What are the intermolecular force in glycerin

Answers

Answer 1

Answer: Carbon to hydrogen single, double or triple bond as intramolecular forces and is famous for forming ester linkages (intermolecular) as it is an alchol.

Related Questions

Which statement best describes the formula equation Cl2(g) + 2KBr(aq) mc014-1.jpg 2KCl(aq)+ Br2(l)?A Carbon iodide reacts with potassium bromide to form potassium carbon iodide and bromine. B Bromine gas reacts with a solution of potassium chloride to form potassium bromide and chlorine gas. C Potassium bromine gas reacts with liquid chlorine to form potassium chloride in solution and bromine gas. D Chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromine.
HELP ME AGAIN FOR BRAINLIEST
A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.
What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass = 26 grams/mole)?
which part of earths interior is inferred to have convection currents that causes tectonic plates to move

A solution contains 15 g Na₂CO₃ and 235 g if H₂O? What is the mass% of the solution?

Answers

The total mass of the solution is 15 g (Na₂CO₃) + 235 g (H₂O) = 250 g (solution).

Now, let's calculate the mass percent of Na₂CO₃:
Mass percent of Na₂CO₃ = (mass of Na₂CO₃ / total mass of solution) * 100
= (15 g / 250 g) * 100
= 6%

Therefore, the mass percent of Na₂CO₃ in the solution is 6%.

Final answer:

The mass percent of a solution is calculated by dividing the mass of the solute by the total mass of the solution and multiplying by 100%. In this case, the solute is Na₂CO₃ and the solvent is H₂O. The calculation yields a mass percent of 6% for Na₂CO₃ in the solution.

Explanation:

To calculate the mass percent of a solution, we need the mass of the solute and the mass of the solution (which is the sum of the masses of the solute and the solvent). In your given solution, you have 15 g of Na₂CO₃ (solute) and 235 g of H₂O (solvent). Therefore, the total mass of the solution is 15 g (Na₂CO₃) + 235 g (H₂O) = 250 g.

Now, to find the mass percent of Na₂CO₃ in the solution, we use the following formula:

Mass percent = (mass of solute / total mass of solution) × 100%

Substitute the known values into the formula, we get:

Mass percent = (15 g / 250 g) × 100% = 6%

So, the mass percentage of Na₂CO₃ in the H₂O solution is 6%.

Learn more about mass percent here:

brainly.com/question/35288517

#SPJ11

Positrons are spontaneously emitted from the nuclei of(1) potassium-37 (3) nitrogen-16
(2) radium-226 (4) thorium-232

Answers

Answer: Option (1) is the correct answer.

Explanation:

A positron is a small particle which contains a +1 charge and its mass is equal to the mass of an electron, that is, $9.109 * 10^(-31)$ kg.

A positron is represent by the symbol $^(0)_(+1)\beta$ .

For example, $^(37)_(19)K \rightarrow ^(37)_(18)Ar + ^(0)_(+1)\beta$

Whereas nitrogen-16 does not decay to give a positron because nitrogen-16 is the daughter isotope formed due to decay of oxygen-16.

The decay reaction is as follows.

$^(16)_(8)O \rightarrow ^(16)_(7)N + ^(0)_(+1)\beta$

And, on radioactive decay of thorium-232 there will be formation of radium-228 along with emission of an alpha particle.

The reaction will be as follows.

$^(232)_(90)Th \rightarrow ^(228)_(88)Ra + ^(4)_(2)\alpha$

Therefore, we can conclude that out of the given options positrons are spontaneously emitted from the nuclei of potassium-37.

Positrons are spontaneously emitted from the nuclei of potassium -37.

According to one acid-base theory, a water molecule acts as an acid when the water molecule(1) accepts an H+ (3) donates an H+
(2) accepts an OH– (4) donates an OH–

Answers

A water molecule acts as an acid when the water molecule donates an H+.

The correct option is 3, donates an H+.

What is the acid-base theory?

The Acid-base theory tells that if a substance produce hydrogen ion is called as an acid.

If the substance accepts, a hydrogen ion is called as base.

This theory is given by Arrhenius.

Thus, the correct option is 3, donates an H+.

Learn more about acids, here:

brainly.com/question/1515003

According to one acid-base theory, a water molecule acts as an acid when the water molecule (3) donates an H+.

How do we measure the acidity of rain?

Answers

just use litmus paper or a pH indicator

The multiple covalent bond in a molecule of 1-butene is a(1) double covalent bond that has 6 shared electrons
(2) double covalent bond that has 4 shared electrons
(3) triple covalent bond that has 6 shared electrons
(4) triple covalent bond that has 4 shared electrons

Answers

Answer: Option (2) is the correct answer.

Explanation:

An alkene is a molecule that contains a hydrocarbon chain with atleast one double bond.

For example, $H_(2)C=CH-CH_(2)-CH_(3)$ is a 1-butene molecule and it contains one double bond that consists of four shared electrons.

On the other hand, a molecule of hydrocabon that contains a triple bond is known as an alkyne. Whereas a hydrocarbon that contains only single bonds is known as an alkane.

Thus, we can conclude that the multiple covalent bond in a molecule of 1-butene is a double covalent bond that has 4 shared electrons.

(2) double covalent bond that has 4 shared electrons

How would you be able to use the spectrum of each gas to establish its identity

Answers

You could compar and contrast the identities so you can compare them and identify them

Other Questions

How different are the duck leeches offsprings from their parents

Juliet is using a paper towel to clean up a juice spill. The liquid sticks to the paper towel because of _____.adhesion cohesion specific heat a neutral pH

How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl?

if an element,X, can form an oxide that has the formula X2O3, then element X that would most likely be located on the Periodic Table in the group as?