Consider the dissolution of 2.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreased by 0.93 oC. The heat capacity of the calorimeter is 42.2 J/oC. The density of the water (and the solution) is 1.00 g/mL. The specific heat capacity of the solution is 4.184 J/goC. Calculate the enthalpy change for dissolving this salt on a energy per mass basis (units of J/g).
Answers
The enthalpy change for dissolving this salt on a energy per mass is 136.32 J/g
How to determine the mass of the water
- Density of water = 1 g/mL
- Volume of water = 75 mL
- Mass of water =?
Mass = Density × Volume
Mass of water = 1 × 75
Mass of water = 75 g
How to determine the heat absorbed by the solution
- Mass of water = 75 g
- Mass of salt = 2.50 g
- Mass of solution (M) = 75 + 2.5 = 77.5 g
- Temperature change (ΔT) = 0.93 °C
- Specific heat capacity of the solution = 4.184 J/gºC
- Heat of solution (Q) =?
Q = MCΔT
Q = 77.5 × 4.184 × 0.93
Q = 301.5618 J
How to determine the heat consumed by the calorimeter
- Heat capacity of the calorimeter (C) = 42.2 J/ºC
- Temperature change (ΔT) = 0.93 °C
- Heat by calorimeter (H) =?
H = CΔT
H = 42.2 × 0.93
H = 39.246 J
How to determine the total heat released
- Heat of solution (Q) = 301.5618 J
- Heat by calorimeter (H) = 39.246 J
- Total heat =?
Total heat = 301.5618 + 39.246
Total heat = 340.8078 J
How to determine the enthalpy change
- Total heat = 340.8078 J
- Mass of salt = 2.5 g
- Enthalpy change (ΔH) =?
ΔH = Total heat / mass
ΔH = 340.8078 / 2.5
ΔH = 136.32 J/g
Learn more about heat transfer:
Answer : The enthalpy change for dissolving this salt on a energy per mass basis is 132.4 J/g
Explanation :
Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water
where,
q = heat released by the reaction
= heat absorbed by the calorimeter
= heat absorbed by the water
= specific heat of calorimeter =
= specific heat of water =
= mass of water =
= change in temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the enthalpy change for dissolving this salt on a energy per mass basis.
where,
= enthalpy change = ?
q = heat released = 331.08 J
m = mass of salt = 2.50 g
Therefore, the enthalpy change for dissolving this salt on a energy per mass basis is 132.4 J/g
Related Questions
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What mass of magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?
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The diagram below shows different layers of sedimentary rocks.Picture showing seven layers of rocks of different colors labeled A, B, C, D, E, F, and G from top to bottom; A and B are parallel horizontal layers at the top of the diagram and C, D, E, F, and G are slanted layers with C closest to the surface and G at the bottom. Based on the diagram, which of these inferences is most likely correct? A.Layer A is older than Layer B. B.Layer C is older than Layer E. C.Layer F is younger than Layer D. D.Layer B is younger than Layer G.
Answers
Answer:
Less than
Explanation:
The process of dissolution occurs as a kind of "tug of war". On one side are the solute-solute and solvent-solvent interaction forces, while on the other side are the solute-solvent forces.
Only when the solute-solvent forces are strong enough to overcome the pre-mixing forces do they overcome the "tug of war", and thus dissolution occurs.
Thus, it is concluded that the interaction forces between solute particles and solvent particles before they are combined are less than the interaction forces after dissolution.
For the dissolution of the soluteparticles in the solvent particles, the force of attraction between the particles of solute and between the particle of solvent must be less than the interaction between the solute particles and solvent particles after dissolution.
In a solution the forces act between the solute molecules, solvent molecules, and solute-solvent molecules. For the dissociation to take place the bond between the solute and solvent has to be formed. The resultant will result in the dissolution of the solute in the solvent mixture. The strong solute-solute and solvent-solvent bond will result in difficulty in the formation of the solute-solvent bond, and the dissolution will not take place.
Thus for the dissolution of the solute particles in the solvent particles, the force of attraction between the particles of solute and between the particle of solvent must be less than the interaction between the solute particles and solvent particles after dissolution.
For more information about dissolution, refer to the link:
Answers
Answers
NaCl is 1:1, while H2O is 2:1.
B.) 75g
C.) 120g
D.) 140g
Answers
Answer:
A
Explanation:
Im just guessing its half of 200 as it says
Final answer:
The actual yield of a reaction, where only 50% of a theoretical yield of 200g is formed, is 100g.
Explanation:
The actual yield refers to the amount of product that is actually formed when the reaction is carried out in a real-life setup. In this case, if the theoretical yield (which is the amount of product predicted by stoichiometric calculations) is 200g but only 50% is actually formed, then the actual yield would be 50% of the theoretical yield. Hence, the answer will be 50% of 200g i.e., 100g.
Learn more about Yield in Chemistry here:
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Answers
The atomic mass of bromine is: A(Br) = 80
The molecule Br₂ consists of 2 Br atoms. Thus, the molecular mass of bromine is: Mr(Br₂) = 2*A(Br) = 2*80 = 160
This means there are 160 grams/l of Br₂ in 1 M.
Let's write a proportion. If 160 grams/l of Br₂ are present in 1 M, how much of Br₂ will be in 0.01 M:
160 g/l : 1 M = x : 0.01 M
After crossing the products:
x = 80 * 0.01 = 1.6 g/l
Let's write another proportion. If there are 1.6 g of Br₂ in 1 liter, how many of Br₂ will be present in 0.5 liter:
1.6 g : 1 l = x : 0.5
After crossing the products:
x = 1.6 * 0.5 = 0.8 g