If the solution process is endothermic, then an increase in temperature usually results in:an increase in solubility

a decrease in solubility

no change in the solubility

a slower reaction

Answers

Answer 1
Answer:

If the solution process is endothermic, then an increase in temperature usually results in an increase in solubility. Their heat of reaction is usually positive. The rest of the choices do not answer the question above.

Answer 2
Answer:

Answer:

solubility increases

Explanation:


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What volume of 0.205 m k3po4 solution is necessary to completely react with 154 ml of 0.0110 m nicl2? 1.65 l?

Answers

the balanced equation for the above reaction is 
2K₃PO₄   + 3NiCl₂  ---> 6KCl + Ni₃(PO₄)₂
stoichiometry of K₃PO₄  to NiCl₂ is 2:3
the number of NiCl₂ moles reacted - 0.0110 mol/L x 0.154 L = 1.69 x 10⁻³ mol
if 3 mol of NiCl₂ reacts with - 2 mol of K₃PO₄ 
then 1.69 x 10⁻³ mol of NiCl₂ reacts with - 2/3 x 1.69 x 10⁻³  = 1.13 x 10⁻³ mol of K₃PO₄
molarity of K₃PO₄ solution given - 0.205 M
there are 0.205 mol in 1 L
therefore 1.13 x 10⁻³ mol are in - 1.13 x 10⁻³ mol / 0.205 mol/L = 5.51 mL
volume of K₃PO₄ required - 5.51 mL

If ΔH = -50.0 kJ and ΔS = -0.300 kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature.

Answers

The basis for spontaneous reactions and their dependence on temperature is given by the equation for the Gibbs Free energy:

ΔG = ΔH – S < 0


For a spontaneous reaction to occur, ΔG must be negative. Following the equation, ΔH must be < 0, and ΔS must be > 0 for a reaction to be spontaneous at all temperatures. However, the given values have a negative value for both enthalpy and entropy. This means that spontaneity can only occur below a certain temperature, which can be calculate by setting ΔG as zero. This gives:

ΔG = ΔH – TΔS = 0

T = ΔH/ΔS = -50/-0.3 = 166.67 Kelvin

Anything below that temperature gives a negative ΔG, making it spontaneous.

Final answer:

The reaction is spontaneous at temperatures greater than 166.7 K.

Explanation:

To determine the temperature at which the reaction is spontaneous, we can calculate the Gibbs free energy change (ΔG) using the equation ΔG = ΔH - TΔS, where ΔH is the enthalpy change and ΔS is the entropy change. Since the reaction is spontaneous below a certain temperature, we can assume that at this temperature, ΔG is negative. Thus, we have -50.0 kJ - T(-0.300 kJ/K) < 0. Solving for T, we find that the reaction is spontaneous at temperatures greater than 166.7 K.

Learn more about Spontaneity of reaction here:

brainly.com/question/32274705

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The ____ contains the highest concentration of ozone.a. troposphere
c. stratosphere
b. mesosphere
d. exosphere

Answers

C. The stratosphere. About 90% of the ozone is in the stratosphere which begins about 8 miles above the Earth's surface.

Answer: Option (c) is the correct answer.

Explanation:

A layer above the troposphere and below the mesosphere is known as stratosphere.

This layer of stratosphere contains about 90% concentration of ozone and there is no occurrence of weather in this layer.

The occurrence of ozone in stratosphere makes it warmer.

Therefore, we can conclude that the stratosphere contains the highest concentration of ozone.

How to know that something is a basic oxide or acedic oxides?
plz help ​

Answers

Explanation:

General Rules. In general, the electropositive character of the oxide's central atom will determne whether the oxide will be acidic or basic. The more electropositive the central atom the more basic the oxide. The more electronegative the central atom, the more acidic the oxide.

Stoichiometry! Please note:
- Use 6.022x1023 for avogadro’s number
- Ignore sig figs and do not round the final answer.
- Keep it to 1 decimal place.

Answers

Answer:

a) 13.2 moles 2H_(2)O

b) 79.33 grams of 2H_(2)O

Explanation:

First, we'll need to balance the equation

H_(2(g)) + O_(2(g))H_(2)O_((g))

There are 2 (O) on the left and only one on the right, so we'll add a 2 coefficient to the right.

H_(2(g)) + O_(2(g))2H_(2)O_((g))

Now there are 4 (H) on the right and only 2 on the left, so we'll add a 2 coefficient to the (H_(2)) on the left.

2H_(2(g)) + O_(2(g))2H_(2)O_((g))

The equation is now balanced.

a) This can be solved with a simple mole ratio.

4.6 moles O_(2) × (2 moles H_(2)O)/(1 mole O_(2)) = 13.2 moles 2H_(2)O

b) This problem is solved the same way!

2.2 moles H_(2) × (2 moles H_(2)O)/(2 moles H_(2)) = 2.2 moles 2H_(2)O

However, this problem wants the mass of 2H_(2)O, not the moles.

The molecular weight of 2H_(2)O is the weight of 4 (H) molecules and 2 (O) molecules (found on the periodic table). So,

4(1.008) + 2(15.999) = 36.03 g/mol

2.2 moles 2H_(2)O × (36.03 g)/(1 mol) = 79.33 grams of 2H_(2)O

What is equal to the number of particles in 24 grams of carbon-12? 2 moles 2:1 mole ratio 2:1 molar mass 1:2 molar volume

Answers

Answer:

The answer to your question is 2 moles of Carbon

Explanation:

Carbon-12 means it has a molecular mass of 12g / mol. Mol is defined as the number of grams of an atom in one mol.

To solve this problem, we use proportions

                                    12 g of Carbon ---------------- 1 mol of Carbon

                                     24 g of Carbon --------------   x

                                     

                                      x = ( 24 g x 1 mol ) / 12 g

                                      x = 24 / 12

                                     x = 2 mol of Carbon

Answer:

2 moles

Explanation:

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