If the system 2CO(g)+O2(g) 2CO2(g) has come to equilibrium and then more CO(g) is added,

Answers

Answer 1

Answer: If more CO is added the reaction will shift to the right and produce more products to maintain the equilibrium constant. This can be explained through Le Chatlier principles. I hope this helps. Let me know if anything is unclear.

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What element forms a compound with chlorine with the general formula MCl?
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Based on relative bond strengths, classify these reactions as endothermic or exothermic.

l. Given the balanced equation representing a reaction:What occurs during this reaction?1) Energy is absorbed as bonds are broken.2) Energy is absorbed as bonds are formed.3) Energy is released as bonds are broken4) Energy is released as bonds are formed.

Answers

1) energy is absorbed and bonds are broken

This is due to two reasons
1. The breaking of bonds requires and input energy. The formation of bonds is a release on energy. As bond breaking requires energy, it is only natural that once of the answers would involve the absorption of energy.
2. O2 is the covalent bond between two oxygen molecules. When these molecules are separated the bond is broken. As such the answer must be 1

I hope this helps

What is the chemical formula for zinc carbonate?(1) ZnCO3(2) Zn(CO3)2
(3) Zn2CO3
(4) Zn3CO3

Answers

The chemical formula for Zinc Carbonate is ZnCO3.

What is the name of the compound with the chemical formula (NH4)2S?A. ammonium sulfide
B. hydrogen sulfate
C. sulfur hydride
D. sulfuric acid

Answers

NH₄⁺ - ammonium cation
S²⁻ - sulfide anion

(NH₄)₂S - ammonium sulfide
The answer is A.

Final answer:

The compound with the chemical formula (NH4)2S is ammonium sulfide. This name signifies the presence of two ammonium ions and a single sulfide ion in the compound.

Explanation:

The compound with the chemical formula (NH4)2S is ammonium sulfide. In this compound, there are two ammonium ions (NH4) for every sulfide ion (S2-). The positive charge of the two ammonium ions balances the negative charge of the sulfide ion, forming a neutral compound. The prefixes and suffixes in the name of the compound indicate the elements present and their ratios.

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Which list of elements is arranged in order of increasing atomic radii?(1) Li, Be, B, C (3) Sc, Ti, V, Cr(2) Sr, Ca, Mg, Be (4) F, Cl, Br, I

Answers

Elements which are arranged in increasing order of atomic radii are F,Cl,Br, I.

What is atomic radius ?

Atomic radius is defined as the distance between nucleus of an atom and the valence electrons.In a group, atomic radii increases up to down as electrons are added in the next successive shell which increases the size of atom.

In a period, as electrons are added to the same shell the force of attraction between nucleus and valence electrons increases as a result of which atom tend to shrink resulting in decrease in atomic size.

As fluorine, chlorine, bromine and iodine are present in the same group their atomic size increases as new shells are added from top to bottom of periodic table., while for the elements given in other options they are present in same period or in different group and hence do not show an gradual increase in atomic radii.

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Answer: F,Cl,Br,l

Explanation:these elements are all part of group 17

How many grams of calcium bromide are in 50.0 mL of a 0.25 M calcium bromide solution?

Answers

The mass of the compound can be calculated by the molarity. The mass of the calcium bromide in the given solution is 2.5 g.

The mass of the given compound can be calculated by the molarity formula,

$\bold {M = \frac {w}{m* v} * 1000}\n\n\bold {w = \frac {M* m* v}{ 1000}}$

Where,

M- molarity of the solution = 0.25 M

w - given mass =?

m -molar mass of Calcium bromide = 200 g/mol

v-volume in mL= 50 mL

Put the values in the formula,

$\bold {w = \frac {0.25* 200* 50}{ 1000}}\n\n\bold {w = 2.5\ g}$

Therefore, the mass of the calcium bromide in the given solution is 2.5 g.

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$C_(m)=(n)/(V_(r))\n\nm=(m)/(M)\n\nC_(m)=(m)/(MV_(r)) \ \ \ \ \Rightarrow \ \ \ \ m=C_(m)MV_(r)}\n\nC_(m)=0.25(mol)/(L)\nM_{CaBr_(2)}=200(g)/(mol)\nV_(r)=50mL=0.05L\n\nm=0.25(mol)/(L)*200(g)/(mol)*0.05L= \emph{\textbf{2.5g}}$

In the early 1880s, the British Scientist John Dalton worked to find the atomic mass of several common elements.How could knowing the atomic mass of an element help a chemist do his or her work?

A. The atomic mass could be used to convert that element into another element.

B. The atomic mass could be used to identify an element.

C. The atomic mass could be used to calculate the number of isotopes formed by the element.

Answers

C. The atomic mass could be used to calculate the number of isotopes formed my the element.

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