CHEMISTRY HIGH SCHOOL

Consider the balanced chemical equation for the combustion of methane (CH4).mc026-1.jpg

Given that the molar mass of CO2 is 44.01 g/mol, how many liters of oxygen is required at STP to produce 88.0 g of CO2 from this reaction?
44.8 L
45.00 L
89.55 L
89.6 L

Answers

Answer 1
Answer:

Answer:

                  89.6 L of O₂

Solution:

The balanced chemical equation is as,

                                CH₄  +  2 O₂    →    CO₂  +  2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

             44 g ( 1 mol) CO₂ is produced by  =  44.8 L (2 mol) of O₂

So,

                  88 g CO₂ will be produced by  = X L of O₂

Solving for X,

                        X = (88 g × 44.8 L) ÷ 44 g

                        X = 89.6 L of O₂
Answer 2
Answer: Took a guess and got it right!

D) 89.6 L

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Some substances cannot exist in liquid form at normal atmospheric conditions.
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Answers

I think it might be true.
false that is what i think

CaCO3---> CaO+CO2 How many moles of CaO form when 98.60g CaCO3 decompose? 98.60g CaCO3= ______ mol CaO

Answers

Answer:

0.9852 moles of CaO

Explanation:

Reaction equation for the decomposition of CaCO₃:

CaCO₃ → CaO + CO₂

The question asks how many moles of CaO form when 98.60g of CaCO₃ decompose.

We can see from the reaction equation that for every mol of CaCO₃, one mol of CaO will be produced (molar ratio 1:1)

_____________________________________________________

So first we need to calculate how many moles are the 98.60g of CaCO₃:

Molar Mass of CaCO₃ = molar mass Ca + molar mass C + 3 * molar mass O

                                     = 40.078 + 12.011 + 3 * 15.999 = 100.086 g/mol

Moles of CaCO₃ = mass CaCO₃ / molar mass CaCO₃

Moles of CaCO₃ = 98.60 g / 100.086 g/mol = 0.9852 moles CaCO₃

________________________________________________________

As we said before for every mol of CaCO₃, one mol of CaO is produced.

So the decomposition of 0.9852 moles of CaCO₃ will produce 0.9852 moles of CaO.

Hey I think it is going to be 0986 moles. Cuz we can see that no. of moles of CaCO3 which will decompose is equivalent to the no. of CaO . Now it's just the matter of finding the no. of moles of CaCO3 .

no.of moles=mass /relative molecular mass

If 600.0 ml of air at 20.0 c is heated to 60.0L , what will be its volume

Answers

p1v1/t1 = p2t2/t2

p is constant
v1=600, t1 =20c=293K
v2=?, t2=60c=333K
temperature must be in Kelvin

do the math

Which statement about exothermic reactions is accurate? a.As reactants form products, the potential energy decreases.
b.As reactants form products, the potential energy increases.
c.Thermal energy is transferred from the product to the reacting substances.
d.Thermal energy is transferred from the surroundings to the reacting substances.

Answers

Option A. Exothermic reactions RELEASE energy, so the potential energy of the products will be less than the energy of the reactants.

Answer:

As reactants form products, the potential energy decreases.

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Edge

What is the mass of potassium chloride when 6.75g of potassium reactants with an excess of chlorine gas the balanced chemical equation

Answers

2K+Cl₂→2KCl
First you need to find the number of moles of potassium that is present in a 6.75g sample.  To do this you need to divide the mass of potassium (6.74g) by its molar mass (39.1g/mol) to get 0.172mol K.  Since we are told that the reaction happens with excess chlorine we know that potassium is the limiting reagent and we can therefore ignore chlorine gas and convert the moles of potassium straight to the moles of potassium chloride.  Since we know that 2 moles of potassium creates 2 moles of potassium chloride we can say that 0.172mol K turns into 0.172mol KCl since the molar ratio is 2/2 which can be thought of as 1.  The final step is to multiply 0.172mol KCl by its molar mass (74.55g/mol) to get 12.85g of potassium chloride.

I hope this helps.  Let me know in the comments if anything is unclear.

Please help me, please

Answers

Answer:

A. Metal

Explanation:

Hope this helps! :)

If this wasn't what you were looking for please don't hesitate to comment again! Have a nice day/night! :)

Answer:

Metal

Explanation:

they deleted my answer so I am putting it back sorry
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