Explanation :
As we know that the geometrical symmetry of the molecule and the polarity of the bonds both are equally important for determining the polarity of the molecule.
The molecule that has zero dipole moment that means it is a geometrical symmetric molecule and the molecule that has some dipole moment that means it is a geometrical asymmetric molecule.
As the molecule is symmetric, the dipole moment will be zero and the molecule will be non-polar.
As the molecule is asymmetric, the dipole moment will not be zero and the molecule will be polar.
Thus, we can say that the a symmetry molecule is non-polar in nature and an asymmetry molecule is a polar molecule.
Hydroxide Ions
Acid and Bases are defined according to three different theories and concepts.
A) Arrhenius Concept
B) Lowry Bronsted Theory
C) Lewis Theory
According to Arrhenius Concept of Acid and Base, "Acid is any specie which when dissolved in water ionizes to produce H⁺ ions".
Examples:
HNO₃ → H⁺ + NO₃⁻
H₃PO₄ → 3 H⁺ + PO₄³⁻
While, "Bases are those species which when dissolved in water produces Hydroxyl Ions (OH⁻)".
Examples:
KOH → K⁺ + OH⁻
Ca(OH)₂ → Ca²⁺ + 2 OH⁻
When an Arrhenius base dissolves in water, it yields hydroxide ions (OH-).
When an Arrhenius base is dissolved in water, it yields hydroxide ions, which have a chemical formula of OH-. The formula for an Arrhenius base is usually represented as BOH, where B represents a cation (positive ion) and OH- represents the hydroxide ion. Some examples of Arrhenius bases include sodium hydroxide (NaOH) and potassium hydroxide (KOH).
#SPJ6
A. AgCrO4(s) + Na2NO3(aq)
B. Ag2CrO4(s) + NaNO3(aq)
C. Ag(CrO4)2(s) + Na2NO3(aq)
D. Ag(CrO4)3(s) + Na(NO3)2(aq)
The products obtained when 2 AgNO₃ + Na₂CrO₄ reacts is Ag₂CrO₄ + 2 NaNO₃.
The reaction in which reduction and oxidation takes place simultaneously
by obtaining or losing an electron, the oxidation number of a molecule, atom, or ion varies.
In the question it is given that
AgNO₃(aq) + Na₂CrO₄(aq) → and we have to predict the products
So Silver Nitrate when reacts with Chromic Acid to from silver Chromate and sodium nitrate.
2 AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2 NaNO₃
Therefore Product B is the correct answer.
To know more about Redox Reaction
#SPJ5
Answer:
approximately 4.8 grams of oxygen gas is formed.
Explanation:
To determine the amount of oxygen (O2) formed when 12.26 grams of potassium chlorate (KClO3) is heated, we need to consider the chemical reaction that occurs during this process. When KClO3 is heated, it decomposes into potassium chloride (KCl) and oxygen gas (O2).
The balanced chemical equation for this reaction is:
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
Calculate the molar mass of KClO3:
K: 39.10 g/mol
Cl: 35.45 g/mol
O: 16.00 g/mol
Molar mass of KClO3 = (39.10 + 35.45 + 3 * 16.00) g/mol = 122.55 g/mol
Calculate the number of moles of KClO3 in 12.26 grams:
Moles of KClO3 = (12.26 g) / (122.55 g/mol) = 0.1 moles
Now, we can determine the number of moles of O2 produced using the mole ratio from the balanced equation:
Moles of O2 = (0.1 moles of KClO3) * (3 moles of O2 / 2 moles of KClO3) = 0.15 moles
Finally, convert moles of O2 to grams:
Mass of O2 = (0.15 moles) * (32.00 g/mol for O2) = 4.8 grams
So, when 12.26 grams of KClO3 is heated, approximately 4.8 grams of oxygen gas is formed.
(2) The atomic radius decreases, and the first ionization energy generally decreases.
(3) The atomic radius increases, and the first ionization energy generally increases.
(4) The atomic radius increases, and the first ionization energy generally decreases.
The type of stoichiometric calculation that does not require the use of the molar mass is a calculation involving molar or stoichiometric ratios which are derived directly from the coefficients in a balanced chemical equation.
In stoichiometry, there are several types of calculations that can be performed. However, the type of stoichiometric calculation that does not require the use of the molar mass is the calculation involving the molar ratio, or stoichiometric ratio. This refers to the ratio of coefficients in a balanced chemical equation, which we use to determine the relative amounts of each substance involved in a chemical reaction.
An example of this is a balanced equation for the formation of water: H2 + 0.5O2 -> H2O. In this equation, the molar or stoichiometric ratio of hydrogen (H2) to oxygen (O2) to water (H2O) is 2:1:2. If we are given the number of moles of one substance, we can use this molar ratio to find the number of moles of any other substance in the equation, without needing to know their molar masses. This constitutes a stoichiometric calculation without the need for molar mass.
#SPJ3