H2O has a mc021-1.jpgHvap = 40.7 kJ/mol. What is the quantity of heat that is released when 27.9 g of H2O condenses?

Answers

Answer 1
Answer: The molecular weight of H2O is 18g/mol.
Therefore, 27.9 g H2O / (1mol/18g) = 0.155 mol H2O
Calculating only for the latent heat, the heat required to be released for this amount of H2O to condense is:
40.7 kJ/mol (0.155 mol) = 6.3 kJ or -6.3 kJ since it is to be released

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Which of the following can be used to neutralize an ammonia (NH3) solution?

Answers

It really depends on your options. 
Since NH3 solution is a weak base, the option that neutralizes a base is an acid. So find an acid among your options, and here are some examples: HNO3, HCl, etc.
It would have been much better if you had attached some options to choose. But I think I've got what you mean. I bet that solution is HCl.

What are atoms that have gained or lost electrons?A. ions
B. isotopes
C. elements
D. molecules

Answers

They are called... ions.
Ions have negative charges. They also contain more protons than electrons.
I hope this helps!

Answer:

IONS

Explanation:

Determine which of these elements would be liquid at 525 K (assume samples are protected from air): A. platinum, Pt B. selenium, Se C. bismuth, Bi D. copper, Cu E. calcium, Ca

Answers

Answer:

selenium, Se

Explanation:

Selenium is the only element that has a melting point below 525 K. Therefore, it would be the only element that would be liquid at that temperature.

Final answer:

At 525 K, only bismuth would be in the liquid phase as its melting point is 544.7 K and boiling point is 1837 K, while all other elements would be in the solid state.

Explanation:

The question asks about the phase of different elements at a specific temperature of 525 K. To answer the question, we need to know the melting and boiling points of these elements: platinum (Pt), selenium (Se), bismuth (Bi), copper (Cu), and calcium (Ca).

At 525 K, bismuth (Bi) would be in the liquid state as its melting point is 544.7 K and boiling point is 1837 K. All other elements mentioned have melting points and boiling points higher than 525 K, so they would be in the solid state.

Learn more about Phase of Elements at Temperature here:

brainly.com/question/32773702

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Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium nitrite (KNO2). The acid dissociation constant of nitrous acid is 4.5 × 10^-4. Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium nitrite (KNO2). The acid dissociation constant of nitrous acid is
4.5 × 10^-4.

Answers

HNO2 =====> H+ + NO2-
Initial concentration = 0.311
C = -x,x,x 
E = 0.311-x,x,x

KNO2 ====>K+ + NO2- 
Initial concentration = 0.189 
C= -0.189,0.189,0.189 
E = 0,0.189,0.189
 

The process of a material going through a change of state from a gas to a liquid is called _____. melting freezing condensation vaporization

Answers

Condensation is the change in state of matter from gas to liquid.

The process of a material going through a change of state from a gas to a liquid is called _____.

condensation

What orbits the nucleus of an atom?

Answers

Electrons orbit the nucleus of an atom. They are very small, in fact they are 1/2000 of an amu. Electrons are negative while the inside of an atom includes the positive protons and neutral neutrons. :D
Electrons. They are found in the orbitals outside the nucleus.