Which statement is true about BF3, a nonpolar molecule? It has nonpolar bonds and a symmetrical structure. It has nonpolar bonds and an asymmetrical structure. It has polar bonds and a symmetrical structure. It has polar bonds and an asymmetrical structure. It has ionic bonds and symmetrical structure.

Answers

Answer 1

Answer: I think the correct answer is the first option. It has nonpolar bonds and a symmetrical structure. The structure of a BF3 molecule shows a symmetrical trigonal geometry. The net dipole moment of the molecule is zero therefore it is polar.

Answer 2

Answer:

Answer: It has polar bonds and a symmetrical structure.

Explanation:

Formula used for calculating hybridization

$:{\text{Number of electrons}} =(1)/(2)[V+N-C+A]$

where, V = number of valence electrons present in central atom i.e. boron= 3

N = number of monovalent atoms bonded to central atom=3

C = charge of cation = 0

A = charge of anion = 0

$BF_3$

${\text{Number of electrons}} =(1)/(2)[3+3-0+0]=3$

The number of electrons is 3 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

Thus as there are no lone pair of electrons, there is no distortion and the molecule is symmetrical. The B-F bonds are polar due to electronegativity difference but the polarities cancel due to symmetrical structure.

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If you were asked to describe metals and magnetism you could say. A. non–paired electrons spin in opposite directions in all metals, creating a magnetic field. B. metals are magnets because they have more electrons than non–magnetic materials. C. metals can become magnetic if they have many spinning electrons that create magnetic fields. D. the electrons in some metals pair up to create a magnetic field.

Answers

Answer : Option D) the electrons in some metals pair up to create a magnetic field.

Explanation : Most of the metalsare magnetic in nature including some exceptions. When the unpaired electrons get aligned with the magnetic field they posses magnetism. Also there are some paired electrons in metals which align themselves according to the magnetic field and create magnetism in them.

The correct answer is C; Metals can become magnetic if they have many spinning electrons that create magnetic fields.

Further Explanation;

As long as there are many spinning electrons anything metal will become magnetic. Ferromagnetic is when there are only some certain types of metals that are attracted to magnetic. If you were to make an electromagnet, you would only need to take an insulated wire and wrap it around the metal that has ferromagnetic properties.

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What is the ph of a 0.027 M KOH solution?

Answers

The pH of a 0.027 M KOH solution is 12.4 and since KOH is a strong base it will dissociate completely in the solution

How do we calculate?

KOH is a strong base, so it will dissociate completely in solution to form potassium ions and hydroxide ions. The concentration of hydroxide ions will be equal to the concentration of KOH, which is 0.027 M.

The pH of a solution can be calculated using the following equation:

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in the solution.

The concentration of hydrogen ions in a basic solution is very low, so we can use the approximation that:

pH = 14 - log[OH-]

pH = 14 - log(0.027)

pH = 12.4

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First you calculate the concentration of [OH⁻] in solution :

POH = - log [ OH⁻]

POH = - log [ 0.027 ]

POH = 1.56

PH + POH = 14

PH + 1.56 = 14

PH = 14 - 1.56

PH = 12.44

hope this helps!

Can someone help me find the theoretical value of methane? It is chemistry

Answers

Methane is lighter than air, having a specific gravity of 0.554. It is only slightly soluble in water. It burns readily in air, forming carbon dioxideand water vapour; the flame is pale, slightly luminous, and very hot.The boiling point of methane is −162 °C (−259.6 °F) and the meltingpoint is −182.5 °C (−296.5 °F). Methane in general is very stable, butmixtures of methane and air, with the methane content between 5 and 14percent by volume, are explosive. Explosions of such mixtures have beenfrequent in coal mines and collieries and have been the cause of manymine disasters.

The purpose of an indicator is to A. test and determine the pH values of unknown solutions. B. help acids and bases dissociate when placed in water. C. make a solution more neutral. D. conduct electricity.

Answers

Answer is: A. test and determine the pH values of unknown solutions.

Acid-base indicators are usually weak acids or bases and they are chemical detectors for hydrogen or hydronium cations (pH or pOH values).

Example for acid-base indicator is phenolphthalein (molecular formula C₂₀H₁₄O₄). Phenolphthalein is colorless in acidic solutions and pink in basic solutions.

Another example is methyl orange. It is red colour in acidic solutions and yellow colour in basic solutions.

Answer: The correct answer is option A.

Explanation:

An indicator is a substance which changes color to show any chemical change happening in the reaction. It gives the visible sign of any change.

Hence, main role of indicators from the given options is to determine the pH values of unknown solutions.

pH is the scale which shows the acidity and basicity of the solutions. It is the negative logarithmic value of hydrogen ion concentration of the solution. More the hydrogen ion concentration, less will be the pH and more acidic will be the solution.

$pH=-\log[H^+]$

The scale ranges from 0 to 14.

The value ranging from 0 to 6.9 are acidic solutions.

The value ranging from 7.1 to 14 are basic solutions.

The value having pH = 7 is neutral solution.

Indicator used to determine the pH of the solution is pH-paper which is shown in the image.

Which step would help a student find the molecular formula of a compound from the empirical formula?

Answers

First, you need to be given the gram formula mass of this molecular or related conditions that can calculate this. Then you need the empirical formula and calculate the gram formula mass of empirical formula. Then use them to get the ratio. Finally you can get the molecular formula.

Final answer:

To find the molecular formula from the empirical formula, first calculate the empirical formula mass. Then, divide the molecular or molar mass by the empirical formula mass to find the number of empirical formula units per molecule. Finally, multiply the subscript of each element in the empirical formula by this number to get the molecular formula.

Explanation:

The process of finding the molecular formula from the empirical formula involves a few steps. First, you need to determine the empirical formula of a compound, which is the simplest positive integer ratio of atoms present in a compound. After you have the empirical formula, you can calculate the empirical formula mass by summing up the average atomic masses of all the atoms in the empirical formula.

Next, compare the compound's molecular or molar mass (which you should know or have been given) to the empirical formula mass. This comparison is done by dividing the molecular or molar mass by the empirical formula mass. This will give you the number of empirical formula units, denoted as n, per molecule of the compound.

The final step is to take the empirical formula and multiply the subscript of each element in it by n. This will give you the molecular formula of the compound.

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Knowledge of atomic structure has evolved over time. Thomson discovered that atoms contain electrons, Rutherford discovered that most of the mass of an atom is concentrated in its center, and Bohr discovered that electrons orbit the nucleus. Taken together, what do these discoveries demonstrate?
A. the cumulative nature of science
B. the quantitative nature of science
C.the importance of thorough review of scientific papers
D. the importance of not publishing science until it is final

Answers

I believe the correct response would be A. The cumulative nature of science. How experimental evidence and ideas made by many scientists have accumulated and or built up to have a more understandable and or clear view of a particular scientific topic, and or principle.

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