How many grams of solute are present in 615 ml of 0.630 m kbr?
Answers
molarity of KBr solution is 0.630 M
this means that there there are 0.630 moles of KBr in 1 L solution
then in 615 mL number of KBr moles are - 0.630 mol/L x 0.615 L = 0.387 mol
mass of KBr is - molar mass x number of moles
KBr molar mass is 119 g/mol x 0.387 mol = 46.1 g
mass of KBr is 46.1 g
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How many grams of hydrogen peroxide (H2O2) must be added to 1,500 mL of water to produce a concentration of 1.33 m (molal solution)? (Recall that the density of water is 1.0 gram/mL.)
How do ionic bonds affect the properties of ionic compounds?A) The bonds weakly hold ions together, increasing the melting point.B) The bonds strongly hold ions together, reducing the boiling point.C) The bonds prevent ions from moving throughout the crystal, so a solid ionic compound is a poor conductor.D) The bonds prevent electrons from moving throughout the crystal, so a solid ionic compound is a poor conductor.
I will give brailiest to whoever needs it!
Answers
Answer:
33.21% is the right answer.
Explanation:
0.04720 L * 0.02240 mol / L = 1.0573*10-3
mol Fe+2 = 1.0573* 10-3 mol = 5.2864*10-3
mass of Fe= 5.2864 * 10-3 = 0.29522g
% of Fe in sample = 0.29522 g Fe / 0.8890 g of sample * 100 = 33.21%
Final answer:
The number of moles of MnO4– added to the solution is 0.00106 mol. The moles of Fe2+ in the sample is 0.00530 mol. The grams of iron in the sample is 0.296 g and the percentage of iron in the sample is 33.33%.
Explanation:
The titration reaction between Fe2+ and MnO4– in acid solution is as follows: 5Fe2+ + MnO4– + 8H+ → 5Fe3+ + Mn2+ + 4H2O. Firstly, we can calculate the number of moles of MnO4– added to the solution using the formula volume X molarity. That is 0.0472 L X 0.02240 M = 0.00106 mol MnO4–. According to the balanced redox reaction, one mole of MnO4– reacts with five moles of Fe2+. Therefore, the moles of Fe2+ in the sample is 0.00106 mol MnO4– X 5 = 0.00530 mol Fe2+.
Next, we calculate the grams of iron in the sample. The molarmass of iron is approximately 55.85 g/mol, thus the grams of iron in the sample are 0.00530 mol Fe2+ X 55.85 g/mol = 0.296 g Fe2+. Finally, we find the percentage of iron in the sample by mass = (mass of iron in the sample / total mass of the sample) X 100%. Therefore, the percentage is (0.296 g / 0.8890 g) X 100% = 33.33%.
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Answers
The safest method for diluting concentrated sulfuric acid with water is to add acid to water. This way, when spill occurs, the acid is already diluted and less harmful than adding water to acid.
(2) at the cathode in an electrolytic cell and at the anode in a voltaic cell
(3) at the anode in both an electrolytic cell and a voltaic cell
(4) at the anode in an electrolytic cell and at the cathode in a voltaic cell
Answers
Negative ion arrives at the anode, attracted by electrostatic forces, where they lose electrons. Loss of electrons is defined as oxidation.
The reverse process occur at the negative electrode, where positive ions pick up electrons. They are reduced.
Answer : The correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.
Explanation :
As we know that there are two types of cell which are, electrolytic cell and electrochemical cell or galvanic cell.
Electrolytic cell : It is defined as the cell in which the chemical reaction occurs by passing of the current from external source.
In this electrolytic cell, the oxidation occurs at anode which is a positive electrode and reduction occurs at cathode which is a negative electrode.
Electrochemical cell : It is defined as the cell in which the chemical reaction occurs with the production of electric potential difference between the two electrodes. It is also known as voltaic cell.
In this cell, the oxidation occurs at anode which is a negative electrode and reduction occurs at cathode which is a positive electrode.
From this we conclude that, the oxidation occurs at the anode in both an electrolytic cell and a voltaic cell.
Hence, the correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.
Answers
For 2*32=64 grams of oxygen, you can burn 2*16=32 grams of methane (that is, half).
So, our answer is .5g.
Other intermediate calculations are mollecular masses:
Answer:
0.28 g of
Explanation:
You need a balanced equation first. ⇒
You need to find the number of moles of oxygen, which is mass divided by the Mr: 1 ÷ 32 = 1/32
Then you find the moles of methane using the mole ration oxygen to methane 2:1. 1/32 ÷ 2 = 1/64
Then you find the mass by multiplying the Mr with the number of moles:
1/64 × 18 = 0.28125 g = 0.28 g
B. solvent
C. solution
D. mixture
Answers
Answer is: A. solute .
Solvation is the interaction of solvent (in this example water) with molecules or ions (in this example carbon dioxide)) in a solute.
Solvent (usually a liquid, but can also be a solid or a gas) is a substance that dissolves a solute (dissolved in the solvent).
Solvent is always the same state of matter as the solution. In this example, soft drink is a liquid, so water is a solvent.
Solute is what is mixed into the solvent
Answers
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Charles' gas law is used here. Therefore the new volume of the balloon in the hot room is 3.68 L.
What is ideal gas equation?
Ideal gas equation is the mathematical expression that relates pressure volume and temperature. Vanderwaal gas can behave as ideal gas low pressure and high temperature.
Mathematically the relation between Pressure, volume and temperature can be given as
PV=nRT
where,
P = pressure of gas
V= volume of gas
n =number of moles of gas
T =temperature of gas
R = Gas constant = 0.0821 L.atm/K.mol
Combining Boyle's and Charles' gas law
V₁/T₁ = V₂/T₂
3.50 L ÷298 K = V₂÷313 K
V₂ = 3.68 L
Therefore the new volume of the balloon in the hot room is 3.68 L.
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yes, according to charles law, this would be equal to 3.68 L