CHEMISTRY HIGH SCHOOL

The four basic blood types are:
A
B
D
AB
AO
O

Answers

Answer 1

Answer: The four basic blood types are: A, B, AB and O.

Answer 2

Answer:

Answer:

AB, A, O and B.

Related Questions

Which of these elements has physical and chemical properties most similar to silicon (Si)?(1) germanium (Ge) (3) phosphorus (P) (2) lead (Pb) (4) chlorine (Cl)
What should be place in _C6H12O6(s) + _O2(g) mc018-1.jpg _CO2(g) + _H2O(l)
If a substance goes from the gas phase to the liquid phase, was it heated or cooled
What is the next atomic orbital in the series below? 1s, 2s, 2p, ___ a. 2d b. 3d c. 3s d. 2f
what are the three particles of an atom

A hydrocarbon is said to be saturated if: A)           one end of the molecule is hydrophilic while the other end is hydrophobic.
                B)            it has one or more double bonds between carbon atoms.
                C)            it contains more than one functional group.
                D)           each internal carbon atom is covalently bonded to two hydrogen atoms.
                E)            its functional groups include at least one aromatic ring.

Answers

D. If each eternal carbon is bonded to 2 hydrogen atoms, the hydrogen carbon is saturated. An easier way to remember if a hydrocarbon is saturated or not is to look for a double bond between 2 carbons in the chain, if this if present the hydrocarbon is UNsaturated, if this is not present the hydrocarbon is saturated.

Life has existed on Earth for about 3.8 billion years despite gradual and sudden environmental changes. How do the scientific factors of sustainability help explain how life has continued to survive and evolve?

Answers

Answer:

As we all are aware that life on Earth is existed due to several environmental changes and there are several scientific factors of sustainability that support the survival and evolution of life on Earth.

Scientific factors of sustainability include solar energy, chemical cycle, and biodiversity that supported life on Earth.solar energy helps all organism and especially producers to gain energy and store the energy which further used in chemical cycles of transferring energy to other trophic levels.

Chemical cycle also involves the interaction of biotic and abiotic envrionment with each other that leads to environmental changes as well as organisms adapt themselves accordingly.

Biodiversity maintains the balance in the ecosystem and prevent dominancy of one organism otherwise it can lead to scarcity and organism would not be able to survive. Variation in biodiversity due to random mating in the same species leads to evolution and produces new species of organisms.

Hence, scientific factors of sustainability play major role in survival and evolution of life on the Earth.

Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 525 mL of insulin at a concentration of 50.0 mg/mL . What is the total mass of insulin in the bottle?

Answers

26.25 ? I am not sure about my answer ;;-;;

When 70.4 g of benzamide (C,H,NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2.7 C lower than the freezing point of pure X. On the other hand, when 70.4 g of ammonium chloride (NH CI) are dissolved in the same mass of X, the freezing point of the solution is 9.9 °C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits.

Answers

Answer:

1.60 is the van't Hoff factor for ammonium chloride in X.

Explanation:

$\Delta T_f=iK_f* m$

$Delta T_f=K_f* \frac{\text{Mass of solute}}{\text{Molar mass of solute}* \text{Mass of solvent in Kg}}$ ...(1)

where,

$\Delta T_f$ =Elevation in boiling point =

i = van't Hoff factor

$K_f$ = Freezing point constant

m = molality

1) When 70.4 g of benzamide are dissolved in 850. g of a certain mystery liquid X.

Mass of benzamide = 70.4 g

Molar mass of benzamide = 121 g/mol

i = 1 (organic molecule)

Mass of liquid X = 850 g = 0.850 kg

$K_f$ = Freezing point constant of liquid X= ?

$\Delta T_f=2.7^oC$

Putting all value in a (1):

$2.7^oC=K_f* (70.4 g)/(121 g/mol* 0.850 kg)$

$K_f=3.944 ^oC kg/mol$

2) When 70.4 g of ammonium chloride are dissolved in 850. g of a certain mystery liquid X.

Mass of ammonium chloride= 70.4 g

Molar mass of ammonium chloride = 53.5 g/mol

i = ? (ionic molecule)

Mass of liquid X = 850 g = 0.850 kg

$K_f=3.944 ^oC kg/mol$

$\Delta T_f=9.9^oC$

Putting all value in a (1):

$9.9^oC=i* 3.944^oC kg/mol* (70.4 g)/(53.5 g/mol* 0.850 kg)$

i = 1.6011 ≈ 1.60

1.60 is the van't Hoff factor for ammonium chloride in X.

Final answer:

The van't Hoff factor, which measures ionization, for ammonium chloride in the mysterious liquid X can be calculated to be approximately 1.01. This is calculated by first determining the cryoscopic constant from the observed depression of the freezing point by benzamide (which does not ionize), and then utilizing this value to calculate the theoretical freezing point depression for ammonium chloride (pretending it does not ionize either). Since the observed depression was 9.9℃ and the calculated was 9.8℃, the van't Hoff factor is their quotient, or approximately 1.01.

Explanation:

To solve this problem, we need to understand that the van't Hoff factor (i) is a measure of the extent of ionization in solution. It can be calculated using the formula i = ΔTf observed / ΔTf calculated, where ΔTf observed is the observed freezing point depression and ΔTf calculated is the theoretical freezing point depression if no ionization occurs.

First, we calculate the theoretical freezing point depression for ammonium chloride. We know that this is given by the benzamide that reduces the freezing point of the same amount of liquid X by 2.7℃. Therefore we assume the van't Hoff factor of benzamide is 1 (since it does not ionize) and we get the cryoscopic constant (Kf) of X from ΔTf = Kf * m * i. Substituting into the formula and rearranging gives Kf = ΔTf / (m * i) = 2.7 ℃/(70.4 g/850 g) = 2.7 ℃/0.082824 = 32.6 ℃ kg/mol.

We then use this Kf to calculate the ΔTf calculated for ammonium chloride: ΔTf calculated = Kf * m * i (where we again assume i=1) = 32.6 ℃ kg/mol * (70.4 g/850 g) = 9.8 ℃. Finally we can calculate the van't Hoff factor for ammonium chloride using the original formula: i = ΔTf observed / ΔTf calculated = 9.9 ℃ / 9.8 ℃ = 1.01.

Learn more about Van't Hoff Factor here:

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The solubility of KClO3(s) in water increases as the(1) temperature of the solution increases
(2) temperature of the solution decreases
(3) pressure on the solution increases
(4) pressure on the solution decreases

Answers

Answer: option (1) solubility of the solution increases.

Justification:

The solubility of substances in a given solvent is temperature dependent.

The most common behavior of the solubility of salts in water is that the solubiilty increases as the temperature increase.

To predict with certainty the solubility at different temperatures you need the product solubility constants (Kps), which is a constant of equlibrium of the dissolution of a ionic compound slightly soluble in water, or a chart (usually experimental chart) showing the solubilities at different temperatures.

KClO₃ is a highly soluble in water, so you do not work with Kps.

You need the solubility chart or just assume that it has the normal behavior of the most common salts. You might know from ordinary experience that you can dissolve more sodium chloride (table salt) in water when the water is hot. That is the same with KClO₃.

The solubility chart of KlO₃ is almost a straight line (slightly curved upward), with positive slope (ascending from left to right) meaning that the higher the temperature the more the amount of salt that can be dissolved.

Answer: Option (1) is the correct answer.

Explanation:

Solubility of a solute gets affected by change in temperature. That is, when we increase the temperature then more and more solute particles will dissolve into the solvent or solution.

Therefore, solubility of KClO3(s) in water increases as the temperature of the solution increases because on increasing the temperature it will completely dissociate into the solution.

Which process represents a chemical change?(1) melting of ice(2) corrosion of copper(3) evaporation of water(4) crystallization of sugar

Answers

Answer:

Corrosion of Copper is a chemical change.

Explanation:

Copper like Iron when come in contact with moisture and oxygen oxidized and corrodes according to following equation,

4 Cu + O₂ → 2 Cu₂O

This corrosion results in lost of conductivity, strength and luster of copper. As in this reaction two substances i.e Cu and O₂ are reacting to produce a completely new substance i.e. Cu₂O hence, it is declared as chemical change.

The process which represents a chemical change is (2) corrosion of copper.

FURTHER EXPLANATION

Matter may undergo two types of changes: physical or chemical change.

Physical change involves changes in appearance, size, and other physical properties of a substance. There is no change in the composition or identity of the substance. Examples of physical changes are changes of state and change in size.

Chemical changes are changes wherein the composition or identity of the substance is altered. The properties of the substance changes. This involves formation of a new substance due to the rearrangement of atoms. Examples of chemical change are burning and rotting.

Melting of Ice is a physical change. It is only a state change from solid to liquid.
Corrosion of copper is a chemical change. A new substance forms when copper is corroded and there is a change in the property of the substance. Copper is a conductor but copper oxide is not.
Evaporation of water is a physical change. It is a state change from liquid to vapor.
Crystallization of sugar is a physical change. The composition of sugar remains the same and no new chemical bonds are formed.