When baking soda (sodium bicarbonate or sodium hydrogen carbonate, NaHCO3) is heated, it releases carbon dioxide gas, which is responsible for the rising of cookies, doughnuts, and bread. a) Write a balanced equation for the decomposition of the compound (one of the products is Na2CO3).
b) Calculate the mass of NaHCO3 required to produce 20.5 g of CO2.

Answers

Answer 1
Answer:

Answer:

a. NaHCO₃ + HCl → NaCl + H₂O + CO₂

b. 39.14 g is the mass of NaHCO₃ required to produce 20.5 moles of CO₂

Explanation:

A possible reaction for NaHCO₃ to make dioxide is this one, when it reacts with hydrochloric to produce the mentioned gas.

NaHCO₃ + HCl → NaCl + H₂O + CO₂

Ratio in this reaction is 1:1

So 1 mol of baking soda, produce 1 mol of CO₂

Let's calculate the moles

20.5 g CO₂ / 44 g/m = 0.466 moles

This moles of gas came from the same moles of salt.

Molar mass baking soda = 84 g/m

Molar mass . moles = mass

84 g/m .  0.466 moles = 39.14 g


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Please match word and definition < electrons and electric current move easily 1. electric current < Prevents electrons from moving 2. insulator flow of an electrical charge in a circuit 3. electric circuit 4. conductor provides a path for electrons to flow​

Answers

Due to property of conduction, conductor allows electrons and electric current to move easily,insulators prevent electric current from moving, electric current is the  flow of an electrical charge in a circuit and electric circuit provides a path for electrons to flow​.

What is conduction?

Conduction is defined as a process as a means of which heat is transferred from the hotter end of the body to it's cooler end.Heat flows spontaneously from a body which is hot to a body which is cold.

In the process of conduction,heat flow is within the body and through itself.In solids the conduction of heat is due to the vibrations and collisions of molecules while in liquids and gases it is due to the random motion of the molecules .

When conduction takes place, heat is usually transferred from one molecule to another as they are in direct contact with each other.There are 2 types of conduction:1) steady state conduction 2) transient conduction.According to the type of energy conduction is of three types:

1) heat conduction

2) electrical conduction

3)sound conduction

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Answer:

1st box:4

2nd box:2

3rd box:3

4th box:1

Explanation:

I am not 100% sure on this, but i am pretty confident that this is the answer! BUT If this is somehow wrong, please tell me so i can comment a better answer! :)

A water wave has a frequency of 10 Hz and a wavelength of 150 m. What is the wave speed? *Equation to use: wave speed (m/s) = frequency (Hz) x wavelength (m)*

Answers

Answer:

Speed of wave = 1500 m/s

Explanation:

Given data:

Frequency of wave = 10 Hz

Wavelength of wave = 150 m

Speed of wave = ?

Solution:

Formula:

Speed of wave = Frequency × Wavelength

Now we will put the values in formula.

Speed of wave = 10 Hz × 150 m

Speed of wave = 1500 m/s

         Hz = s⁻¹

What is the name of the structures that help move substances across a tract surface?

Answers

Answer:

cilia and flagella

Explanation:

In prokaryotic species , cilia are present , and in eukaryotic species , flagella is present .

Cilia and flagella both have same function , i.e. , to enable the movement of the cell , along with the movement of some substance and direct the flow of these substance along the tracts.

Cilia and flagella are composed of basal bodies.

Hence , from the given statement of the question,

The correct term is cilia and flagella .

Final answer:

Cilia are the structures that help move substances across the surface of a tract. They are primarily found in certain types of cells such as those in the respiratory tract and the oviducts.

Explanation:

The structures that assist in moving substances across a tract surface are primarily called cilia. In biology, cilia are tiny hair-like structures that line certain types of cells, especially those in the respiratory tract and the oviducts. They work much like oars on a boat, moving in coordinated waves to propel substances (like mucus or egg cells) along the surface of the tract they occupy. They are responsible in movement of substances across tract.

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The two reactions above, show routes for conversion of an alkene into an oxirane. If the starting alkene is cis-3-hexene the configurations of the oxirane products, A and B are Product A: _______ Product B: _______ Will either of these two oxirane products rotate the plane of polarization of plane polarized light

Answers

Answer:

Product A and B : (2R,3S)-2,3-diethyloxirane and (2S,3R)-2,3-diethyloxirane.

Explanation:

A double bond is converted to an oxirane through oxidation by peracids e.g. mCPBA (meta-chloroperoxybenzoic acid).

Epoxidation can occur at both face of double bond result in formation of two stereoisomers.

Product A and B : (2R,3S)-2,3-diethyloxirane and (2S,3R)-2,3-diethyloxirane

Both A and B contain plane of symmetry. Hence, both the products are achiral. So, they do not rotate the plane of polarization of plane polarized light.

Could someone pls help me :)

Answers

liquid 1 and 2 have the same color and mass so the answer would be liquid 1 and 2

Explanation:

hope this is helpful

The rate constant doubles when the temperature is increased from 45.0 C to 73.0 C. What is the activation energy for this reaction? (R=8.314 J/Kmol)?

Answers

Answer:

Ea =22542.6

Explanation:

The rate constant k is affected by the temperature and this dependence may be represented by the Arrhenius equation:

k=Ae^{-(E_a)/(RT) }

where the pre-exponential factor A is assumed to be independent of temperature, R is the gas constant, and T the temperature in K. Taking the natural logarithm of this equation gives:

ln  k = ln A - Ea/(RT)

or

ln  k = -Ea/(RT) + constant

or

ln  k = -(Ea/R)(1/T) + constant

These equations indicate that the plot of ln k vs. 1/T is a straight line, with a slope of -Ea/R. These equations provide the basis for the experimental determination of Ea.

now applying the above equation in the problem

we can write that

ln(k_2)/(k_1) = (E_a)/(R)[(1)/(T_1)-(1)/(T_2)  ]

solve for Ea:

Ea = R[Ln(k2/k1)] / [(1/T1) - (1/T2)]

but k_2 = 2 k_1, hence:

Ea = (8.314 J/moleK)[ln(2)] / [(1/273+45) - (1/273+73)]

Ea =22542.6

Answer:

The activation energy for this reaction is 22.6 kJ/ mol

Explanation:

Step 1: Data given

Rate constant doubles when Temperature goes from 45.0 °C to 73.0 °C

R = 8.314 J/K*mol

Step 2: Calculate the activation energy

Log (k2/k1) = Ea / 2.303R *((1/T1) - (1/T2))

⇒ with k1 = initial rate constant

⇒ with k2 = rate constant after doubled = 2k1

⇒ T1 = initial temperature = 45.0 °C = 318 Kelvin

⇒ T2 = Final temperature = 73.0 °C = 346 Kelvin

log (2) = Ea / (2.303*8.314) *((1/318) - (1/346))

log(2) = Ea / (2.303*8.314) * 0.00025448

Ea = 22649 J/mol = 22.6 kJ/mol

The activation energy for this reaction is 22.6 kJ/ mol