CHEMISTRY HIGH SCHOOL

Which was a testable idea that J.J. Thomson developed through his experiments?Atoms are the most important substances in the universe.
It is impossible to divide an atom into smaller parts.
There are electrically neutral particles inside atoms.
Atoms contain small, negatively charged particles.

Answers

Answer 1
Answer: Atoms contains small, negatively charged particles. His experiment showed that an atom contains negatively charged particles which was later known as electrons. This was confirmed by the Cathode Ray Experiment he conducted. 
Answer 2
Answer:

Answer: The correct statement is atoms contain small, negatively charged particles.

Explanation:

J.J.Thomson was a scientist which discovered electrons that are present in an atom.

He did an experiment and gave a model for this. The experiment conducted by him was Cathode Ray experiment and the model given by him was Plum pudding model.

From cathode ray, he showed that the cathode ray was composed of a negatively charged particles and named it as electrons. From plum pudding experiment, he said that the electrons are embedded in the atom. These particles carry negative charge and are very small as compared to the atom.

Hence, the correct statement is atoms contain small, negatively charged particles.

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Which of the following is NOT a type of carbohydrate molecule? Choose one: A. A disaccharide B. A glucose molecule C. A triglyceride D. A polysaccharide

Which of the following is a heterogeneous mixture?A. Oil and Vinegar
B. Air
C. Milk
D. Vinegar in water

Answers

Answer:

B

Explanation:

b/c air is not seen by eye

What determines the strength of a dipole-dipole force?A. The more symmetrical the molecule, the stronger the force.
B. The more hydrogen in the molecule, the stronger the force.
C. The more polar the molecules, the stronger the force.
D. The larger the atomic radius, the stronger the force.

Answers

The more polar the molecules, the stronger the force. Hence, option C is correct.

What is dipole-dipole force?

Dipole-Dipole forces are the interaction between molecules of the permanent dipole. It occurs between the partially charged positive molecules and partially charged negative molecules.

Polar molecules align themselves so that the δ– end of one molecule is near the δ+ ends of other molecules.

The molecules are thus attracted to each other. Dipole-dipole forces exist between polar molecules.

The greater the polarity, the stronger the dipole-dipole forces.

Hence, option C is correct.

Learn more about dipole-dipole force here:

brainly.com/question/14195217

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The answer is C: the more polar the molecules, the stronger the force. Hope this helps!

What type of bond is formed when an atom of potassium transfers an electron to a bromine atom?

Answers

A Polar Covalent Bond is created when the shared electrons between atoms are not equally shared. This occurs when one atom has a higher electronegativity than the atom it is sharing with .

All of the following can be used to define a base except__. A. a hydronium ion donor in a reaction B. a substance that increases the concentration of hydroxide ions C. an electron pair donor in a reaction D. a substance that is a hydrogen ion acceptor in a reaction

Answers

All of the following can be used to define a base except__.

Answer: Out of all the options presented above the one that cannot be used to define a base is answer choice A) a hydronium ion donor in a reaction. As we already know a base is a compound that is a proton (H¹⁺) acceptor.

I hope it helps, Regards.

The volume of a gas decreases from 15.7 m3 to 11.2 m3 while the pressure changes from 1.12 atm to 1.67 atm. If the initial temperature is 245 K, what is the final temperature of the gas

Answers

The final temperature of the gas is 260.01 K.

 The final temperature can be calculated by using the equation as follows:-

(P_(1)V_(1) )/(T_(1)) =(P_(2)V_(2) )/(T_(2))........(1)

Here, P_1 and P_2  is the pressure of this gas before and after the changes.

V_1  and V_2 is volume of this gas before and after the changes.

T_1 and T_2 is the temperature (in degrees Kelvins) of this gas before and after the changes.

Given values:-

P_1=1.12\ atm, P_2=1.67\ atm\n\nV_1=15.7\ m^(3) , V_2=11.2\ m^(3)\n\nT_1=245\ K.T_2=?

Substitute all the values in the equation (1) as follows:-

(1.12\ atm*15.7\ m^(3))/(245\ K ) =(1.67\ atm*11.2\ m^(3))/(T_2 )\nT_2=(1.67\ atm*11.2\ m^(3)*245\K)/(1.12\ atm*15.7\ m^(3) )\n=260.60\ K

Hence, the final temperature of the gas is 260.60 K.

To know more about:-

brainly.com/question/23967621

   

Explanation:

The data is given as follows.

P_(1) = 1.12 atm,              P_(2) = 1.67 atm

V_(1) = 15.7 m^(3),           V_(2) = 11.2 m^(3)

T_(1) = 245 K,                  T_(2) = ?

Therefore, calculate the final temperature using the relation as follows.

    (P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))

    (1.12 atm * 15.7 m^(3))/(245) = (1.67 atm * 11.2 m^(3))/(T_(2))

 T_(2) = (1.67 atm * 11.2 m^(3) * 245 K)/(1.12 atm * 15.7 m^(3))

                  = (4582.48 K)/(17.584)

                  = 260.605 K

                  = 260.61 K (approx)

Thus, we can conclude that final temperature is 260.61 K.

How many liters of oxygen gas can be produced if 28.7 grams of water decomposes at 294 Kelvin and 0.986 atmospheres? Show all of the work used to solve this problem. . . 2 H2O (l) --->2 H2 (g) + O2 (g)

Answers

2 H₂O (l) → 2 H₂ (g) + O₂ (g) 

Molar mass water = 1.01 x 2 + 16.00 = 18.02 g/mol 

Number of mol water decomposed = 28.7 g H₂O x [1 mol / 18.02g] = 1.59 mol H₂O 

From the balanced equation 2 mol H₂O decomposes to 2 mol H₂ and 1 mol O₂ 

so the mole ratio water : oxygen = 2 : 1 

and number of mol O₂ produced = ½ x 1.59 = 0.796 mol O₂ 


The ideal gas law is PV = nRT 

so V = nRT/P 

P = 0.986 atm 

V = ? 

n = 0.796 

R = 0.0821 L atm K⁻¹ mol⁻¹ 

T = 294K 

V = 0.796 x 0.0821 x 294 / 0.986 

V = 19.5 L 

So 19.5 L O₂ gas are produced

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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