Answer:
Explanation:
y = (0.2 cm) Sin(2x - 3 t + π/16)
Put x = 4 m, t = 10 s
y = (0.2 cm) Sin (2 x 4 - 3 x 10 + π/16)
y = (0.2 cm) Sin (8 - 30 + π/16)
y = (0.2 cm) Sin (π/16 - 22)
y = (0.2 cm) Sin(-21.80375)
y = (0.2 cm) x (- 0.1863)
y = - 0.37 cm
The given wave function represents a transverse wave on a string. Substituting the given values into the wave function yields a height of -0.037 cm. The correct option is a. -0.037 cm.
The given wave function y(x,t) represents a transverse wave on a string. To find the height of the string with respect to the equilibrium position at a position x = 4.00m and a time t = 10.00s, substitute these values into the wave function. y(4.00m, 10.00s) = (0.20 cm) sin[(2.00 m-1)(4.00m) - (3.00 s-1)(10.00s) + π/16].
Calculating this expression gives the height of the string as -0.037 cm. Therefore, the correct option is a. -0.037 cm.
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The displacement vector, d, can be recomposed as follows: d = (Dx, Dy) and the magnitude of the displacement vector is approximately 11.24 meters.
To recompose the displacement vector, d, using the given X and Y components, you can use vector addition. The X and Y components represent the horizontal and vertical displacements, respectively.
Given:
Dx = 6.68 m (left)
Dy = 9.04 m (down)
The displacement vector, d, can be recomposed as follows:
d = (Dx, Dy)
So, the displacement vector is (6.68 m left, 9.04 m down). This means that the object moved 6.68 meters to the left (in the negative X direction) and 9.04 meters downward (in the negative Y direction) from its starting point.
The magnitude of the displacement can be found using the Pythagorean theorem:
|d| = √((Dx)^2 + (Dy)^2)
|d| = √((6.68 m)^2 + (9.04 m)^2)
|d| ≈ √(44.49 m^2 + 81.72 m^2)
|d| ≈ √(126.21 m^2)
|d| ≈ 11.24 meters
So, the magnitude of the displacement vector is approximately 11.24 meters.
Learn more about displacement vector here:
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B. hydrogen nucleus
C. high energy electron
D. radium nucleus
An alpha particle is identical to a helium nucleus as it consists of two protons and two neutrons, which match the composition of a helium atom’s nucleus.
An alpha particle is identical to a helium nucleus. This is because an alpha particle contains two protons and two neutrons, which is the same as the nucleus of a helium atom. The alpha particle does not have electrons that surround the nucleus in a helium atom.
Options B, C, and D are not correct. A hydrogen nucleus (B) has only one proton and no neutrons, a high energy electron (C) is a subatomic particle with charge -1 and not part of a helium nucleus, and a radium nucleus (D) contains many more protons and neutrons than a helium nucleus or an alpha particle.
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Answer:
True
Explanation:
i took the quiz
A) atoms break up in extreme heat
B) atoms are rearranged in materials
C) atoms combine in water to form solids
D) atoms of magma cool after a volcanic eruption