PHYSICS MIDDLE SCHOOL

The displacement vector from your house to the library is 760 m long, pointing 35° north of east. What are the components of this displacementvector?

Answers

Answer 1
Answer:

Answer:

The two components of displacement vector are:

East:760\cos 35=622.56\ m\nNorth:760\sin 35=435.92\ m

Explanation:

Given:

The magnitude of displacement is 760 m.

The direction of the displacement vector is 35° North of East.

North of East means that the vector is between North and East and makes an angle of 35° with the east direction.

Now, there are two components of this displacement vector. One component is along the East direction and the other perpendicular to the East direction which is the North direction.

Component along the East direction is given as:

East:760\cos 35=622.56\ m

Component along the North direction is given as:

North:760\sin 35=435.92\ m

Therefore, the two components that are mutually perpendicular to each other are 622.56 m East and 435.92 m North.

Answer 2
Answer:

Final answer:

In physics, the vector components of a displacement of 760 meters at an angle of 35 degrees north of east are approximately 622 meters eastward and 435 meters northward.

Explanation:

The displacement vector you're describing is associated with a movement that falls under the umbrella of vector algebra, a common topic in physics. We're given a magnitude (760 m) for the vector and a direction (35° north of east).

We decompose, or break down, this displacement vector into its component along the east (x-direction) and north (y-direction). This splitting of vectors into components is useful when dealing with multiple vectors as it simplifies calculations.

For the eastward component (x-component, or horizontal), we use the cosine of the given angle. For the Northward component (y-component, or vertical), we use the sine of the given angle. The formulas are as follows:

  • Eastward component=x = 760 m * cos(35)
  • Northward component=y = 760 m * sin(35)

Calculating these gives us roughly x = 622 m eastward and y = 435 m northward. These are the vector components of your original displacement vector.

Learn more about Vector Components here:

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James Cameron piloted a submersible craft to the bottom of the Challenger Deep, the deepest point on the ocean's floor, 11,000 m below the surface. What was the total inward force on the 1.1-m-diameter pilot sphere in which Cameron sat?

Answers

Answer:

4.1\cdot 10^8 N

Explanation:

First of all, we need to find the pressure exerted on the sphere, which is given by:

p=p_0 + \rho g h

where

p_0 =1.01\cdot 10^5 Pa is the atmospheric pressure

\rho = 1000 kg/m^3 is the water density

g=9.8 m/s^2 is the gravitational acceleration

h=11,000 m is the depth

Substituting,

p=1.01\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(11,000 m)=1.08\cdot 10^8 Pa

The radius of the sphere is r = d/2= 1.1 m/2= 0.55 m

So the total area of the sphere is

A=4 \pi r^2 = 4 \pi (0.55 m)^2=3.8 m^2

And so, the inward force exerted on it is

F=pA=(1.08\cdot 10^8 Pa)(3.8 m^2)=4.1\cdot 10^8 N

The total inward force is about 4.1 × 10⁸ N

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Further explanation

Let's recall Hydrostatic Pressure formula as follows:

\boxed{ P = \rho g h}

where:

P = hydrosatic pressure ( Pa )

ρ = density of  fluid ( kg/m³ )

g = gravitational acceleration ( m/s² )

h = height of a column of liquid ( m )

Let us now tackle the problem!

\texttt{ }

Given:

depth of the ocean's floor = h = 11 000 m

diameter pilot sphere = d = 1.1 m

atmospheric pressure = Po = 10⁵ Pa

Asked:

total inward force = F = ?

Solution:

F = P A

F = ( P_o + \rho g h ) A

F = ( P_o + \rho g h ) ( \pi d^2 ) → Area of Sphere = π d²

F = ( 10^5 + 1000 * 9.8 * 11000 ) ( \pi * 1.1^2 )

F \approx 4.1 * 10^8 \texttt{ Newton}

\texttt{ }

Conclusion:

The total inward force is about 4.1 × 10⁸ N

\texttt{ }

Learn more

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Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

This experiment is to see if water flows faster out of a smaller can or a larger can. You will need:

• two cans (one quite small like a soup can and the other large, like a juice, can.)

Follow these steps:

A. Remove the top of each can. Punch a hole in the side of each can, very close to the bottom, making sure the holes are equal in size. Cover each hole with a piece of tape, and place the cans next to the sink.
B. Put water in both cans, making sure the water is at the same level - different amounts, but the same level. Turn the cans so the holes are facing into the sink, and remove the tape at the same time. Answer these questions: Do the streams of water shoot out at the same distance? Why or why not?
C. Try the same experiment, but this time put one cup of water in each can. What happens to the streams of water now?
D. Try the same experiment, but this time fill both cans to the top. What happens to the streams of water?



ANSWER A B C AND D CORRECTLY!!!

Answers

the water flows faster out of a smaller can than it does a larger can.

Answer:

A&B: The stem of the water does not shoot out the same distance because one can have less water and the other can have more water and the can with less water have more pressure that making the can shoot out further than the can with more water.

C: Less water will come out of the two cans because they are compressed together so all of the water is trying to come out all at the same time.

D:All of the water in the can started coming out all in one small stream.

Explanation:

An eagle carrying a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1 m. The fish travels 7.9 m horizontally before hitting the water.What is the velocity of the eagle? Round your answer to the nearest tenth.
m/s

Answers

Answer:

7.1 m/s

Explanation:

First, find the time it takes for the fish to reach the water.

Given in the y direction:

Δy = 6.1 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

6.1 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.12 s

Next, find the velocity needed to travel 7.9 m in that time.

Given in the x direction:

Δx = 7.9 m

a = 0 m/s²

t = 1.12 s

Find: v₀

Δx = v₀ t + ½ at²

7.9 m = v₀ (1.12 s) + ½ (0 m/s²) (1.12 s)²

v₀ = 7.1 m/s

Answer:

7.1m/s

Explanation:

EDGE

Imagine you poor some hot soup into a bowl. You place your hands on the outside of the bowl and feel that the bowl is very warm. How did that heat get from the soup bowl through your hands?A Osmosis
B Radiation
C Conduction
D Convection

Answers

May be The answer is Conduction
the answer  is c conduction

Which of the following is NOT supported by Newton's Second Law?1 The mass of an object will change depending on the force acting on it

2 The greater the force applied on an object, the greater it's acceleration

3 You can find the mass of an object if you know it's acceleration and the forces acting on it

4 Force is equal to the product of mass and acceleration

Answers

Answer:

1. The mass will change depending on the force.

Explanation:

We know that the newton's second law of motion gives the relation between the mass (m) of an object, force (F) applied and the corresponding measure of acceleration (a) of the object. This can be expressed in the form of an equation:

                     F = ma

Thus force is the product of mass and acceleration. Using this equation we can derive mass of an object, if acceleration and force values are known.

In the given equation, mass is a constant value and mass will not change in any case. Therefore force is directly proportional to amount object will be accelerated. With the increase in force applied on object, amount the object accelerated will increase and vice versa

sla’s change in velocity is 30 m/s, and Hazel has the same change in velocity. Which best explains why they would have different accelerations?

Answers

Because acceleration depends not only on the change in velocity.
It also depends on the time during which the change occurs.
The formula is

Acceleration = (change in velocity) divided by (time for the change) .

Maybe Sla changed his velocity in 3 seconds, but Hazel
took all morning to change hers.  In that case, even though
the amounts of change were equal, the times were different,
so the quotients of (change/time) were different. 
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