Two rectangles are similar. One has a length of 14 cm and a width of 9 cm, and the other has a width of 3 cm. Find the length of the second rectangle. Round to the nearest tenth if necessary.1.9 cm
4.7 cm
5.4 cm
3.5 cm

Answers

Answer 1
Answer: 9/3 is 3
so then its proportionate to 14/3 which would be 4.7
Answer is 4.7
Answer 2
Answer:

Answer:

B 4.7 cm umm it needs to be little long ;-;


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Find the product -2x a(-4x b - 2x 3 + 5x)

Answers

-2ax(-4bx - 2x³ + 5x)
-2ax(-4bx) - 2ax(-2x³) - 2ax(5x)
8abx² + 4ax⁴ - 10ax²

Given: ABCD is a parallelogram.Prove: ∠A and ∠D are supplementary.

Parallelogram A B C D is shown.

By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are
angles. Because AB and DC are
, the same-side interior angles must be
by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.

Answers

Answer:

By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are  

✔ same-side interior

angles.  Because AB and DC are  

✔ parallel

, the same-side interior angles must be  

✔ supplementary

by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.

Step-by-step explanation:

Answer:

The answer above is correct!

The correct options are:

First box: option D. same-side interior

Second box: option C. parallel

Third box: option D. supplementary

Step-by-step explanation:

Hope this helped - just got it right on edge!

Brainliest would be greatly appreciated :)

The product of two integers is 50. one integer is twice the other. find the integers.

Answers

(1) -5*(-10)=50
(2) 5*10=50
use what they are telling. 

a*b=50 (one integer times the other give you a product of 50. we're randomly calling these integers "a" and "b")

2a=b (one integer is twice the amount of the other. we're randomly selecting "b" to be twice the amount of "a")

plug in what we know 

a*(2a)=50 (we replaced "b" with "2a" because we know from the info they gave us that b=2a)

now solve for "a"

a*2a=50
2a²=50
a²=50/2
a²=25
√a²=√25
a=5

which because 2a=b we know that b=10 

The larger of two numbers is 1 more than twice the smaller. The sum of the numbers is 20 less than three times the larger. Find the numbers.

I NEED help please. I'm getting extremely frustrated!!

Answers

Let x be the larger number; Let y be the smaller number.
EQUATIONS:
x-2y=1
x+y+20=3x
---------
Rewrite as
x-2y=1
2x-y=20
==========

Multiply the 1st equation by 2 to get:
2x-4y=2
Subtract this result from the 1st equation to get:
3y=18
y=6
Substitute that into the 1st equation to get:
x-2*6=1
x=13
-------
Solution: x=13; y=6

Answer:

13 and 6

Step-by-step explanation:

Let x = larger number

Let y = smaller number

 

The larger of two numbers is:  x =

one more than twice the smaller: 2y + 1

x = 2y + 1    {equation 1}

 

The sum of the numbers is:  x + y =

20 less than three times the larger: 3x - 20

x + y = 3x - 20

This can be simplified.  Subtract 3x from both sides.

x - 3x + y = -20

-2x + y = -20     {equation 2}

 

Since we already know from equation 1 that x=2y+1, substitute that into equation 2

and solve for y:

 

-2(2y+1) + y = -20

-4y - 2 + y = -20

-3y - 2 = -20

-3y = -18

y = -18/(-3)

y = 6      

 

x = 2y+1 = 2(6)+1 = 12 + 1 = 13

 

Your numbers are 13 and 6

John threw a surprise birthday party for his friend. Food, drinks, and a DJ cost $480 for a group of 32 people. Write and solve and equation to find the cost c per person.

Answers

The required cost per person at the party is given as $15.

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
John threw a surprise birthday party for his friend.
Let the cost per peroson be c,
According to the question,
32c = 480
c = 480 / 32
c = 15

Thus, the required cost per person at the party is given as $15.

Learn more about simplification here:

brainly.com/question/12501526

#SPJ2

First, you have to do 480/32. (divide) That gives you the cost of $15 per person.

What is the highest common factor of 12 and 49?

Answers

12|2\n.\ 6|2\n.\ 3|3\n.\ 1|\n==========\n49|7\n.\ 7|7\n.\ 1|\n==========\n\nHCF(12;\ 49)=1
Factors of 12 . . . . . 1, 2, 3, 4, 6, 12

Factors of 49 . . . . . 1, 7, 49

Common factors . . . 1

Highest common factor . . . 1