute = 0.05 x 1500

mass of solute = 75 g of solute

Therefore, mass of K $_2$ SO $_4$ would you need to prepare 1500g of 5.0% K $_2$ SO $_4$ (m/m) solution is 75 g.

To learn more about mass, here:

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Answer 2

Answer: Mass of solute = ?

Mass of solution = 1500 g

5.0 % = 5.0 / 100 = 0.05

w = mass of solute / mass of solution

0.05 = ? / 1500

w = 0.05 x 1500

w = 75 g of solute

hope this helps!

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