Answer:
-196 kJ
Explanation:
By the Hess' Law, the enthalpy of a global reaction is the sum of the enthalpies of the steps reactions. If the reaction is multiplied by a constant, the value of the enthalpy must be multiplied by the same constant, and if the reaction is inverted, the signal of the enthalpy must be inverted too.
2S(s) + 3O₂(g) → 2SO₃(g) ΔH = -790 kJ
S(s) + O₂(g) → SO₂(g) ΔH = -297 kJ (inverted and multiplied by 2)
2S(s) + 3O₂(g) → 2SO₃(g) ΔH = -790 kJ
2SO₂(g) → 2S(s) + 2O₂(g) ΔH = +594 kJ
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2S(s) + 3O₂(g) + 2SO₂(g) → 2SO₃(g) + 2S(s) + 2O₂(g)
Simplifing the compounds that are in both sides (bolded):
2SO₂(g) + O₂(g) → 2SO₃(g) ΔH = -790 + 594 = -196 kJ
The enthalpy of the reaction where sulfur dioxide is oxidized to sulfur trioxide is -395 kJ.
The calculation of the enthalpy change of the reaction in which sulfur dioxide is oxidized to sulfur trioxide involves Hess's Law, which states that the enthalpy change of a chemical reaction is the same whether it takes place in one step or several steps. This can be solved by comparing the enthalpy changes given in the two reactions presented.
First, consider the reactions given:
2S(s) + 3O₂(g) → 2SO₃(g), ΔH = -790 kJ
S(s) + O₂(g) → SO₂(g), ΔH = -297 kJ
From these reactions, it is seen that the first reaction can be re-written as:
2SO₂(g) + O₂(g) → 2SO₃(g), ΔH = -790 kJ
However, this reaction contains two moles of SO₂ whereas the reaction in question only requires one mole. Thus, the enthalpy change for the reaction becomes: ΔH = -790 KJ / 2 = -395 kJ.
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Answer:
Chemical properties,
Explanation:
Let us understand all the given terms
a) catalyst properties: this is the property of a substance by virtue of which it helps to modulate the rate of reaction, and itself remains unconsumed during the reaction (does not react). Example : enzymes
b) chemical properties: this is the property of a substance by virtue of which it reacts with another substance to give a new product of different structure, bonding, chemical and physical properties.
Example : hydrogen reacts with oxygen to give water.
So here the hydrogen is undergoing reaction with oxygen and this is chemical property of hydrogen.
c) Physical properties: This is the property which is related to the nature of a substance to exit in nature. for example hydrogen is a gas is its physical property not chemical.
d) mineral properties: It is again a kind of physical property.
A. S.
B. N.
C. Sn.
D. Na.
Answer:
Atomic Number of Chlorine. Chlorine is a chemical element with atomic number 17 which means there are 17 protons and 17 electrons in the atomic structure.
Explanation:
a. True
b. False
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(B) A catalyst reduces the ∆H of a reaction and hence the temperature needed to produce products.
(C) A catalyst reduces the activation energy for a reaction and increases the rate of a reaction.
(D) A catalyst increases the equilibrium constant and final product concentrations