which part of earths interior is inferred to have convection currents that causes tectonic plates to move

Answers

Answer 1
Answer: Asthenosphere is inferred to have convection currents that cause tectonic plates to move because the material in this part of the mantle flows and can move plastically and convection is all about the movement of the magma,the hotter stuff rising towards the crust while the cooler stuff sinks deeper into the mantle.
Answer 2
Answer:

Answer:

Correct answer: B). Global climate is changing due to burning of fossil fuels and deforestation.

Forest holds a large amount of carbon, plants are known to absorb carbon dioxide from the atmosphere as they grow, that carbon dioxide is stored in plants in the form of carbon in plant's roots, leaves and in the soil. When trees are cut down, that stored carbon is released in the environment in the form of carbon dioxide, which accounts for approximately 18% of global greenhouse gas emission.

The burning of fossil fuel like coal, petroleum, oil, gas for the energy purpose is one of the major contributors for the rising level of carbon dioxide in the atmosphere, which leads to global warming and affect the climate.

Hence, the correct answer would be option B.

Explanation:


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Can someone pls help indicate the number of significant figures with these numbers: 34g, 564 l, 19.3 mm, 23.45 mg, 101 km, and 3400 g

Answers

The concept of significant figures are mainly used by scientist and engineer to know the significance of digits in a measurement. Therefore, significant figures gives an idea about the digits that are necessary to indicate the experimental value.

What is significant figures?

Significant figures are the figures that indicate the degree of accuracy of a value. It tells about the precision of a value.

Rules for counting significant figures are:

Number between 1 to 9 is always significant

Zeroes after a number has got no significance

Zeroes before a number has got no significance

Zeroes between number has got significance

34g              2significant figures

564l              3significant figures

19.3mm        3significant figures

23.45 mg     3significant figures

101 km           3significant figures

3400 g          2 significant figures

Therefore, significant figures gives an idea about the digits that are necessary to indicate the experimental value.

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The significant figures is two because that is the least amount of spaces before the decimal out of those numbers

A sample of 0.3257 g of an ionic compound containing the bromide ion (Br−) is dissolved in water and treated with an excess of AgNO3. If the mass of the AgBr precipitate that forms is 0.7165 g, what is the percent by mass of Br in the original compound?

Answers

Answer:

Explanation:

Given parameters:

Mass of ionic compound = 0.3257g

Mass of AgBr precipitate = 0.7165g

Unknown:

Percent mass of Br in the original compound.

Solution

The percent mass of Br in original compound = (mass of  Br  in the sample)/(mass of sample)

Now we have to find the mass of Br⁻:

We must note that the same mass of Br⁻ would move through the ionic sample to form the precipitate.

Mass of Br in AgBr = (Atomic mass of Br)/(Molar mass of AgBr)  x mass of precipitate

Mass of Br =  (80)/(80 + 108)  x 0.7165

Mass of Br = 0.426 x 0.7165 = 0.305g

Percent mass of Br = (0.305)/(0.3257) x 100 = 93.7%

What part of a plant is most likely to show negative phototropism

Answers

Negative phototropism in plants refers to the growth response of plant parts away from a light source. The part of a plant most likely to show negative phototropism is the roots.

Negative phototropism in plants refers to the growth response of plant parts away from a light source. This means that the plant part will grow in a direction where it receives less light.

Roots typically exhibit negative phototropism because they grow away from light sources. This behavior is advantageous for roots because they need to grow deeper into the soil to seek water, nutrients, and stability. By growing away from light, roots are guided towards a more favorable environment for their functions. In contrast, other parts of the plant, such as stems and leaves, often exhibit positive phototropism, where they grow towards light to optimize photosynthesis and energy production.

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Final answer:

The root of a plant is the part that is most likely to show negative phototropism.

Explanation:

The part of a plant that is most likely to show negative phototropism is the root.

Phototropism is the growth response of a plant to light, and negative phototropism means the plant grows away from the light.

The root grows downwards into the soil, away from the light, in order to anchor the plant and absorb water and nutrients.

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1. Eleanor weights 300 N. She walks up a small hill which is 5 meters high. It takes her 4 seconds. How much work did Eleanor do when she climbed the hill? (3 points)Hint: What is the equation used to calculate work? Does time affect the amount of work completed?

Answers

The equation is Work equals the force times the distance in the direction of the force. This is 300 N * 5 m = 1500 J.

The time does not affect the amount of work.

Which process takes place when recharging a rechargeable battery?

Answers

Answer:

The correct answer is "Oxidation at the anode and reduction at the cathode".

Explanation:

A rechargeable battery is recharged by the movement of electrons from an external power source into the battery. In order to achieve this, two process take place inside the rechargeable battery: oxidation at the anode and reduction at the cathode. The electrons flow within the battery from the anode to the cathode, this happens by the oxidation of the anode (loss of electrons) and the reduction at the cathode (gain of electrons).

moving of positive charge electron and negative charge proton.

Can someone how to do these problems!!

Answers

You can use the follwing equations.
pH=14-pOH
pOH=-log[OH⁻]

a)  pOH=-log10⁻¹²
     pOH=12
     pH=14-12
     pH=2

You can also use these equations:
[H⁺]=K(w)/[OH⁻]    (K(w)=1.01×10⁻¹⁴)
pH=-log[H⁺]

b) [H⁺]=(1.01×10⁻¹⁴)/10⁻²M
    [H⁺]=1.01×10⁻¹²M²
    pH=-log(1.01×10⁻¹²)
    pH=12

You can use either method.  It does not really matter.
I hope this helps.  Let me know if anything is unclear and when you do the calculations for c you should get pH=7.