Pentagon PQRST and its reflection, pentagon P'Q'R'S'T', are shown in the coordinate plane below:Pentagon PQRST and pentagon P prime Q prime R prime S prime T prime on the coordinate plane with ordered pairs at P negative 4, 6, at Q negative 7, 4, at R negative 6, 1, at S negative 2, 1, at T negative 1, 4, at P prime 4, 6, at Q prime 7, 4, at R prime 6, 1, at S prime 2, 1, at T prime 1, 4.
What is the line of reflection between pentagons PQRST and P'Q'R'S'T'?
x = 0
y = x
y = 0
x = 1
Answers
Yes, the answer is A. x=0. Another way to say "reflect across the y-axis" is to say "reflect across the line x=0" since the line created by graphing x=0 is the same as the y-axis. An image that is a reflection across the y-axis, or across the line x=0, will have opposite x-coordinates from the pre-image but identical y-coordinates. In other words, the x value points just changed signs from negative to positive values since it went through the rule (x, y) → (−x, y).
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(x - 2)² + (y - 4)² = 25
(x - 2)² + (y - 4)² = 100
Answers
The center of the circle is the midpoint of the diameter.
The 'x' coordinate of the midpoint is (1/2) (6 - 2) = 2
The 'y' coordinate of the midpoint is (1/2) (7 + 1) = 4
The center of the circle is the point (2, 4) .
The length of the diameter of the circle is the distance
between the endpoints of the diameter.
The distance between (-2, 1) and (6, 7) is
√ (8² + 6²)
= √ (64 + 36)
= √ 100 = 10 .
The radius of the circle is 1/2 of 10 = 5 .
Now, the equation of any circle is
(x - [x of the center])² + (y - [y of the center])² = (radius)² .
and we have all the numbers now.
(x - 2)² + (y - 4)² = (5)² .
I'm very happy to see that this equation is actually
one of the choices ! I'll bet you are too.
Answer:
Step-by-step explanation:
In the picture you can see that has endpoints of (-2, 1) and (6, 7)
Answers
One would be in a fraction form where "3 to 10" can be written as "3/10", or using a colon between the two numbers, where it would be written as "3:10". It is necessary to understand that these forms all mean the same, even if they look really different.
Answers
Answer:
130
Step-by-step explanation:
Answers
= x² ( x² - 3 x - x + 3 ) =
= x² ( x ( x - 3 ) - ( x - 3 ) ) =
= x² ( x - 3 ) ( x - 1 ) = 0
x² = 0 ⇒ x = 0
x - 3 = 0 ⇒ x = 3
x - 1 = 0 ⇒ x = 1
The zeroes of the function are: x = 0, x = 1 and x = 3.
Answer:
B ) The number 0 is a zero of multiplicity 2; the numbers 1 and 3 are zeroes of the multiplicity 1.
• Never
•Sometimes
Answers
Never, B is the middle colinear point so it cant measure longer than AC which is the full line segment.
Answers
x^2-27+6x=0
the use quadratic formula