Which of the following types of radiation has the greatest ability to penetrate matter

Answers

Answer 1
Answer: You did not specify the types, but I believe the answer would be gamma radiation.
Answer 2
Answer:

Final answer:

Among alpha,beta, neutron, and gamma radiations, gamma radiation has the greatest ability to penetrate matter. It can pass through dense and thick materials, including a few feet of concrete and even lead.

Explanation:

When comparing the ability of different types of radiation to penetrate matter, from least penetrating to most penetrating, the sequence is alpha < beta < neutron < gamma. This means the gamma radiation is the most penetrating type of radiation. Alpha radiation has the least penetration ability and can be blocked by even a thin sheet of paper. Beta radiation has slightly higher penetration power, able to go through about 3mm of aluminum, for instance. Gamma radiation, on the other hand, can penetrate much denser and thicker materials. For example, high-energy gamma radiation can pass through a few feet of concrete, and even lead to a depth of 2 or more centimeters.

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What is the frequency of an event?Group of answer choices

Probability

Degree

Expected occurrence

Identification

Answers

Answer:

Probability

Explanation:

Final answer:

The frequency of an event is a measure of how often the event occurs within a given time period.

Explanation:

The frequency of an eventrefers to how often the event occurs within a given time period. It is a measure of the rate at which the event happens. Frequency can be calculated by dividing the number of times the event occurs by the total time period. Probability, on the other hand, is a measure of the likelihood of an event happening.

For example, if a student attends class 4 days a week, the frequency of attending class is 4/7 or 0.57. Probability, on the other hand, refers to the likelihood of an event occurring. It is a measure of the chances of the event happening. Probability is expressed as a number between 0 and 1, where 0 means the event will not happen and 1 means the event will definitely happen.

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Calculate the number of oxygen atoms in 2.00 moles of Mn2O7

Answers

first you should know that there is seven oxygen atoms in one Mn2O7
So 
2.00 moles of Mn2O7 contain 14.00 moles of oxygen...
Then you multiply this no. with Avagadro no....
from formula
Number of moles= no. of particles/avagadro's no..
14.00×6.02×10²³=84.28 atoms of oxygen... 

What is heat?
(in scientific vocab)

Answers

my guess i dont know exactly but heat is energy

heat absorbed or radiated during a change of phase at a constant temperature and pressure. specific heat. the heat required to raise the temperature of one gram of a substance one degree centigrade. heat of condensation. heat liberated by a unit mass of gas at its boiling point as it condenses into a liquid.

Argon-39 has a half-life of 269 years. How long will it take for 52.5 g of a 60.0 g sample to decay to its daughter isotope?

Answers

The years that will take or 52.5 g of a 60.0 g sample to decay to its daughter isotope is 807 years.

What is half-life?

Half-life is the time required to decay or undergo half the process of any element.

Given the sample is 60.0 g in which 52.5 g sample has to be decay

so, 60 - 52.5 = 7.5 g

It can be seen that it goes three half life

60 >30 >15 >7.5

Now, the half life is 269

269 × 3 = 807 years.

Thus, the years taken are 807 years.

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For 60.0 g sample, if it remains 60-52.5=7.5 g, it will go through 60->30->15->7.5, 3 half-life. So the time being taken is 269*3=807 years.

A closed system initially containing 1×10^-3M H2 and 2×10^-3 at 448°C is allowed to reach equilibrium. Analysis of the equilibrium mixture show s that the concentration of HI is 1.87×10^ -3. Calculate Kc at 448°C for the reaction.

Answers

Answer:

1.74845

Explanation:

We have the following reaction:

I2 + H2 => 2 HI

Now, the constant Kc, has the following formula:

Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b

In this case I2 is A, H2 is B and C is HI

We know that the values are:

 H2 = 1 × 10 ^ -3 at 448 ° C

I2 = 2 × 10 ^ -3 at 448 ° C

HI = 1.87 × 10 ^ -3 at 448 ° C

Replacing:

Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}

Kc = 1.87 ^ 2/2 * 1

Kc = 1.74845

Which means that at 448 ° C, Kc is equal to 1.74845

Answer:

K_c = 51

Explanation:

[H2] = 10^-3

[I2] = 2*10^-3

[HI] = 0

in equilbiirum

[H2] = 10^-3 - x

[I2] = 2*10^-3 -x

[HI] = 0 + 2x

and we know

[HI] = 0 + 2x = 1.87*10^-3

x = ( 1.87*10^-3)/2 =  0.000935

then

[H2] = 10^-3 - 0.000935 = 0.000065

[I2] = 2*10^-3 -0.000935 = 0.001065

                        H₂                +          I              ⇄              2 HI

Initially     1 × 10⁻³                       2 × 10⁻³

Change  -9.35 × 10⁻⁴               -9.35 × 10⁻⁴                +1.87 × 10⁻³

At equil   6.5 × 10⁻⁵                  1.06 5 × 10⁻³               1.87 × 10⁻³

HI increase by 1.87 × 10⁻³M

K_c = ([HI]^2)/([H_2][I_2]) \n\n= ((1.87*10^-^3)^2)/((6.5*10^-^5)(1.065*10^-3)) \n\nK_c = 51

What is a disadvantage of using a structural model to show a chemical compound? Structural models provide minimal three-dimensional information. Structural models do not identify the number and type of each atom. Structural models cannot distinguish between single, double, and triple bonds. Structural models cannot distinguish between different isomers of a compound.

Answers

The answer is the first: that structural models provide minimal three-dimensional information. This is because the ball-and-stick model cannot show the actual size of the atoms depicted in the model. You also cannot see the actual bond lengths between the atoms. This, then, limits the accuracy of the model and fails to precisely portray how the chemical compounds being shown are like in all actuality. Thus, though you do see a three-dimensional picture of the chemical compound, this picture is not completely accurate and is not scaled to size. 

Answer: A - Structural models provide minimal three-dimensional information.

Explanation: