Which celestial object is found in the Kuiper Belt?

Answers

Answer 1
Answer: Beyond the planet Neptune is found a region filled with icy bodies. This region is known as the Kuiper Belt. This holds trillions of objects which is said to be remnants of the early solar system. The region contains comets and dwarf planets.

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Smoking marijuana can be as unhealthy as smoking cigarettes and ___________a. can cause cancer.
b. results in "smokers breath."
c. can lead to premature aging.

Answers

The answer is all of them. But in a school situation, would be appropriate. This is because the smoke gets into the smokers lungs, whether it be marijuana or tobacco, and can cause cancer cells to grow in your lungs and enter your bloodstream.
So A is the answer. 

Smoking marijuana can be as unhealthy as smoking cigarettes and can cause cancer.

a. can cause cancer.

Smoking marijuana can be as unhealthy as smoking cigarettes, and it can cause cancer. Marijuana smoke contains many of the same harmful chemicals as cigarette smoke, including tar, carbon monoxide, and carcinogens. These chemicals can damage DNA and lead to the development of cancer.

In addition to cancer, smoking marijuana can also lead to other health problems, such as respiratory problems, heart disease, and lung infections. It can also impair cognitive function and increase the risk of accidents.

The other options, b. results in "smokers breath" and c. can lead to premature aging, are also possible effects of smoking marijuana, but they are not as serious as cancer.

To know more about marijuana here

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From where does the nitrogen in the nitrogen cycle originate?a. root nodules of legumes
b. the atmosphere
c. decomposers
d. nitrifying bacteria

Answers

The correct answer is B. The nitrogen in the nitrogen cycle originate from the atmosphere. It forms approximately 78% of the Earth's atmosphere. However, this form is not usable because it is in its most stable form therefore unreactive. This nitrogen gas needs to be converted into nitrate compound for it to be usable. Then, the nitrogen cycle starts.

Answer:

B) the atmosphere

Explanation:

How many grams of carbon dioxide (CO2) are found in a 11.9 L container under 1.5 atm and 20.0oC.

Answers

pV=nRT

p = 1,5atm = 1,5*101325 = 151987,5 Pa
V = 11,9l = 0,0119m3
n = ?
R = 8,314 J/mol*K
T = 20°C = 20+273 = 293K

pV=nRT
151987,5*0,0119 = n*8,314*293
1808,6513=n*2436,002  ||:2436,002
0,7425 = n >>> moles of CO2

1 mole of CO2 = 44g

1 mole of CO2--------------44g
0,7425 moles of CO2----------x
x = 32,67g of CO2

What is the product when magnesium reacts with nitrogen? Mg(s) + N2(g) →

Answers

magnesium nitride would be the result of this reaction

Stage in a star's evolution formed as the core of a main sequence star uses up its helium and the outer layers escape into space

Answers

Answer:

The stars when they release their helium and get rid of their cape and throw it into space is because it is already the end of their life

Explanation:

During a portion of its life, a bright star due to the thermonuclear fusion of hydrogen in helium in its nucleus, which releases energy that crosses the interior of the star and then radiates into outer space. When the hydrogen in the nucleus of a star is almost depleted, almost all heavier elements than naturally produced helium are created by stellar nucleosynthesis during the life of the star and, in some stars, by nucleosynthesis of supernovae when explode At the end of its life, a star can also contain degenerate matter

Answer: the answer is white dwarf

Explanation:

The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO2. How many moles of water are used in this reaction?

Answers

The reaction that results from this is:

H2O + CO2 --> H2CO3

Stoichiometric ratio between water and CO2 is 1:1. So we can say that for every Mole of CO2, we need 1 Mole of water to produce 1 Mole of H2CO3. Thus as n=m/M we can find n = 528/44.01 = 11.997 ~ 12Mol.

therefore, we need 12 moles of water.

Answer:

First one, 12.0.

Explanation: