Which correctly summarizes the trend in electron affinity? it tends to be very high for group 2
it tends to be more negative across a period
it tends to remain the same across periods
it tends to be more negative down a group

Answers

Answer 1
Answer:

The answer is it tends to be more negative down a group. This is because as you go down the periodic table, the elements have more electron shells in their atoms. This makes the outermost shells less attracted to the nucleus due to their greater distances from the nucleus. Therefore, these shells are less likely to attract electrons (hence lower electron affinity) and are even more likely to lose electrons from their outer electron orbits.

Answer 2
Answer:

Answer:

it tends to be more negative across a period

Explanation:

We have to remember that the periodic table is arranged accordingly to the number of electrons that the elements have in their outer valance shell, so the closer you are to the right of the periodic table the closer you get to the elements taht have the most electrons in their outer valance shells, this means that they have a greater negative electron affinity, which means that the elements on the right are more willing to gain an electron.


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An ice cube is dropped into boiling water. How will heat flow between the water and the ice cube?

Answers

On a microscopic (molecular) level, heat flows from the ice to the boiling water
at a minuscule rate, and from the water to the ice at a humongous rate.

Heat transfers from hot body to cold body. So when ice is dropped in water , the water at higher temperature will lose heat energy and is gained by the ice at less temperature. When the Net heat lost equals to Net heat gained i.e.,When both the bodies attain themal equilibrium, the flow of heat energy stops and both attain equal temperatures.

A gas Syringe contains 42.3 milliliters of a gas at 98.15°C. Determine the volume that the gas will occupy if the temperature is decreased to -18.50°C.

Answers

The volume that the gas will occupy is "29.00 mL".

According to the question,

Volume,

  • V_1 = 42.3 \ mL
  • V_2 = ?

Temperature,

  • T_1 = 98.15^(\circ) C

             = 371.15 \ K

  • T_2 = -18.50^(\circ) C

             = 254.5 \ K

As we know the relation,

(V_1)/(T_1) = (V_2)/(T_2)

or,

V_2 = (V_1* T_2)/(T_1)

By substituting the values, we get

→      = (41.3* 254.5)/(371.15)

→      = (10765.35)/(371.15)

→      = 29.00 \ mL

Thus the above answer is right.  

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V₁ = 42.3 mL

T₁ ( K ) = 98.15ºC + 273 = 371.15 K

V₂ = ?

T₂ ( K) = -18.50ºC + 273 = 254.5 K

V₁ / T₁  = V₂ / T₂

42.3 / 371.15 =  V₂ / 254.5

371.15 x V₂ = 42.3 x  254.5

371.15 x V₂ = 10765.35

V₂ = 10765.35 / 371.15

V₂ = 29.00 mL

hope this helps!

Of the following choices, the best conductor is _____. iron copper steel rubber

Answers

Metals are usually good conductors because they have abundant free negative charges, or electrons.

The answer is Copper

Copper because not many impurities


2. The energy of a photon that has a wavelength of 12.3 nm is _______ J.A) 2.72 x 10^-50
B) 1.62 x 10^-17
C) 4.42 x 10^-23
D) 1.99 x 10^-25
E) 1.51 x 10^-17

Answers

I think it is e sorry if I’m wrong

Determine how many moles of O2 are required to react completely with 6.7 moles C6H14.

Answers

I think *extra stress on the word think lol* it's 6.7 moles of O₂.
unless you have the full formula, giving me the amount of moles in C₆H₁₄ and O₂.

hopefully this helps. :/

A plate moves south at a rate of 2 cm/year. How many meters south from its original location will the plate be in 4,000 years? 8,000 meters south 4,000 meters south 200 meters south 80 meters south

Answers

The distance (in meters south) the plate will be given that the plate is moving at a rate of 2 cm/year is 80 meters south (last option)

How do i determine the distance?

Speed is defined as distance travelled per unit time. This is mathematically written as

Speed = Distance travelled / time

If we make distance the subject, we have

Distance travelled = Speed × time

The following data were obtained from the question:

  • Speed of plate = 2 cm/year = 2 / 100 = 0.02 m/year
  • Time = 4000 years
  • Distance travelled =?

Distance travelled = Speed × time

Distance travelled = 0.02 × 4000

Distance travelled = 80 meters south

Thus, we can conclude that the distance travelled is 80 meters south (last option)

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the plate will be 80 meters south from its original location in 4,000 years. The correct answer is (d) 80 meters south.

The plate moves south at a rate of 2 cm/year. To find out how many meters south it will be in 4,000 years, we need to convert the years to centimeters and then meters.

In 4,000 years, the plate will have moved: 2 cm/year x 4,000 years = 8,000 cm.

Now, to convert 8,000 cm to meters, we need to divide by 100 (since there are 100 centimeters in a meter):

8,000 cm / 100 = 80 meters.

So, the plate will be 80 meters south from its original location in 4,000 years. The correct answer is (d) 80 meters south.

To know more about south

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Complete question is:

A plate moves south at a rate of 2 cm/year. How many meters south from its original location will the plate be in 4,000 years?

a. 8,000 meters south

b. 4,000 meters south

c. 200 meters south

d. 80 meters south