A water wave travels across a 42-meter wide pond in 7.0 seconds. The speed of the wave is _____. 292 m/s 49 m/s 6.0 m/s 0.17 m/s

Answers

Answer 1

Answer:    Speed = (distance covered) / (time to cover the distance).

The speed of anything that covers 42 meters in 7 seconds is

   (42 meters) / (7.0 seconds)

   = (42 / 7.0) (meters/second)

   =   6.0 m/s .

Answer 2

Answer:

Answer:

6.0 m/s

Explanation:

A water wave travels across a 42-meter wide pond in 7.0 seconds. The speed of the wave is _____.

292 m/s

49 m/s

6.0 m/s

0.17 m/s

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Name the physical quantity measured by the velocity-time graph?

Answers

The so-called "velocity-time" graph is actually a "speed-time" graph. At any point
on it, the 'x'-coordinate is a time, and the 'y'-coordinate is the speed at that time.

'Velocity' is a speed AND a direction. Without a direction, you do not have a velocity,
and these graphs never show the direction of the motion. It seems to me that it would be
pretty tough to draw a graph that shows the direction of motion at every instant of time,
so my take is that you'll never see a true "velocity-time" graph.

At best, it would need a second line on it, whose 'y'-coordinate referred to a second
axis, calibrated in angle and representing the 'bearing' or 'heading' of the motion at
each instant. The graph of uniform circular motion, for example, would have a straight
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What is the KE of a bird, mass 40g flying at 23m/s?

Answers

Answer:

230

Explanation:

You do Ke = kinetic times distance divide by mass

A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.15 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +9.0 10-4 J. (a) Find the magnitude and direction of the electric force that acts on the particle. _______N the direction of motion (along, against, perpendicular)
(b) Find the magnitude and direction of the electric field that the particle experiences. _______N/C the direction of motion (along, against, perpendicular)

Answers

The magnitude of the electric field is 4000 N/C while the direction of the electric field is along the direction of the motion of the charge.

Given to us

Charge of the particle, q = +1.5 µC = 1.5 x 10⁻⁶

Distance between points A and B, d = 0.15 m

The particle's electric potential energy at A and B

= $\rm EPE_A - EPE_B$ = +9.0x10⁻⁴ J

What is the magnitude and direction of the electric force that acts on the particle?

The electric charge in electric potential energy is equal to the work done by an electric field. therefore,

$\rm W=EPE_A - EPE_B$

W = 9.0x10⁻⁴ J

We know that work done by the system can be given as,

$\rm Work = force* displacement$

Substitute the values,

$9 * 10^(-4)= F * 0.15$

F = 1.5 x 10⁻³ N

Thus, the magnitude of the force is 1.5 x 10⁻³ N while its direction is along with the motion of the charge.

What is the magnitude and direction of the electric field that the particle experiences?

We know the relationship between electrostatic and electric force, therefore,

$\rm Force = charge* Electric\ field$

Substitute the values,

$6* 10^(-3)=1.5* 10^(-6) * \rm E$

E = 4000 N/C

Hence, the magnitude of the electric field is 4000 N/C while the direction of the electric field is along the direction of the motion of the charge.

Learn more about the Electric field:

brainly.com/question/12757739

Answer:

Part a)

$F = 6 * 10^(-3) N$

Direction of force is along the motion of charge

Part b)

$E = 4000 N/C$

direction of electric field is along the direction of motion

Explanation:

Part a)

As we know that the change in electric potential energy is equal to the work done by electric field

$W = EPE_A - EPE_B$

$W = 9.0 * 10^(-4) J$

now from the equation of work done we know that

$W = F.d$

$(9.0 * 10^(-4)) = F(0.15)$

$F = 6 * 10^(-3) N$

Direction of force is along the motion of charge

Part b)

As we know the relation between electrostatic force and electric field given as

$F = qE$

$(6 * 10^(-3)) = 1.5 * 10^(-6) E$

$E = 4000 N/C$

direction of electric field is along the direction of motion

Who established the 1st college course in radiography for dental students?

Answers

Howard Riley Raper, In 1909, Raper (a dentist at the Indiana Dental College, now known as Indiana University School of Dentistry) established the first course in dental radiography for dental undergraduate students.

Please help me, i beg you. Which Statement best describes the inner core of the earth?

a
A metallic liquid substance
b
A very cold substance
c
A spherical solid metal made up of Nickel, Iron and small amount of sulfur, silicon and oxygen.
d
A flatten but thick structure similar to a granite counter top

Answers

Answer:

Explanation:

A spherical solid metal made up of Nickel, Iron and small amount of sulfur, silicon and oxygen.

you are welcome

If an object looses electrons, then have been transferred

Answers

if a neutral object loses some electrons, then it will possess more protons

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